Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.

Example:

Input:
[1,2,3] Output:
3 Explanation:
Only three moves are needed (remember each move increments two elements): [1,2,3] => [2,3,3] => [3,4,3] => [4,4,4]

Solution:

incrementing n-1 elements by one, means every time need to increment 1 to every number except the maximum. but it's hard to implement.

Increment to every nums except max, is as same as decrement 1 on one number until every number equals min number.

 public class Solution {
public int MinMoves(int[] nums) {
if(nums.Length==)
{
return ;
}
int n = nums.Length;
//Find min value in nums;
int min =nums[];
foreach(int num in nums)
{
min = Math.Min(min, num);
} //calculate the difference of every num from nums and min; ths sum should be the min Moves
//add 1 to n-1 is same as minus 1 from the max each time.
int moves = ;
foreach(int num in nums)
{
moves +=(num-min);
}
return moves;
}
}

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