SWIFT中用Switch case 类类型

有时觉得SWIFT的语法真的强大而又变态，不说了，直接上代码瞅瞅：

首先先定义一个交通工具的父类

class Vehicle{

var wheels:Int!

var speed:Double!

init(wheels:Int,speed:Double){

self.speed = speed

self.wheels = wheels

}

func run(){

println("The \(self.wheels) wheels is running as \(self.speed) speed")

}

deinit{//类似于其它编程语言的析构函数，退出时释放对象

self.wheels = nil

self.speed = nil

}

}

创建一个自行车类

class Bike : Vehicle{

init(){

super.init(wheels: 2, speed: 10)

}

}

创建一个小车类及一个加油的方法

class Car : Vehicle{

init(){

super.init(wheels: 4, speed: 100.5)

}

func addOil(){

println("The Car is adding oil")

}

}

创建一个货车类及添加货物的方法

class Truck : Vehicle{

init(){

super.init(wheels: 4, speed:80.5)

}

func addCargo(){

println("The Car is adding cargo")

}

}

var myvehicle:Vehicle = Car()

判断如果是小车类型的

if (myvehicle is Car){

println("This is a car")

}

switch myvehicle{

case let bike as Bike: //此时，如果myvehicle是Bike对象那边将myvehicle赋值给bike变量。下面的代码也类似

bike.run()

case let car as Car where car.speed == 100.5: //如果是Car并且速度是100.5，这语法真的很变态

car.addOil() //调用自有方法

car.run()

case let truck as Truck:

truck.addCargo()//调用自有方法

default:

println("unknow")

}