Symptoms

When accessing an STL object created in one DLL or EXE through a pointer or reference in a different DLL or EXE, you may experience an access violation or other serious program errors including the appearance of data corruption or data loss.

Cause

Most classes in the Standard C++ Libraries use static data members directly or indirectly. Since these classes are generated through template instantiation, each executable image (usually with DLL or EXE file name extensions) will contain its own copy of the static data member for a given class. When a method of the class that requires the static data member is executed, it uses the static data member in the executable image in which the method code resides. Since the static data members in the executable images are not in sync, this action could result in an access violation or data may appear to be lost or corrupted.

Resolution

  1. Export accessor methods from the executable image that created the STL object. These methods wrap the required functionality of the STL object. In this way, the STL object will only be directly accessed inside a single executable image. For example, suppose MyProgram.EXE needs to get the next element in deque<MyClass> that resides in MyLibrary.DLL. MyLibrary.DLL could export an accessor method, MyClass* DequeNextItem (/*...*/). Then MyProgram.EXE could execute this method to get the next item in the deque. See the code sample below for a more complete example.

    This option works for STL objects that are either global, static, or static data members of a class that are not exported from a DLL. This option will not work for non-static data members of a class that are exported from a DLL or for automatic data.

  2. Export the template class instantiation from one executable image and import it into the other executable images. For example, if MyLibrary.DLL passes a pointer to vector<MyClass> back to a function in MyProgram.EXE, then export the classes MyClass and vector<MyClass> from MyLibrary.DLL. Then import these classes into MyProgram.EXE. By doing this, you will have one copy of the static class members residing in MyLibrary.DLL. For more information about exporting and importing STL, click the following article number to view the article in the Microsoft Knowledge Base:
    168958How to export STL components inside and outside of a class

Status

This behavior is by design.

More Information

Steps to reproduce the behavior

   //---------------------------------------------------------
// AVEXE.CPP
// Compile options needed: /GX
#pragma warning (disable : 4786)
#include <map>
#include <string>
#include <stdio.h> __declspec(dllimport)
std::map<int,std::string>* GiveMeAMap(int n); __declspec(dllimport)
void ShowMeTheMap(std::map<int,std::string> *amap); __declspec(dllexport)
const char* MapItemX (std::map<int,std::string> *m, int x); int main () { // Create the map in the DLL
int x = 6;
std::map<int,std::string> *p = GiveMeAMap(x); // Display the contents of the map from the DLL
printf("Showing contents from the DLL\n");
ShowMeTheMap(p); // Display the contents of the map from the EXE
// using the accessor function from the DLL so we
// aren't directly accessing the map
printf("Showing contents from the EXE using accessor\n");
int i = x;
while (i--) {
printf("%d = %s\n",i,MapItemX(p,i));
} // Access Violation when accessing the map that
// was created in the DLL from the EXE
printf("Showing contents from the EXE directly\n");
while (x--) {
printf("%d = %s\n",x,(*p)[x].c_str());
} return 0;
} //---------------------------------------------------------
// AVDLL.CPP
// Compile options needed /GX
#pragma warning (disable : 4786)
#include <map>
#include <string>
#include <stdlib.h> // Create the map here in the DLL
__declspec(dllexport)
std::map<int,std::string>* GiveMeAMap(int n) {
std::map<int,std::string> *m = new std::map<int,std::string>;
while(n--) {
char b[33];
itoa(n,b,2);
(*m)[n] = std::string(b);
}
return m;
} // We can access the map without error from the executable
// image where the map was created
__declspec(dllexport)
void ShowMeTheMap(std::map<int,std::string> *p) {
int x = p->size();
while (x--) {
printf("%d = %s\n",x,(*p)[x].c_str());
}
} // An accessor method to return the associated C string
// for key x
__declspec(dllexport)
const char* MapItemX (std::map<int,std::string> *m, int x) {
return (*m)[x].c_str();
}
 
Properties

Article ID: 172396 - Last Review: Sep 2, 2005 - Revision: 1

You may experience an access violation when you access an STL object through a pointer or reference in a different DLL or EXE的更多相关文章

  1. 如何捕获access violation异常

    文章目录 access violation的由来 access violation的实例 Win32 exception SEH异常与C++标准异常 捕获方法 1.access violation的由 ...

