https://pintia.cn/problem-sets/994805342720868352/problems/994805444361437184

Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1, 10^4^]. The first one who bets on a unique number wins. For example, if there are 7 people betting on 5 31 5 88 67 88 17, then the second one who bets on 31 wins.

Input Specification:

Each input file contains one test case. Each case contains a line which begins with a positive integer N (<=10^5^) and then followed by N bets. The numbers are separated by a space.

Output Specification:

For each test case, print the winning number in a line. If there is no winner, print "None" instead.

Sample Input 1:

7 5 31 5 88 67 88 17

Sample Output 1:

31

Sample Input 2:

5 888 666 666 888 888

Sample Output 2:

None

代码:
#include <bits/stdc++.h>
using namespace std; const int maxn = 1e5 + 10;
int a[maxn], num[maxn]; int main() {
int n;
scanf("%d", &n);
for(int i = 1; i <= n; i ++) {
scanf("%d", &a[i]);
num[a[i]] ++;
} int cnt = 0;
for(int i = 1; i <= n; i ++) {
if(num[a[i]] == 1) {
printf("%d\n", a[i]);
return 0;
}
if(num[a[i]] > 1)
cnt ++;
}
if(cnt == n)
printf("None\n");
return 0;
}

  

PAT 甲级 1041 Be Unique的更多相关文章

  1. PAT 甲级 1041 Be Unique (20 分)

    1041 Be Unique (20 分) Being unique is so important to people on Mars that even their lottery is desi ...

  2. PAT 甲级 1041 Be Unique (20 分)(简单,一遍过)

    1041 Be Unique (20 分)   Being unique is so important to people on Mars that even their lottery is de ...

  3. PAT甲级——1041 Be Unique

    1041 Be Unique Being unique is so important to people on Mars that even their lottery is designed in ...

  4. PAT 甲级 1041. Be Unique (20) 【STL】

    题目链接 https://www.patest.cn/contests/pat-a-practise/1041 思路 可以用 map 标记 每个数字的出现次数 然后最后再 遍历一遍 找到那个 第一个 ...

  5. PAT甲 1041. Be Unique (20) 2016-09-09 23:14 33人阅读 评论(0) 收藏

    1041. Be Unique (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Being uniqu ...

  6. 【PAT】1041. Be Unique (20)

    题目链接:http://pat.zju.edu.cn/contests/pat-a-practise/1041 题目描述: Being unique is so important to people ...

  7. PAT Advanced 1041 Be Unique (20 分)

    Being unique is so important to people on Mars that even their lottery is designed in a unique way. ...

  8. PAT甲级——A1041 Be Unique

    Being unique is so important to people on Mars that even their lottery is designed in a unique way. ...

  9. PAT Advanced 1041 Be Unique (20) [Hash散列]

    题目 Being unique is so important to people on Mars that even their lottery is designed in a unique wa ...

随机推荐

  1. Django模型定义参考

    字段 对字段名称的限制 字段名不能是Python的保留字,否则会导致语法错误 字段名不能有多个连续下划线,否则影响ORM查询操作 Django模型字段类 字段类 说明 AutoField 自增ID字段 ...

  2. skyline画折现bug代码

    <!DOCTYPE html><html> <head> <meta charset="utf-8"> <title>加 ...

  3. Go语言中结构体的使用-第2部分OOP

    1 概述 结构体的基本语法请参见:Go语言中结构体的使用-第1部分结构体.结构体除了是一个复合数据之外,还用来做面向对象编程.Go 语言使用结构体和结构体成员来描述真实世界的实体和实体对应的各种属性. ...

  4. python 内置调试工具 pdb

    除了 pycharm 可以调试python外,python自带的内置工具pdb 也可以调试 python.其命令方式类似于 gdb. pdb 常用的调试命令见下表. 命令 解释 break 或 b 设 ...

  5. 学号20155311 2016-2017-2 《Java程序设计》第一次实验报告

    课程:Java程序设计 实验名称:Java开发环境的熟悉 实验目的与要求: 没有Linux基础的同学建议先学习<Linux基础入门(新版)><Vim编辑器> 课程: 完成实验. ...

  6. 2017-2018-1 20155318 《信息安全系统设计基础》第2周课堂实践、makefile、以及myod

    2017-2018-1 20155318 <信息安全系统设计基础>第2周课堂实践.makefile.以及myod 测试3-gdb测试 用gcc -g编译vi输入的代码 在main函数中设置 ...

  7. 【转载】TCP/IP 之 大明王朝邮差

    原文:TCP/IP 之 大明王朝邮差 原创 2016-05-12 刘欣 码农翻身 前言: 本文主要想说一下TCP的知识, 比喻有不恰当之处,敬请包涵. 大明王朝天启四年, 清晨. 天色刚蒙蒙亮,我就赶 ...

  8. Drupal7 配置多站点及为每个站点设置语言

    默认情况 在Drupal7的安装目录下存在sites目录 sites目录结构如下: --all --default --example.sites.php --README.txt 1. 添加新域名, ...

  9. 「日常训练」The Necklace(UVA-10054)

    代码 for(int i=0; i!=n; ++i) { int u = cin.nextInt(); int v = cin.nextInt(); edges.add(new Edge(u,v)); ...

  10. moment.js使用方法总结

    Moment.js是一个轻量级的JavaScript时间库,它方便了日常开发中对时间的操作,提高了开发效率.日常开发中,通常会对时间进行下面这几个操作:比如获取时间,设置时间,格式化时间,比较时间等等 ...