模拟 CSU 1562 Fun House

题目传送门

 /*
     题意：光线从 '*' 发射，遇到 '/' 或 '\' 进行反射，最后射到墙上，将 'x' 变成 '&'
     模拟：仔细读题，搞清楚要做什么，就是i,j的移动，直到撞到墙，模拟一下一次AC，不要被题目吓怕了:)
 */
 #include <cstdio>
 #include <iostream>
 #include <algorithm>
 #include <stack>
 #include <cmath>
 #include <cstring>
 #include <vector>
 using namespace std;

 const int MAXN = 1e4 + ;
 const int INF = 0x3f3f3f3f;
 char g[][];

 int main(void)        //CSU 1562 Fun House
 {
     //freopen ("B.in", "r", stdin);

     int n, m, cas = ;
     while (scanf ("%d%d", &m, &n) == )
     {
         if (n ==  && m == )    break;

         for (int i=; i<n; ++i)
         {
             scanf ("%s", &g[i]);
         }

         printf ("HOUSE %d\n", ++cas);

         int sx = -, sy = -;
         int num = ;
         for (int i=; i<n; ++i)
         {
             for (int j=; j<m; ++j)
             {
                 if (g[i][j] == '*')
                 {
                     if (j == ) num = ;
                     else if (j == m-)    num = ;
                     else if (i == )    num = ;
                     else if (i == n-)    num = ;
                     sx = i;    sy = j;
                     break;
                 }
             }
         }

         while ()
         {
             if (num == )
             {
                 ++sy;
                 if (g[sx][sy] == '/')    num = ;
                 else if (g[sx][sy] == '\\')    num = ;
                 else if (g[sx][sy] == 'x')
                 {
                     g[sx][sy] = '&';    break;
                 }
             }
             else if (num == )
             {
                 --sy;
                 if (g[sx][sy] == '/')    num = ;
                 else if (g[sx][sy] == '\\')    num = ;
                 else if (g[sx][sy] == 'x')
                 {
                     g[sx][sy] = '&';    break;
                 }
             }
             else if (num == )
             {
                 ++sx;
                 if (g[sx][sy] == '/')    num = ;
                 else if (g[sx][sy] == '\\')    num = ;
                 else if (g[sx][sy] == 'x')
                 {
                     g[sx][sy] = '&';    break;
                 }
             }
             else if (num == )
             {
                 --sx;
                 if (g[sx][sy] == '/')    num = ;
                 else if (g[sx][sy] == '\\')    num = ;
                 else if (g[sx][sy] == 'x')
                 {
                     g[sx][sy] = '&';    break;
                 }
             }
         }

         for (int i=; i<n; ++i)
         {
             for (int j=; j<m; ++j)
             {
                 printf ("%c", g[i][j]);
             }
             puts ("");
         }
     }

     return ;
 }

 /*
 HOUSE 1
 xxxxxxxxxxx
 x../..\...x
 x..../....x
 *../......x
 x.........x
 xxxxxx&xxxx
 HOUSE 2
 xxxxx
 *...&
 x...x
 x...x
 xxxxx
 HOUSE 3
 xxxxx
 x./\x
 *./.x
 x..\&
 xxxxx
 HOUSE 4
 xxx*xx
 x/...x
 x....x
 x/./.&
 x\./.x
 xxxxxx
 HOUSE 5
 xxxxxxxxxx
 x.../\...x
 x........x
 x........x
 &.../\..\x
 *...\/../x
 x........x
 x........x
 x...\/...x
 xxxxxxxxxx
 */