[LeetCode] Can I Win 我能赢吗】的更多相关文章

In the "100 game," two players take turns adding, to a running total, any integer from 1..10. The player who first causes the running total to reach or exceed 100 wins. What if we change the game so that players cannot re-use integers? For examp…
In the "100 game," two players take turns adding, to a running total, any integer from 1..10. The player who first causes the running total to reach or exceed 100 wins. What if we change the game so that players cannot re-use integers? For examp…
In the "100 game," two players take turns adding, to a running total, any integer from 1..10. The player who first causes the running total to reach or exceed 100 wins. What if we change the game so that players cannot re-use integers? For examp…
详见:https://leetcode.com/problems/can-i-win/description/ C++: class Solution { public: bool canIWin(int maxChoosableInteger, int desiredTotal) { if (maxChoosableInteger >= desiredTotal) { return true; } if (maxChoosableInteger * (maxChoosableInteger +…
#!/usr/bin/python # -*- coding: utf-8 -*- from random import shuffle class caigame: win=False flag=False life=12 what=-1 s1='' map1=[] thenum=0 def start(self): t=range(1,10) shuffle(t) self.thenum=t[0]*1000+t[1]*100+t[2]*10+t[3] self.inmap() print s…
Football the most popular sport in the world (americans insist to call it "Soccer", but we will call it "Football"). As everyone knows, Brasil is the country that have most World Cup titles (four of them: 1958, 1962, 1970 and 1994). As…
三.编程题(4小题共40.0分)程序及结果写入对应文框内 1. 孪生素数查找程序. 所谓孪生素数指的是间隔为2 的相邻素数,就像孪生兄弟.最小的孪生素数是(3, 5),在100 以内的孪生素数还有 (5, 7), (11, 13), (17, 19), (29, 31), (41, 43), (59, 61) 和(71, 73),总计有 8 组. 现给定一个正整数number,要求编程计算出小于等于number的孪生素数的组数,请根据要求,完成getPrimeTwins方法. 方法原型如下: /…
Week3. Welcome to week 3! This is our fourth and final week of History where we make the connection from those early innovations of the modern Internet we are using for this class. Up next we move into looking at how the Internet works on the inside.…
动态规划是一种top-down求解模式,关键在于分解和求解子问题,然后根据子问题的解不断向上递推,得出最终解 因此dp涉及到保存每个计算过的子问题的解,这样当遇到同样的子问题时就不用继续向下求解而直接可以得到结果.状态压缩就是用来保存子问题的解的,主要思想是把所有可能的状态(子问题)用一个数据结构(通常是整数)统一表示,再用map把每个状态和对应结果关联起来,这样每次求解子问题时先find一下,如果map里面已经有该状态的解就不用再求了:同样每次求解完一个状态的解后也要将其放入map中保存 状态…
In the "100 game," two players take turns adding, to a running total, any integer from 1..10. The player who first causes the running total to reach or exceed 100 wins. What if we change the game so that players cannot re-use integers? For examp…
我能赢吗 在 "100 game" 这个游戏中,两名玩家轮流选择从 1 到 10 的任意整数,累计整数和,先使得累计整数和达到 100 的玩家,即为胜者. 如果我们将游戏规则改为 "玩家不能重复使用整数" 呢? 例如,两个玩家可以轮流从公共整数池中抽取从 1 到 15 的整数(不放回),直到累计整数和 >= 100. 给定一个整数 maxChoosableInteger (整数池中可选择的最大数)和另一个整数 desiredTotal(累计和),判断先出手的玩…
In the "100 game," two players take turns adding, to a running total, any integer from 1..10. The player who first causes the running total to reach or exceed 100 wins. What if we change the game so that players cannot re-use integers? For examp…
