POJ. 1005 I Think I Need a Houseboat(水 )
POJ. 1005 I Think I Need a Houseboat(水 )
代码总览
#include <cstdio>
#include <cstring>
#include <cmath>
#include <queue>
#include <stack>
#include <vector>
#define nmax
using namespace std;
const double pi = acos(-1);
int main()
{
double x,y ;
int n;
scanf("%d",&n);
for(int i =1;i<=n;++i){
scanf("%lf %lf" ,&x,&y);
double rf = x*x + y*y;
double area = pi*rf /2;
printf("Property %d: This property will begin eroding in year %d.\n",i,(int)ceil(area / 50.0));
}
printf("END OF OUTPUT.\n");
return 0;
}
POJ. 1005 I Think I Need a Houseboat(水 )的更多相关文章
- OpenJudge/Poj 1005 I Think I Need a Houseboat
1.链接地址: http://bailian.openjudge.cn/practice/1005/ http://poj.org/problem?id=1005 2.题目: I Think I Ne ...
- [POJ 1005] I Think I Need a Houseboat C++解题
I Think I Need a Houseboat Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 81874 ...
- poj 1005:I Think I Need a Houseboat(水题,模拟)
I Think I Need a Houseboat Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 85149 Acce ...
- [POJ] #1005# I Think I Need a Houseboat : 浮点数运算
一. 题目 I Think I Need a Houseboat Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 97512 ...
- poj 1005 I Think I Need a Houseboat
#include <iostream> using namespace std; const double pi = 3.1415926535; int main() { ;; doubl ...
- I Think I Need a Houseboat POJ - 1005
I Think I Need a Houseboat POJ - 1005 解题思路:水题 #include <iostream> #include <cstdio> #inc ...
- I Think I Need a Houseboat POJ - 1005(数学)
题目大意 在二维坐标内选定一个点,问你当洪水以半圆形扩散且每年扩散50单位,哪一年这个点被被洪水侵蚀? 解法 代码 #include <iostream> #include <cst ...
- POJ 1005 解题报告
1.题目描述 2.解题思路 好吧,这是个水题,我的目的暂时是把poj第一页刷之,所以水题也写写吧,这个题简单数学常识而已,给定坐标(x,y),易知当圆心为(0,0)时,半圆面积为0.5*PI*(x ...
- 1005 -- I Think I Need a Houseboat
I Think I Need a Houseboat Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 105186 Acc ...
随机推荐
- Java enum类型笔记
用途: 定义命令行参数,菜单选项,星期,方向(东西南北)等 与普通类的不同 有默认的方法 value() 每个enum类都已默认继承java.lang.Enum,所以enum类不能继承其他类 构造方法 ...
- Oracle启动与关闭数据库实例
Oracle数据库启动实例分为3个步骤: 启动实例 加载数据库 打开数据库 通用模式: STARTUP [ nomount | mount | open | force ] [resetrict] ...
- Java并发基础--volatile关键字
一.java内存模型 1.java内存模型 程序运行过程中的临时数据是存放在主存(物理内存)中,但是现代计算机CPU的运算能力和速度非常的高效,从内存中读取和写入数据的速度跟不上CPU的处理速度,在这 ...
- 376. Binary Tree Path Sum【LintCode java】
Description Given a binary tree, find all paths that sum of the nodes in the path equals to a given ...
- [SHELL]shell中变量的使用
1.输出变量 : #! /bin/bash my_var=BOB echo $my_var echo "hi,$my_var" echo "the price is \$ ...
- 出现java.lang.Exception: java.lang.RuntimeException: java.lang.NoSuchMethodException: com.web.visit.main.ClickVist$VisitMapper.<init>()的问题
执行mapreduce报错java.lang.Exception: java.lang.RuntimeException: java.lang.NoSuchMethodException: com.w ...
- window.open()与window.showModalDialog区别
window.open()与window.showModalDialog区别 弹出窗口两种方式: 1.window.showModalDialog: var feature = &qu ...
- HDU 3726 Graph and Queries(平衡二叉树)(2010 Asia Tianjin Regional Contest)
Description You are given an undirected graph with N vertexes and M edges. Every vertex in this grap ...
- jQuery实现仿京东商城图片放大镜
效果图: 不废话直接上代码: <!DOCTYPE html> <html> <head> <meta charset="utf-8"> ...
- popen()与system()
一.popen() 用途:执行shell命令(并读取其输出或向其发送一些输入) 特点:通过管道来与shell命令进行通信 二.system()