# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 42: Trapping Rain Waterhttps://oj.leetcode.com/problems/trapping-rain-water/ Given n non-negative integers representing an elevation map where the width of each bar is 1,compute how much wa…
leetcode - 42. Trapping Rain Water - Hard descrition Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1],…
leetcode#42 Trapping rain water 这道题十分有意思,可以用很多方法做出来,每种方法的思想都值得让人细细体会. 42. Trapping Rain WaterGiven n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For ex…
LeetCode 42. Trapping Rain Water Python解法 解题思路: 本思路需找到最高点左右遍历,时间复杂度O(nlogn),以下为向左遍历的过程. 将每一个点的高度和索引存成一个元组 (val, idx) 找到最高的点(可能有多个,任取一个),记为 (now_val, now_idx). 向左找第一个val不大于now_val的点(left_val, left_idx). 以left_val作为水平面,用height[left_val+1, now_val-1]中每一…
42. Trapping Rain Water Problem's Link ---------------------------------------------------------------------------- Mean: 在坐标上给你一些竖直放置的条形积木,问你这个积木能够容纳多少液体. analyse: 首先找出最高的积木,然后从前往后一直扫到最高积木,从后往前一直扫到最高积木,两部分体积相加即可. Time complexity: O(N) view code ;  …
11. Container With Most Water https://www.cnblogs.com/grandyang/p/4455109.html 用双指针向中间滑动,较小的高度就作为当前情况的高度,然后循环找容量的最大值. 不管两个指针中间有多少高度的柱子,只管两头,因为两头的才决定最大容量. class Solution { public: int maxArea(vector<int>& height) { if(height.empty()) ; ; ,end = h…
Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note: All numbers (including target) will be posi…
Write a program to solve a Sudoku puzzle by filling the empty cells. Empty cells are indicated by the character '.'. You may assume that there will be only one unique solution. A sudoku puzzle... ...and its solution numbers marked in red. 题意分析: 本题是要解…
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 →…
一.题目说明 题目是42. Trapping Rain Water,翻译起来就是"接雨水".给n个非负正数代表高度,每个正数宽度为1,让计算能多少雨水.题目难度是Hard 二.我的解法 这个题目是找"坑",然后计算里面可以存的"雨".总共提交了5次,前面几次都是边界错误. 代码如下: #include<iostream> #include<vector> using namespace std; class Solutio…