hdu 2251 Dungeon Master bfs
| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 17555 | Accepted: 6835 |
Description
Is an escape possible? If yes, how long will it take?
Input
input consists of a number of dungeons. Each dungeon description starts
with a line containing three integers L, R and C (all limited to 30 in
size).
L is the number of levels making up the dungeon.
R and C are the number of rows and columns making up the plan of each level.
Then there will follow L blocks of R lines each containing C
characters. Each character describes one cell of the dungeon. A cell
full of rock is indicated by a '#' and empty cells are represented by a
'.'. Your starting position is indicated by 'S' and the exit by the
letter 'E'. There's a single blank line after each level. Input is
terminated by three zeroes for L, R and C.
Output
Escaped in x minute(s).
where x is replaced by the shortest time it takes to escape.
If it is not possible to escape, print the line
Trapped!
Sample Input
3 4 5
S....
.###.
.##..
###.# #####
#####
##.##
##... #####
#####
#.###
####E 1 3 3
S##
#E#
### 0 0 0
Sample Output
Escaped in 11 minute(s).
Trapped!
Source
#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
#define maxn 31
const int inf=0x7fffffff; //无限大
int visited[maxn][maxn][maxn];
struct node
{
int x;
int y;
int z;
int cnt;
};
int dx[]={,-,,,,};
int dy[]={,,,-,,};
int dz[]={,,,,,-};
int main()
{
int n,m,k;
string s;
while(cin>>n>>m>>k)
{
if(n==&&m==&&k==)
break;
memset(visited,,sizeof(visited));
node sb;
node sb2;
for(int i=;i<n;i++)
{
for(int j=;j<m;j++)
{
cin>>s;
for(int t=;t<k;t++)
{
if(s[t]=='S')
{
sb.x=i;
sb.y=j;
sb.z=t;
sb.cnt=;
}
if(s[t]=='E')
{
sb2.x=i;
sb2.y=j;
sb2.z=t;
}
if(s[t]=='#')
{
visited[i][j][t]=;
}
}
}
}
queue<node> q;
q.push(sb);
visited[sb.x][sb.y][sb.z]=;
int flag=;
while(!q.empty())
{
node now=q.front();
for(int i=;i<;i++)
{
node next;
next.x=now.x+dx[i];
next.y=now.y+dy[i];
next.z=now.z+dz[i];
next.cnt=now.cnt+;
if(next.x<||next.x>=n||next.y<||next.y>=m||next.z<||next.z>=k)
continue;
if(visited[next.x][next.y][next.z])
continue;
visited[next.x][next.y][next.z]=;
if(next.x==sb2.x&&next.y==sb2.y&&next.z==sb2.z)
flag=next.cnt;
if(flag>)
break;
q.push(next);
}
if(flag>)
break;
q.pop();
}
if(flag>)
printf("Escaped in %d minute(s).\n",flag);
else
cout<<"Trapped!"<<endl; }
return ;
}
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