原题链接 两个人依次从1~maxNum中选取数字(不可重复选取同一个),累和.当一方选取数字累和后结果大于等于给定的目标数字,则此人胜利. 题目给一个maxNum和targetNum,要求判断先手能否胜利. 思路: 首先判断两种特殊条件: 可选最大值大于等于目标值,直接返回true. 其中一个人可选的最大值小于目标值,直接返回false. 具体再看题目,题目给出maxNum不大于20,则可状态压缩为一个int(32位)来保存每个数字是否被使用过(题解中利用1-32位进行存储). 利用一个map存…
You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip twoconsecutive "++" into "--". The game ends when a person can no longer…
You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove th…
最近闲来无事刷LeetCode,发现这道题的Accept Rate还是挺高的,尝试着做了一下,结果悲剧了,把过程写下来,希望能长点记性.该题的描述翻译成中文如下: 你正在和你的朋友玩尼姆游戏(Nim Game): 桌子上有一堆石块,你和你的朋友轮流去拿这些石块,每次只能拿1块.2块或者3块.在石块被拿光前,最后一次拿到石块的人获胜.你将首先去拿这些石块. 你和你的朋友都非常聪明,并且拥有应对该游戏的最佳策略.写一个函数来决定在给定石块数量的情况下,你是否能够获胜.比如:如果桌子上有4块石块,那么…
You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove th…
Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the…
一天一道LeetCode 从今天开始,调整规律,不按顺序做,从easy开始! 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to…
请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…
You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip two consecutive "++" into "--". The game ends when a person can no longer…
摘要: Nim Game.WordPattern.Move zeros.First Bad version.Ugly Number五个算法的python实现. 一个月多没更新,大概是因为状态一直不太好吧,有几次打开却不知从何写起.总结一下这一个月多:看了几个算法:接触了hadoop虽然还不算会:会用linux:看了HTML,JS:拿了两个省奖,其中一个真是一直的梦想:加入了一个团队也算是离自己的梦想更近一步:去过自己喜欢的地方:吃吃吃玩玩玩:做了好几件自己喜欢的事:帮到了挺多人:此刻却突然纠结于…
最近闲来无事刷LeetCode,发现这道题的Accept Rate还是挺高的,尝试着做了一下,结果悲剧了,把过程写下来,希望能长点记性.该题的描述翻译成中文如下: 你正在和你的朋友玩尼姆游戏(Nim Game): 桌子上有一堆石块,你和你的朋友轮流去拿这些石块,每次只能拿1块.2块或者3块.在石块被拿光前,最后一次拿到石块的人获胜.你将首先去拿这些石块. 你和你的朋友都非常聪明,并且拥有应对该游戏的最佳策略.写一个函数来决定在给定石块数量的情况下,你是否能够获胜.比如:如果桌子上有4块石块,那么…
Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the…
源代码地址:https://github.com/hopebo/hopelee 语言:C++ 301. Remove Invalid Parentheses Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other tha…
源代码地址:https://github.com/hopebo/hopelee 语言:C++ 24.Swap Nodes in Pairs Given a linked list, swap every two adjacent nodes and return its head. For example,Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should u…
You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip two consecutive "++" into "--". The game ends when a person can no longer…
Design a Tic-tac-toe game that is played between two players on a n x n grid. You may assume the following rules: A move is guaranteed to be valid and is placed on an empty block.Once a winning condition is reached, no more moves is allowed.A player…
914. Flip Game https://www.cnblogs.com/grandyang/p/5224896.html 从前到后遍历,遇到连续两个'+',就将两个加号变成'-'组成新的字符串加入到结果中. class Solution { public: vector<string> generatePossibleNextMoves(string &s) { // write your code here vector<string> result; ;i <…
Contest 91 (2018年10月24日,周三) 链接:https://leetcode.com/contest/weekly-contest-91/ 模拟比赛情况记录:第一题柠檬摊的那题6分钟AC,然后是第二题树的距离K的结点那题比较久,大概写了30分钟,第三题翻转矩阵那题第一次提交错误了,列的优化方法思路错了,WA.后来比赛时间到了才改过来.最后一题最短子数组的和比K大的这题不会做. [860]Lemonade Change   (第一题) 一个柠檬摊,有一队人排队要买柠檬,一个5刀,…