Given a singly linked list, return a random node's value from the linked list. Each node must have the same probability of being chosen.

Follow up:
What if the linked list is extremely large and its length is unknown to you? Could you solve this efficiently without using extra space?

Example:

// Init a singly linked list [1,2,3].
ListNode head = new ListNode(1);
head.next = new ListNode(2);
head.next.next = new ListNode(3);
Solution solution = new Solution(head); // getRandom() should return either 1, 2, or 3 randomly. Each element should have equal probability of returning.
solution.getRandom();
代码如下:(方法一)
 /**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution { /** @param head The linked list's head.
Note that the head is guaranteed to be not null, so it contains at least one node. */ private List<Integer> list=new ArrayList<>(); public Solution(ListNode head) {
ListNode p=head;
int i=0;
while(p!=null)
{
list.add(p.val);
p=p.next;
i++;
}
} /** Returns a random node's value. */
public int getRandom() {
Random random=new Random(); int q=random.nextInt(list.size());
return list.get(q); }
} /**
* Your Solution object will be instantiated and called as such:
* Solution obj = new Solution(head);
* int param_1 = obj.getRandom();
*/

方法二:(参考别人的)

 /**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution { /** @param head The linked list's head.
Note that the head is guaranteed to be not null, so it contains at least one node. */ private ListNode list=null;
private int size=0;
public Solution(ListNode head) {
list=head;
ListNode p=head;
while(p!=null)
{
p=p.next;
size++;
}
} /** Returns a random node's value. */
public int getRandom() {
ListNode ss=list;
int rand=(int)(Math.random()*size);
while(rand>0&&ss!=null)
{
ss=ss.next;
rand--;
}
return ss!=null?ss.val:0;
}
} /**
* Your Solution object will be instantiated and called as such:
* Solution obj = new Solution(head);
* int param_1 = obj.getRandom();
*/

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