1095 Cars on Campus (30 分) Zhejiang University has 8 campuses and a lot of gates. From each gate we can collect the in/out times and the plate numbers of the cars crossing the gate. Now with all the information available, you are supposed to tell, at…
题意: 输入一个正整数N(<=30),接着输入两行N个正整数第一行为先序遍历,第二行为后续遍历.输出是否可以构造一棵唯一的二叉树并输出其中一颗二叉树的中序遍历. trick: 输出完毕中序遍历后须换行,否则所有测试点格式错误. #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ],post[]; map<int,int>mp; int flag; vector<int>…
1119 Pre- and Post-order Traversals (30 分) Suppose that all the keys in a binary tree are distinct positive integers. A unique binary tree can be determined by a given pair of postorder and inorder traversal sequences, or preorder and inorder travers…
1135 Is It A Red-Black Tree (30 分) There is a kind of balanced binary search tree named red-black tree in the data structure. It has the following 5 properties: (1) Every node is either red or black. (2) The root is black. (3) Every leaf (NULL) is bl…
Suppose that all the keys in a binary tree are distinct positive integers. A unique binary tree can be determined by a given pair of postorder and inorder traversal sequences. And it is a simple standard routine to print the numbers in level-order. H…
喊山(30 分) 喊山,是人双手围在嘴边成喇叭状,对着远方高山发出“喂—喂喂—喂喂喂……”的呼唤.呼唤声通过空气的传递,回荡于深谷之间,传送到人们耳中,发出约定俗成的“讯号”,达到声讯传递交流的目的.原来它是彝族先民用来求援呼救的“讯号”,慢慢地人们在生活实践中发现了它的实用价值,便把它作为一种交流工具世代传袭使用.(图文摘自:http://news.xrxxw.com/newsshow-8018.html) 一个山头呼喊的声音可以被临近的山头同时听到.题目假设每个山头最多有两个能听到它的临近山…
1064 Complete Binary Search Tree (30 分)   A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a…
1053 Path of Equal Weight (30 分)   Given a non-empty tree with root R, and with weight W​i​​ assigned to each tree node T​i​​. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf…
1034 Head of a Gang (30 分)   One way that the police finds the head of a gang is to check people's phone calls. If there is a phone call between A and B, we say that A and B is related. The weight of a relation is defined to be the total time length…
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example:Given binary tree {3,9,20,#,#,15,7}, / \ / \ return its level order traversal as: [ [], [,], [,] ] 题解:二叉树的层次遍历,用队列实现.重点在…
Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root). For example:Given binary tree {3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its bottom-up level order tr…
1126 Eulerian Path (25 分) In graph theory, an Eulerian path is a path in a graph which visits every edge exactly once. Similarly, an Eulerian circuit is an Eulerian path which starts and ends on the same vertex. They were first discussed by Leonhard…
1114 Family Property (25 分) This time, you are supposed to help us collect the data for family-owned property. Given each person's family members, and the estate(房产)info under his/her own name, we need to know the size of each family, and the average…
1112 Stucked Keyboard (20 分) On a broken keyboard, some of the keys are always stucked. So when you type some sentences, the characters corresponding to those keys will appear repeatedly on screen for k times. Now given a resulting string on screen,…
1101 Quick Sort (25 分) There is a classical process named partition in the famous quick sort algorithm. In this process we typically choose one element as the pivot. Then the elements less than the pivot are moved to its left and those larger than th…
