Flip Game poj1753
| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 32961 | Accepted: 14407 |
Description
- Choose any one of the 16 pieces.
- Flip the chosen piece and also all adjacent pieces to the left, to the right, to the top, and to the bottom of the chosen piece (if there are any).
Consider the following position as an example:
bwbw
wwww
bbwb
bwwb
Here "b" denotes pieces lying their black side up and "w" denotes pieces lying their white side up. If we choose to flip the 1st piece from the 3rd row (this choice is shown at the picture), then the field will become:
bwbw
bwww
wwwb
wwwb
The goal of the game is to flip either all pieces white side up or all pieces black side up. You are to write a program that will search for the minimum number of rounds needed to achieve this goal.
Input
Output
Sample Input
bwwb
bbwb
bwwb
bwww
Sample Output
4
Source
dfs枚举
#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std; int Map[][],a[]={,,,,-},b[]={,,,-,};
int flg,step; int judge(int Map[][])
{
int i,j;
for(int i=;i<=;i++)
for(j=;j<=;j++)
{
if(Map[i][j]!=Map[][])
return ;
}
return ;
} int flip(int r,int c)
{
for(int i=;i<;i++)
{
if(Map[r+a[i]][c+b[i]]==)
Map[r+a[i]][c+b[i]]=;
else
Map[r+a[i]][c+b[i]]=;
}
} void dfs(int r,int c,int deep)
{
int i,j;
if(deep==step)
{
flg=judge(Map);
return;
}
if(flg== || r>)
{
return;
}
flip(r,c);
if(c<)
dfs(r,c+,deep+);
else
dfs(r+,,deep+);
flip(r,c);
if(c<)
dfs(r,c+,deep);
else
dfs(r+,,deep);
return;
} int main()
{
int i,j;
char k;
memset(Map,,sizeof(Map));
for(i=;i<=;i++)
{
for(j=;j<=;j++)
{
scanf("%c",&k);
if(k=='b')
Map[i][j]=;
}
getchar();
}
for(step=;step<=;step++)
{
dfs(,,);
if(flg)
break;
}
if(flg)
printf("%d\n",step);
else
printf("Impossible\n");
return ;
}
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