number(10,6)正则表达式

/**
     * 判断number(10,6)
     * @param dateStr
     * @return
     */
    public boolean isNumJW(String num){
        String regex = "^(\\d{0,4}\\.\\d{0,6})$";
        //符号需要转义,纯正则为:^(\d{0,4}\.\d{0,6})$
        Pattern p = Pattern.compile(regex);
        Matcher m = p.matcher(num);
        return m.matches();
    }