Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
解题思路:
新建一个ListNode进行存储即可,JAVA实现如下:
	static public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
ListNode listnode=new ListNode(0);
ListNode index=listnode;
while(l1!=null&&l2!=null){
if(l1.val>l2.val){
ListNode temp=l1;
l1=l2;
l2=temp;
}
index.next=new ListNode(l1.val);
index=index.next;
l1=l1.next;
}
if(l1==null)
index.next=l2;
else
index.next=l1;
return listnode.next;
}

C++:

 class Solution {
public:
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
if (l1 == NULL)
return l2;
else if (l2 == NULL)
return l1;
ListNode* start;
if (l1->val < l2->val) {
start = l1;
l1 = l1->next;
}
else {
start = l2;
l2 = l2->next;
}
ListNode* cur = start;
while (l1 != NULL&&l2 != NULL) {
if (l1->val < l2->val) {
cur->next = l1;
cur = cur->next;
l1 = l1->next;
}
else {
cur->next = l2;
cur = cur->next;
l2 = l2->next;
}
}
if (l1 == NULL)
cur->next = l2;
else
cur->next = l1;
return start;
}
};

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