The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

Read N Characters Given Read4 The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the rea…

Read N Characters Given Read4 The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the rea…

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

原题链接在这里:https://leetcode.com/problems/read-n-characters-given-read4-ii-call-multiple-times/ 题目: The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns…

Difficulty: Hard  More:[目录]LeetCode Java实现 Description Similar to Question [Read N Characters Given Read4], but the read function may be called multiple times. Intuition 题意:本题与上一题的区别就是连续多次调用read()函数,所以需要将存储4个字符的缓存buffer定义为全局变量,此外全局变量还需要定义buffer[]中的开始…

The API: int read4(char *buf) reads 4 characters at a time from a file.The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file.By using the read4 API, implement the function i…

原题链接在这里:https://leetcode.com/problems/read-n-characters-given-read4/ 题目: The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 ch…

The API: int read4(char *buf) reads 4 characters at a time from a file.The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file.By using the read4 API, implement the function i…

Problem: The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 直接调用 日期 题目地址:https://leetcode-cn.com/problems/read-n-characters-given-read4/ 题目描述 Given a file and assume that you can only read the file using a given method read4, implement a…

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

题目: The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the func…

想了好一会才看懂题目意思,应该是: 这里指的可以调用更多次,是指对一个文件多次操作,也就是对于一个case进行多次的readn操作.上一题是只进行一次reandn,所以每次返回的是文件的长度或者是n,并且将相应的字符存在buf里.现在调用多次的话就可能存在以下的例子: 例如文件case是:1,2,3,4,5,6,7 如果要实现read5,先用read4读四个到buf,再用read4读剩下的3个到buf+4之后,但是read5一次最多读5个到buf,所以read4多读的2个就要存起来,防止下次调用…

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

题目: The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the func…

The API: int read4(char *buf) reads 4 characters at a time from a file.The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file.By using the read4 API, implement the function i…

Difficulty: Easy  More:[目录]LeetCode Java实现 Description The API: int read4(char *buf) reads 4 characters at a time from a file.The return value is the actual number of characters read. For example, it returns 3 if thereis only 3 characters left in the…

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

Read N Characters Given Read4 I/II 要点:这题的要点就是搞清楚几个变量的内在逻辑:只有buffer是整4 bytes的.而client要读的bytes(需求)和实际上disk上有的bytes(供给)都是不整的.所以, 循环的条件就是either 供给不足 or 需求不足:供给不足的判定是上一轮数据不够4 bytes的mark,而需求不足是toRead的计数<=0 所以循环体内,就是min(读进来的bytes, toRead)来把数据copy到buffer里,同时…

Given a string, find the length of the longest substring without repeating characters. Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3. Example 2: Input: "bbbbb" Output: 1 Explana…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

LinkedIn(39) 1 Two Sum 23.0% Easy 21 Merge Two Sorted Lists 35.4% Easy 23 Merge k Sorted Lists 23.3% Hard 33 Search in Rotated Sorted Array 30.2% Hard 34 Search for a Range 29.1% Medium 46 Permutations 35.7% Medium 47 Permutations II 28.0% Medium 50…

158. Read N Characters Given Read4 II - Call multiple times 题目: The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

这里记录一下自己刷的LeetCode题目. 有些博客用英文阐述自己的思路和收获,相当于练习一下英文的表达能力. 比较好的题目有加粗. 1. Two Sum 3. Longest Substring Without Repeating Characters 5. Longest Palindromic Substring 7. Reverse Integer 9. Palindrome Number 8. String to Integer (atoi) 溢出的处理 21. Merge Two S…