sqlserver——cube：多维数据集

1、cube:生成多维数据集，包含各维度可能组合的交叉表格，使用with 关键字连接 with cube

根据需要使用union all 拼接
判断 某一列的null值来自源数据还是 cube 使用GROUPING关键字
GROUPING([档案号]) = 1 ： null值来自cube（代表所有的档案号）
GROUPING([档案号]) = 0 ： null值来自源数据

举例：

 SELECT  * INTO ##GET
                 FROM
                     (
                         SELECT
                             *
                         FROM
                             (
                                 SELECT
                                     CASE
                                 WHEN (GROUPING([档案号]) = 1) THEN
                                     '合计'
                                 ELSE
                                     [档案号]
                                 END AS '档案号',
                                 CASE
                             WHEN (GROUPING([系列]) = 1) THEN
                                 '合计'
                             ELSE
                                 [系列]
                             END AS '系列',
                             CASE
                         WHEN (GROUPING([店长]) = 1) THEN
                             '合计'
                         ELSE
                             [店长]
                         END AS '店长',
                         SUM (剩余次数) AS '总剩余',
                         CASE
                     WHEN (GROUPING([店名]) = 1) THEN
                         '合计'
                     ELSE
                         [店名]
                     END AS '店名'
                     FROM
                         ##PudianCard
                     GROUP BY
                         [档案号],
                         [店名],
                         [店长],
                         [系列] WITH cube
                     HAVING
                         GROUPING([店名]) != 1
                     AND GROUPING([档案号]) = 1 --AND GROUPING([系列]) = 1
                             ) AS M
                         UNION ALL
                             (
                                 SELECT
                                     *
                                 FROM
                                     (
                                         SELECT
                                             CASE
                                         WHEN (GROUPING([档案号]) = 1) THEN
                                             '合计'
                                         ELSE
                                             [档案号]
                                         END AS '档案号',
                                         CASE
                                     WHEN (GROUPING([系列]) = 1) THEN
                                         '合计'
                                     ELSE
                                         [系列]
                                     END AS '系列',
                                     CASE
                                 WHEN (GROUPING([店长]) = 1) THEN
                                     '合计'
                                 ELSE
                                     [店长]
                                 END AS '店长',
                                 SUM (剩余次数) AS '总剩余',
                                 CASE
                             WHEN (GROUPING([店名]) = 1) THEN
                                 '合计'
                             ELSE
                                 [店名]
                             END AS '店名'
                             FROM
                                 ##PudianCard
                             GROUP BY
                                 [档案号],
                                 [店名],
                                 [店长],
                                 [系列] WITH cube
                             HAVING
                                 GROUPING([店名]) != 1
                             AND GROUPING([店长]) != 1
                                     ) AS P
                             )
                         UNION ALL
                             (
                                 SELECT
                                     *
                                 FROM
                                     (
                                         SELECT
                                             CASE
                                         WHEN (GROUPING([档案号]) = 1) THEN
                                             '合计'
                                         ELSE
                                             [档案号]
                                         END AS '档案号',
                                         CASE
                                     WHEN (GROUPING([系列]) = 1) THEN
                                         '合计'
                                     ELSE
                                         [系列]
                                     END AS '系列',
                                     CASE
                                 WHEN (GROUPING([店长]) = 1) THEN
                                     '合计'
                                 ELSE
                                     [店长]
                                 END AS '店长',
                                 SUM (剩余次数) AS '总剩余',
                                 CASE
                             WHEN (GROUPING([店名]) = 1) THEN
                                 '合计'
                             ELSE
                                 [店名]
                             END AS '店名'
                             FROM
                                 ##PudianCard
                             GROUP BY
                                 [档案号],
                                 [店名],
                                 [店长],
                                 [系列] WITH cube
                             HAVING
                                 GROUPING([店名]) != 1
                             AND GROUPING([店长]) != 1
                                     ) AS W
                             )
                         UNION ALL
                             (
                                 SELECT
                                     *
                                 FROM
                                     (
                                         SELECT
                                             CASE
                                         WHEN (GROUPING([档案号]) = 1) THEN
                                             '合计'
                                         ELSE
                                             [档案号]
                                         END AS '档案号',
                                         CASE
                                     WHEN (GROUPING([系列]) = 1) THEN
                                         '合计'
                                     ELSE
                                         [系列]
                                     END AS '系列',
                                     CASE
                                 WHEN (GROUPING([店长]) = 1) THEN
                                     '合计'
                                 ELSE
                                     [店长]
                                 END AS '店长',
                                 SUM (剩余次数) AS '总剩余',
                                 CASE
                             WHEN (GROUPING([店名]) = 1) THEN
                                 '合计'
                             ELSE
                                 [店名]
                             END AS '店名'
                             FROM
                                 ##PudianCard
                             GROUP BY
                                 [档案号],
                                 [店名],
                                 [店长],
                                 [系列] WITH cube
                             HAVING
                                 GROUPING([店名]) = 1
                             AND GROUPING([店长]) = 1
                             AND GROUPING([档案号]) = 1
                                     ) AS K
                             )
                     ) AS T
2、rollup:功能跟cube相似

3、将某一列的数据作为列名，动态加载，使用存储过程，拼接字符串
DECLARE @st nvarchar (MAX) = '';

SELECT
@st =@st + 'max(case when [系列]=''' + CAST ([系列] AS VARCHAR) + ''' then [总剩余] else null end ) as [' + CAST ([系列] AS VARCHAR) + '],'
FROM
##GET
GROUP BY
[系列];
print @st;

4、根据某一列分组，分别建表
SELECT
'select ROW_NUMBER() over(order by [卡项] desc) as [序号], [会员],[档案号],[卡项],[剩余次数],[员工],[店名] into ' + ltrim([店名]) + ' from 查询 where [店名]=''' + [店名] + ''' ORDER BY [卡项] desc'
FROM
查询
GROUP BY
[店名]