ZOJ 1122 Clock(模拟)

Clock

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Time Limit: 2 Seconds      Memory Limit: 65536 KB

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You are given a standard 12-hour clock with analog display, an hour hand and a minute hand. How many times does the minute hand pass the hour hand in a given time interval?

Sample Input

12 50  1  2
 3  8  3 20
 2 45 11  0
11  0  3 20
 1  2 12 50
 3 20  3  8

Sample Output

Program 3 by team X
Initial time  Final time  Passes
       12:50       01:02       0
       03:08       03:20       1
       02:45       11:00       8
       11:00       03:20       4
       01:02       12:50      11
       03:20       03:08      10
End of program 3 by team X

题目的下边还有一大段，当时出在HUST上，根本分不清哪输出格式是哪个，谁知道最前边最后边那句话也需要。当时有一次试了一下加上这两句，其他地方哪里又出错了。看了题解，直接把最后一次提交的错误代码， 加上这两句输出，直接A了，坑

判断分针和时针相遇的次数

代码如下：

 # include <iostream>
 # include<cstdio>
 # include<cstring>
 using namespace std;

 int main()
 {
     int a,b,c,d,ans;
     double tmp1,tmp2,tmp3,tmp4;
     printf("Program 3 by team X\n");
     printf("Initial time  Final time  Passes\n");
     while(scanf("%d%d%d%d",&a,&b,&c,&d)!= EOF)
     {
         printf("       ");
         printf("%02d:%02d",a,b);
         printf("       ");
         printf("%02d:%02d",c,d);
         printf("      ");
         if(a==)
             a=;
         if(c==)
             c=;
         tmp2 = b/60.0;
         tmp1 = a/12.0 + tmp2/12.0;
         tmp4 = d/60.0;
         tmp3 = c/12.0 + tmp4/12.0;
                if(a==c)
         {
             if(d>=b)
             {
                 if(tmp1-tmp2> && tmp4-tmp3>)
                 {
                     ans = ;
                 }
                 else
                     ans = ;
             }
             else
             {
                 ans = ;
                 if(tmp1 - tmp2 >  )
                     ans++;
                 if(tmp4-tmp3>)
                     ans ++;
             }
         }
         else if(a<c)
         {
             ans = c-a-;
             if(tmp1 - tmp2 >  )
                 ans++;
             if(tmp4 - tmp3 > )
                 ans++;
         }
         else
         {
             ans = -a + c -;
             if(tmp1 - tmp2 > )
                 ans++;
             if(tmp4 - tmp3>)
                 ans++;
         }
         printf("%2d\n",ans);
     }
     printf("End of program 3 by team X\n");
     return ;
 }