  2. 动态调用DLL函数有时正常,有时报Access violation的异常

    动态调用DLL函数有时正常,有时报Access violation的异常 typedef int (add *)(int a,int b); void test() {     hInst=LoadL ...

  3. 解决 “access violation at address xxxxxxxxx”错误

    在进行磁盘整理的时候,打开Foxmail的时候出现了“access violation at address32383137”错误 和“access violation at address00000 ...

  4. STM32 KEIL不能输入仿真引脚端口error 65: access violation at 0x40021000 : no 'read' permission

    使用MDK自己创建一个STM32F103ZE核的项目 加入源码后编译,正常,在线仿真单步执行出现如下问题 error 65: access violation at 0x40021000 : no ' ...

  5. QDomDocument Access violation writing location

    今天犯了一个非常2的错误! 为了将面板参数保存起来,选择用QDomDocument构造Dom树,然后用doc.toString()方法返回符合xml格式的QString.如: QString CutF ...

  6. Access Violation at address 00000000.Read of address 00000000 解决办法

    是数组越标或没有初始化某个对象之类的问题,搂住细细检查一下代码, 使用指针前未做检查,而这个指针未初始化. 可能是new后没有delete,这样出现溢出的可能性比较大     检查代码或者跟踪试试 使 ...

  7. u-boot TFTP: &#39;Access violation&#39; (2)

    今天做tftp下载时间会遇到以下问题. --->8--- Load address: 0x20000000 Loading: * TFTP error: 'Access violation' ( ...

  8. laravel migrate时报错:Syntax error or access violation: 1071 Specified key was too long; max key length is 767 bytes

    今天在学习laravel的路由模型绑定时,在按照文档执行php artisan migrate时报错. In Connection.php line 664: SQLSTATE[42000]: Syn ...

  9. std::vector push_back报错Access violation

    C/C++ code   ? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 #include < ...

随机推荐

  1. JavaScript函数——预编译

    四部曲 创建AO对象 找形参和变量声明,将变量和形参名作为AO属性名,值为undefined. 将实参值和形参值统一 在函数体内找函数声明,值赋予函数体. 权重按顺序依次增加.以下例子即可体现上述规则 ...

  2. [Codeforces Round#488]Div.2

    总结 这是我无聊透顶肝到三点半的一场 cf ,结果还真够无聊的 这套题涵盖了英语题,语文题,模拟题.注重考查了选手的英语素养能力,语文阅读能力和精湛的模拟和枚举能力.是不可多得的一套好题. 没什么单独 ...

  3. Mvc Moq HttpContext

    1: public class MockMvcHttpContext 2: { 3: public Moq.Mock<System.Web.HttpContextBase> Context ...

  4. LinqProvider系列(三)如何实现自己的Linq Provider?

    这篇文章将在前人的肩上,继续完成实现Linq Provider的任务. 首先,我们列出linq语法的解析过程: linq本质上就是把我们惯用的语法糖,变成了一颗表达式树,然后由不同的linq Prov ...

  5. jQuery扩展插件以及正则相关函数练习

    一.jQuery扩展插件 二.相关正则函数:

  6. JVM内存问题定位

    一.查看机器资源使用状态: 使用top命令,内存占用较高的那个PID对应的进程一般就是JVM了 二.查看Swap状态: 使用free -m 命令,一般内存占用过高会导致swap占用也偏高,看看swap ...

  7. 修改request请求参数

    本质上来讲,request请求当中的参数是无法更改的,也不能添加或者删除: 但在后台程序中,一般对request的参数的操作,都是通过request的getParameter.getParameter ...

  8. git push远程仓库时报错:fatal: remote origin already exists. (已解决)

    在做远程仓库调试阶段,突然发现修改后的项目无法push了: 如果输入$ git remote add origin git@github.com:djqiang(github帐号名)/gitdemo( ...

  9. Unity3D 场景切换加载进度条实现

    需要三个场景,场景A,场景B,场景C: 场景A:一个按钮,点击加载场景B: 场景B:从A切换到C过度场景,加载进度条: 场景C:目标场景: 创建OnProgress.cs脚本: using Syste ...

  10. [AngularJS] “多重路由”嵌套模块——AngularJS“路由”嵌套学习资料教程

    这是小编的一些学习资料,理论上只是为了自己以后学习需要的,但是还是需要认真对待的 以下内容仅供参考,请慎重使用学习 1.AngularJS路由嵌套 Angularjs本身自带路由模块,可以满足通过不同 ...