This time, you are supposed to find A+B where A and B are two polynomials.

Input Specification:

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:

K N​1​​ a​N​1​​​​ N​2​​ a​N​2​​​​ ... N​K​​ a​N​K​​​​

where K is the number of nonzero terms in the polynomial, N​i​​ and a​N​i​​​​ (i=1,2,⋯,K) are the exponents and coefficients, respectively. It is given that 1≤K≤10,0≤N​K​​<⋯<N​2​​<N​1​​≤1000.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input:

2 1 2.4 0 3.2
2 2 1.5 1 0.5

Sample Output:

3 2 1.5 1 2.9 0 3.2

题目很简单,说一下可能的wa点:
1. 末尾不要有空格。
2. 两项相加可能为零,此时要删除此项。
代码如下:
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
typedef struct node *ptonext;
typedef ptonext ploy, list;
struct node{
float n;
int e;
ptonext next;
ptonext pro;
};
list A, B;
list res;
ptonext A_head, A_tail;
ptonext B_head, B_tail;
ptonext r_head, r_tail;
int cnt;
list init()
{
ptonext T;
T = (list)malloc(sizeof(list));
T->n = ;
T->e = ;
T->pro = NULL;
T->next = NULL;
return T;
}
void caculate()
{
ptonext a, b, r;
ptonext T;
a = A_head;
b = B_head;
r = r_head;
a = a->next;
b = b->next;
while(a != A_tail && b != B_tail)
{
if(a->e == b->e){
T = (ptonext)malloc(sizeof(ptonext));
T->e = a->e;
T->n = a->n + b->n;
if(T->n == ){
a = a->next;
b = b->next;
continue;
}
T->pro = r;
r->next = T;
r = r->next;
a = a->next;
b = b->next;
cnt++;
}
else if(a->e > b->e){
T = (ptonext)malloc(sizeof(ptonext));
T->e = a->e;
T->n = a->n;
r->next = T;
T->pro = r;
r = r->next;
a = a->next;
cnt++;
}
else{
T = (ptonext)malloc(sizeof(ptonext));
T->e = b->e;
T->n = b->n;
r->next = T;
T->pro = r;
r = r->next;
b = b->next;
cnt++;
}
}
while(a != A_tail){
T = (ptonext)malloc(sizeof(ptonext));
T->e = a->e;
T->n = a->n;
r->next = T;
T->pro = r;
r = r->next;
a = a->next;
cnt++;
}
while(b != B_tail){
T = (ptonext)malloc(sizeof(ptonext));
T->e = b->e;
T->n = b->n;
r->next = T;
T->pro = r;
r = r->next;
b = b->next;
cnt++;
}
r->next = r_tail;
r_tail->pro = r;
}
int main()
{
int k;
float n;
int e;
A = init();
B = init();
res = init();
A_tail = init();
B_tail = init();
r_tail = init();
A_head = A;
B_head = B;
r_head = res;
cnt = ;
scanf("%d", &k);
while(k--){
scanf("%d %f", &e, &n);
ptonext T;
T = (ptonext)malloc(sizeof(ptonext));
T->n = n;
T->e = e;
A->next = T;
T->pro = A;
A = A->next;
}
A->next = A_tail;
A_tail->pro = A;
scanf("%d", &k);
while(k--){
scanf("%d %f", &e, &n);
ptonext T;
T = (ptonext)malloc(sizeof(ptonext));
T->n = n;
T->e = e;
B->next = T;
T->pro = B;
B = B->next;
}
B->next = B_tail;
B_tail->pro = B;
caculate();
printf("%d", cnt);
while(res->next != r_tail){
printf(" %d %.1f", res->next->e, res->next->n);
res = res->next;
}
printf("\n");
// system("pause");
return ;
}

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