Given two binary strings, return their sum (also a binary string). For example,a ="11"b ="1"Return"100". 题意:将两个以字符串形式保存的二进制数进行相加. 思路:其实不管是以数组.字符串形式,加或者乘(multiply strings),一般的思路都是从后往前计算,用一个中间变量保存相加或者相乘的结果(加法是一个变量int 或string就行,…

Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 思路:二进制加法,比較简单.代码例如以下: public class Solution { public String addBinary(String a, String b) { int len = Math.max(a.l…

Given two binary strings, return their sum (also a binary string).The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&qu…

Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…

Leetcode 67:Add Binary(二进制求和) (python.java) Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. 给定两个二进制字符串,返回他们的和(用二进制表示). 输入为非空字符串且只包含数字 1 和 0. Example 1: Input…

Add BinaryGiven two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". SOLUTION: 指针指到两个字符串的末尾,不断往前推进,用carry表示进位.用stringbuilder来记录结果. 使用insert(0, c)函数将加出的结果不断插入到STRINGBUILDER. pub…

［抄题］: 以字符串的形式给出两个非负整数 num1 和 num2,返回 num1和 num2 的和. 比如一个50位+一个100位. 给定 num1 = "123",num2 = "45" 返回 "168" [暴力解法]: 时间分析: 空间分析: ［思维问题］: ［一句话思路］: ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: sum求和或者循环退出的条件都是i j &g…

题意:两个二进制数相加,大数加法的变形 大数加法流程: 1.倒置两个大数,这一步能使所有大数对齐 2.逐位相加,同时进位 3.倒置两个大数的和作为输出 class Solution { public: string addBinary(string a, string b) { if(a.size() < b.size()){ string t = a; a = b; b = t; } //该步使的能大数加小数,使其能加 reverse(a.begin(),a.end()); reverse(b…

Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 二进制数想加,并且保存在string中,要注意的是如何将string和int之间互相转换,并且每位相加时,会有进位的可能,会影响之后相加的结果.而且两个输入string的长度也可能会不同.这时我们需要新建一个string,它的长度是两…

Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 求数字字符串的二进制和. 同之前的数组代表数字,两个数组相加一样.仅仅只是进位变成了2.可能两个串的长度不一样,故逆转.从左到右加下去.最后再逆转. public static String addBinary(String a…