题目链接:http://poj.org/problem?id=1273 Time Limit: 1000MS Memory Limit: 10000K Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by water for awhile and takes…
Drainage Ditches Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13064    Accepted Submission(s): 6196 Problem Description Every time it rains on Farmer John's fields, a pond forms over Bessie's…
题目链接: Drainage Ditches Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 67475   Accepted: 26075 Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is cover…
                                                                                        Drainage Ditches   Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by water f…
题目链接:http://poj.org/problem?id=1273 Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by water for awhile and takes quite a long time to regrow. Thus, Farmer John has…
Drainage DitchesHal Burch Time Limit 1000 ms Memory Limit 65536 kb description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by water for awhile and takes quite a…
最大流的第一道题,刚开始学这玩意儿,感觉好难啊!哎····· 希望慢慢地能够理解一点吧! #include<stdio.h> #include<string.h> #include<queue> using namespace std; #define inf 1000000 #define min(a,b) a<b?a:b int map[210][210],pre[210],maxf[210]; int n,m; int bfs()//搜索,截止找不到增广路…
题目网址:http://acm.hdu.edu.cn/showproblem.php?pid=1532 思路: 网络流最大流的入门题,直接套模板即可~ 注意坑点是:有重边!!读数据的时候要用“+=”替换“=”. 对网络流不熟悉的,给一篇讲解:http://www.cnblogs.com/ZJUT-jiangnan/p/3632525.html. ✧(≖ ◡ ≖✿)我是看这篇博客才入门的. 代码: #include <cstdio> #include <cstring> #inclu…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1532 题目大意: 给出有向图以及边的最大容量,求从1到n的最大流 思路: 传送门:最大流的增广路算法 直接套用模板,用水流来理解网络流 #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<vector> #include<queu…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1532 感觉题意不清楚,不知道是不是个人英语水平问题.本来还以为需要维护入度和出度来找源点和汇点呢,看讨论才知道1就是起点,m就是汇点..好想把代码写的工程化一点. #include <stdio.h> #include <string.h> #include <queue> #include <algorithm> using namespace std; c…