The Hardest Problem Ever(字符串)
| Time Limit: 1000MS | Memory Limit: 10000K | |
| Total Submissions: 24039 | Accepted: 13143 |
Description
You are a sub captain of Caesar's army. It is your job to decipher the messages sent by Caesar and provide to your general. The code is simple. For each letter in a plaintext message, you shift it five places to the right to create the secure message (i.e., if the letter is 'A', the cipher text would be 'F'). Since you are creating plain text out of Caesar's messages, you will do the opposite:
Cipher text
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Plain text
V W X Y Z A B C D E F G H I J K L M N O P Q R S T U
Only letters are shifted in this cipher. Any non-alphabetical character should remain the same, and all alphabetical characters will be upper case.
Input
A single data set has 3 components:
- Start line - A single line, "START"
- Cipher message - A single line containing from one to two hundred characters, inclusive, comprising a single message from Caesar
- End line - A single line, "END"
Following the final data set will be a single line, "ENDOFINPUT".
Output
Sample Input
START
NS BFW, JAJSYX TK NRUTWYFSHJ FWJ YMJ WJXZQY TK YWNANFQ HFZXJX
END
START
N BTZQI WFYMJW GJ KNWXY NS F QNYYQJ NGJWNFS ANQQFLJ YMFS XJHTSI NS WTRJ
END
START
IFSLJW PSTBX KZQQ BJQQ YMFY HFJXFW NX RTWJ IFSLJWTZX YMFS MJ
END
ENDOFINPUT
Sample Output
IN WAR, EVENTS OF IMPORTANCE ARE THE RESULT OF TRIVIAL CAUSES
I WOULD RATHER BE FIRST IN A LITTLE IBERIAN VILLAGE THAN SECOND IN ROME
DANGER KNOWS FULL WELL THAT CAESAR IS MORE DANGEROUS THAN HE
Source
题解:字符串替换;
代码:
#include<stdio.h>
#include<string.h>
#include<algorithm>
#include<iostream>
using namespace std;
const int MAXN=;
char plain[MAXN],str[MAXN];
int main(){
strcpy(plain,"VWXYZABCDEFGHIJKLMNOPQRSTU");
while(true){
cin.getline(str,MAXN);
if(!strcmp(str,"ENDOFINPUT"))break;
else if(!strcmp(str,"START")||!strcmp(str,"END"))continue;
else for(int i=;str[i];i++){
if(isalpha(str[i]))str[i]=plain[str[i]-'A'];
}
printf("%s\n",str);
}
return ;
}
The Hardest Problem Ever(字符串)的更多相关文章
- (字符串 枚举)The Hardest Problem Ever hdu1048
The Hardest Problem Ever 链接:http://acm.hdu.edu.cn/showproblem.php?pid=1048 Time Limit: 2000/1000 MS ...
- HDUOJ-------The Hardest Problem Ever
The Hardest Problem Ever Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java ...
- hdu_1048_The Hardest Problem Ever_201311052052
The Hardest Problem Ever Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java ...
- HDU1048The Hardest Problem Ever
The Hardest Problem Ever Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & ...
- POJ 1298 The Hardest Problem Ever【字符串】
Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever faced was ke ...
- Poj1298_The Hardest Problem Ever(水题)
一.Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar eve ...
- poj1298 The Hardest Problem Ever 简单题
链接:http://poj.org/problem?id=1298&lang=default&change=true 简单的入门题目也有这么强悍的技巧啊!! 书上面的代码: 很厉害有没 ...
- HDOJ 1048 The Hardest Problem Ever(加密解密类)
Problem Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caes ...
- C - The Hardest Problem Ever
Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever ...
随机推荐
- 数据结构-B树
1.前言: 动态查找树主要有:二叉查找树(Binary Search Tree),平衡二叉查找树(Balanced Binary Search Tree),红黑树(Red-Black Tree ) ...
- VitualBox中linux系统ping ip能通域名不通的解决办法
linux本机的DNS配置信息是在:/etc/resolv.conf vi打开,修改为本机的dns服务器地址
- 怎查看linux系统的位数
# uname -a x86_64则说明你是64位内核, 跑的是64位的系统. i386, i686说明你是32位的内核, 跑的是32位的系统
- Delphi编写的Android程序获取Root权限实现(2015.4.15更新,支持Android 4.4)
借助谷歌,并经过本大侠施展坑.蒙.拐.骗.偷五大绝技,终于成功实现在Delphi下获取Root权限并将其扩展为一个完整功能更加完整的TQAndroidShell记录,在华为荣耀2(Android 4. ...
- Linux学习之十一、环境变量的功能
环境变量的功能 可以利用两个命令来查阅,分别是 env 与 export 呢! 范例一:列出目前的 shell 环境下的所有环境变量与其内容. [root@www ~]# env SHELL 告知我们 ...
- Flash,一次Bug的思考
我绝对不算是F黑,大部分时候,我还是很挺Flash平台的,Flash提供了很好的跨平台特性以及Flash Player11后的GPU加速.Stage3D等等,对于开发者来说,绝对让人欣喜若狂(对我是这 ...
- 把war包放到Tomcat安装文件夹下,不能直接訪问的解决方式
临床表现: Tomcat启动后首页能訪问(http://localhost:8080/). 将自己写的一个webprojectwar包放到Tomcat安装文件夹下的/webapps以下(比方hello ...
- Android创建启动画面[转]
每个Android应用启动之后都会出现一个Splash启动界面,显示产品的LOGO.公司的LOGO或者开发者信息.如果应用程序启动时间比较长,那么启动界面就是一个很好的东西,可以让用户耐心等待这段枯燥 ...
- iOS坐标转换
// 将像素point由point所在视图转换到目标视图view中,返回在目标视图view中的像素值 - (CGPoint)convertPoint:(CGPoint)point toView:(UI ...
- EJB QI查询
EO.PNAME like ?1 OR EO.PNAME like ?2"; Query query = entityManager.createNativeQuery(quer ...