1108 Finding Average (20 分) The basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A legal input is a real number in [−1000,1000…
1111 Online Map (30 分) Input our current position and a destination, an online map can recommend several paths. Now your job is to recommend two paths to your user: one is the shortest, and the other is the fastest. It is guaranteed that a path exist…
1038 Recover the Smallest Number (30 分)   Given a collection of number segments, you are supposed to recover the smallest number from them. For example, given { 32, 321, 3214, 0229, 87 }, we can recover many numbers such like 32-321-3214-0229-87 or 0…
思路 设t = A + B,将每一次t % d的结果保存在int类型的数组s中 然后将t / d,直到 t 等于 0为止 此时s中保存的就是 t 在 D 进制下每一位的结果的倒序 最后倒序输出s数组 #include <iostream> using namespace std; int main() { int a, b, d; cin >> a >> b >> d; int t = a + b; if (t == 0) { cout << 0…
Suppose that all the keys in a binary tree are distinct positive integers. A unique binary tree can be determined by a given pair of postorder and inorder traversal sequences. And it is a simple standard routine to print the numbers in level-order. H…
One way that the police finds the head of a gang is to check people's phone calls. If there is a phone call between A and B, we say that A and B is related. The weight of a relation is defined to be the total time length of all the phone calls made b…
题外话:考试的时候花了一个小时做了27分,由于Siblings这个单词不知道意思,所以剩下的3分就没去纠结了,后来发现单词是兄弟的意思,气哭~~ 这道题的麻烦之处在于如何从一个字符串中去找数字.先首先我们需要整行读取(包括空格),这个我自己写另一个函数,挺好用的: string mygets() { ]; fgets(str,sizeof(str),stdin); int len = strlen(str); ]==] = '\0'; return str; } 用的时候只要 string st…
题意: 输入四个正整数C,N,S,M(c<=100,n<=500),分别表示每个自行车站的最大容量,车站个数,此次行动的终点站以及接下来的M行输入即通路.接下来输入一行N个正整数表示每个自行车站初始拥有的自行车数量,接下来输入M行每行包含三个正整数分别表示一条双向边的端点以及这条路的长度.求去往终点车站一次所经历的最短路,多条最短路则优先少带出车辆,次优先少带回车辆.(路上经过站点时需要把该站点的车辆变为最大容量的一半) AAAAAccepted code: #include<bits/…
题面: 输入四个正整数N,M,K,Q(N<=20,M<=10,K,Q<=1000),N为银行窗口数量,M为黄线内最大人数,K为需要服务的人数,Q为查询次数.输入K个正整数,分别代表每位顾客需要被服务的时间,Q次查询每次查询一位顾客被服务完离开银行的时间.如果他在五点以前(不包括五点)没有开始被服务,输出“Sorry”. trick: 在五点以前(不包括五点)没有开始被服务,输出“Sorry”,而不是被服务完时间在五点以后(以题面为准). AAAAAccepted code: #inclu…
题目分析: 可能是我的理解能力比较差,在读题的时候一直以为所有的切片是可以排列组合的,并不是按照输入顺序就定死的,那么这题就变得十分的复杂啦~~~~~,查看的题解之后发现所有的切片并没有所谓的自由组合的情况,而是类似与一片一片从下往上叠加在一起,形成一个三维的空间,那我们需要做的就是将所有的像素以三维数组的形式存储,然后bfs所有像素为1的点,只要相连的6个方向中有1则继续bfs,每次搜索过的1像素点都清零,避免重复搜索,在bfs的过程中统计相连的1的个数,每次bfs结束时比较sum和阈值的大小…
题意:输入两个正整数N和K(N<=1e4,K<=8e4),接着输入N行数据每行包括三个字符串表示车牌号,当前时间,进入或离开的状态.接着输入K次询问,输出当下停留在学校里的车辆数量.最后一行输出总计停留时间最长的车牌号(字典序升序输出)和停留总时. AAAAAccepted code: //因为一天只有86400秒,所以可以用一个car数组在统计车辆停留时间时在进入时间+1,离开时间-1.再用一个sum数组扫一遍,sum[i]=sum[i-1]+car[i],即可表示当下时间有多少辆车还在停留…
题意: 输入两个正整数N和L(N<=1000,L<=6),接着输入N行数据每行包括它关注人数(<=100)和关注的人的序号,接着输入一行包含一个正整数K和K个序号.输出每次询问的人发出消息经过至多L层转发最多有多少人转发. trick: 逻辑搞错的程序也能得到25或28分... AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ][]; ve…
题意: 输入两个正整数N和M(N<=10000,M<=10000),接着输入N个正整数.输出最小的序列满足序列和为M. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; ]; ][]; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int n,m…
题意: 输入一个正整数N(<=200),代表颜色总数,接下来输入一个正整数M(<=200),代表喜爱的颜色数量,接着输入M个正整数表示喜爱颜色的编号(同一颜色不会出现两次),接下来输入一个正整数L(<=10000),代表条带的长度,接着输入L个正整数表示条带上的颜色的编号.输出以喜爱颜色顺序排列的最长子串长度(不必每种颜色都有,只保证相对位置相同,同种颜色可连续). AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<b…
大家好,我是 程序员小熊 ,来自 大厂 的程序猿.相信绝大部分程序猿都有一个进大厂的梦想,但相较于以前,目前大厂的面试,只要是研发相关岗位,算法题基本少不了,所以现在很多人都会去刷 Leetcode 来保持手感,但有不少人反馈刷题效率很低,今天笔者抽空整理了 三份 分别来自 谷歌的高畅.前阿里的霜神和灵魂机器 的刷题手册,以供大家参考,希望对大家无有所帮助. 一. A LeetCode Grinding Guide (C++ Version) 作者:谷歌的高畅 背景:作者在美国卡内基梅隆大学攻读…