hdu 1228 A + B

题目连接

http://acm.hdu.edu.cn/showproblem.php?pid=1228

A + B

Description

读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

Output

对每个测试用例输出1行,即A+B的值.

Sample Input

one + two =
three four + five six =
zero seven + eight nine =
zero + zero =

Sample Output

3

90

96

字符串水题。。

 #include<algorithm>
 #include<iostream>
 #include<cstdlib>
 #include<cstring>
 #include<cstdio>
 #include<string>
 #include<vector>
 #include<map>
 #include<set>
 using std::map;
 using std::cin;
 using std::cout;
 using std::endl;
 using std::vector;
 using std::string;
 #define sz(c) (int)(c).size()
 #define all(c) (c).begin(), (c).end()
 #define iter(c) decltype((c).begin())
 #define cls(arr,val) memset(arr,val,sizeof(arr))
 #define cpresent(c, e) (find(all(c), (e)) != (c).end())
 #define rep(i, n) for (int i = 0; i < (int)(n); i++)
 #define tr(c, i) for (iter(c) i = (c).begin(); i != (c).end(); ++i)
 #define pb(e) push_back(e)
 #define mp(a, b) make_pair(a, b)
 const int Max_N = ;
 typedef unsigned long long ull;
 map<string, int> rec;
 void init() {
     rec["zero"] = ;
     rec["one"] = ;
     rec["two"] = ;
     rec["three"] = ;
     rec["four"] = ;
     rec["five"] = ;
     rec["six"] = ;
     rec["seven"] = ;
     rec["eight"] = ;
     rec["nine"] = ;
 }
 int main() {
 #ifdef LOCAL
     freopen("in.txt", "r", stdin);
     freopen("out.txt", "w+", stdout);
 #endif
     init();
     int a, b, f;
     char str[], buf[];
     while (gets(buf)) {
         a = b = f = ;
         char *p = buf;
         while (true) {
             if (*p == ' ') { p++; continue; }
             sscanf(p, "%s", str);
             if (!strcmp(str, "=")) break;
             if (!f && strcmp(str, "+")) a = a *  + rec[str];
             if (!strcmp(str, "+") || f) {
                 if (!strcmp(str, "+")) { f = , p++; continue; }
                 b = b *  + rec[str];
             }
             p = p + strlen(str);
         }
         if (!(a + b)) break;
         printf("%d\n", a + b);
     }
     return ;
 }