EC round 33 D. Credit Card 贪心】的更多相关文章

因为到为0的点,充钱的范围都是不确定的,我们维护一个满足条件的最小值以及满足条件的最大值. 当min>d时,代表已经满足条件限制了 当a[ i ] = 0 并且 max<0,代表需要充钱,充钱能够保证当前 minn=0  maxx = d 其他情况则对minn, maxx相应的增加和减少进行操作就可以了 #include<bits/stdc++.h> using namespace std; ; int a[maxx]; int main(){ int n,d; ; ; scanf…
Credit Card time limit per test2 seconds memory limit per test256 megabytes Recenlty Luba got a credit card and started to use it. Let's consider n consecutive days Luba uses the card. She starts with 0 money on her account. In the evening of i-th da…
codeforces 893D Credit Card 题目大意: 有一张信用卡可以使用,每天白天都可以去给卡充钱.到了晚上,进入银行对卡的操作时间,操作有三种: 1.\(a_i>0\) 银行会给卡充入\(a_i\)元 2.\(a_i<0\) 银行从卡中扣除\(a_i\)元 3.\(a_i=0\) 银行对你的卡进行评估,违背了规则就无权再使用此卡 规则1:卡内的余额不得超过\(d\)元 规则2:当\(a_i=0\)时,卡内的余额不能是负数 现在问为了维持信用的平衡,最少去银行几次.(去一次,充…
题意: Recenlty Luba有一张信用卡,一开始金额为0,每天早上可以充值任意数量的钱,但有限制,卡里的钱不能超过D.到了晚上,银行会对信用卡进行一次操作,操作有三种: 1.a[i]>0,.充入a[i]元. 2..a[i]<0 .扣除a[i]元. 3..a[i]=0 查询卡里的金额. 若干在a[i]=0时,卡里的钱为负的或者某天卡里的钱>D,则卡将被冻结,问Recenlty Luba至少需要去银行存多少次钱,使得在接下来的n天里,银行卡不会被冻结. 思路: 贪心,当a[i]=0时,…
这题非常好!!! 主席树版本 很简单的题目,给一个按照指定节点的树,树上有点权,你需要回答给定节点的子树中,和其距离不超过k的节点中,权值最小的. 肯定首先一想,按照dfs序列建树,然后按照深度为下标,建立主席树,那么我们通过主席树相间得到区间状态,但是很不幸,区间最值不能通过减去历史版本的主席树得到. 考虑照深度建立主席树,按照dfs下标建立,貌似可以耶!!! 我们直接查询当前节点往下k深度的主席树,它保存的就是从深度为1-到深度为deep[p]+k深度的所有节点的dfs序对应的点权值 我们查…
D. Credit Card time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Recenlty Luba got a credit card and started to use it. Let's consider n consecutive days Luba uses the card. She starts with …
D. Credit Card Recenlty Luba got a credit card and started to use it. Let's consider n consecutive days Luba uses the card. She starts with 0 money on her account. In the evening of i-th day a transaction ai occurs. If ai > 0, then ai bourles are dep…
# Who = Penalty * A B C D E F 479 arkethos 4 247   + 00:08 + 00:19 +1 00:59 +2 01:41     479  ne-leonardinkret 4 247   + 00:04 -1 +1 00:27 +2 01:47 + 00:49   481 MeePwn# 4 248   + 00:14 + 00:21 + 00:54 +3 01:39     482  shreypandey 4 251   + 00:06 +…
[cf contest 893(edu round 33)] F - Subtree Minimum Query time limit per test 6 seconds memory limit per test 512 megabytes input standard input output standard output You are given a rooted tree consisting of n vertices. Each vertex has a number writ…
https://mapr.com/blog/real-time-credit-card-fraud-detection-apache-spark-and-event-streaming/ Editor's Note: Have questions about the topics discussed in this post? Search for answers and post questions in the Converge Community. In this post we are…
After the fourth season Sherlock and Moriary have realized the whole foolishness of the battle between them and decided to continue their competitions in peaceful game of Credit Cards. Rules of this game are simple: each player bring his favourite n-…
http://forum.chasedream.com/thread-766972-1-1.html 本人2010年 8月F1 二度来美,现在credit score 在724-728之间浮动,最高的时候也就730,属于good range, 大于746的才算excellent score.两年之内从没有信用记录到Good,觉得还算不错,现在把自己如何build credit history和一些心得与大家分享.希望对大家有帮助. 信用记录在北美的重要性自然不必多说.我的启蒙是校内/renren…
题目链接   Codeforces Educational Round 33 Problem A 按照题目模拟,中间发现不对就直接输出NO. #include <bits/stdc++.h> using namespace std; #define rep(i, a, b) for (int i(a); i <= (b); ++i) #define dec(i, a, b) for (int i(a); i >= (b); --i) #define MP make_pair #de…
因为国外盗刷严重,于是得开启验证. 首先可以去 https://developer.cardinalcommerce.com/try-it-now.shtml.这上面有测试账号,截图如下:…
We will use 'HostListener' and 'HostBinding' to accomplish the task. The HTML: <label> Credit Card Number <input name="credit-card" type="text" credit-card placeholder="Enter your 16-digit card number"> </label…
This page includes a password or credit card input in a non-secure context. A warning has been added to the URL bar. For more information, see https://goo.gl/zmWq3m. 从网上找到的解决方案: 1. 有http该为https,因为页面里面有input type是password,谷歌浏览器建议升级https传输密码 2.将passwro…
[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 每次遇到0的时候,看看当前累计的delta是多少. 如果大于0,则temp = d-delta; 小于0,取temp2 = min(d-max{delta}(这里max指之前一段0和0之间的区域),temp); 然后delta显然可以直接加上temp2,可以保证在0和0之间不会超过d. 然后看看delta是不是大于等于0了. 是的话,temp = delta,否则delta=inf,ans++; 然后不论如何delta都直接变成…
C. Rumor time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Vova promised himself that he would never play computer games... But recently Firestorm — a well-known game developing company — pu…
  [题目] 你的信用卡目前欠M元,每月的汇率是R,每月的利息要四舍五入为小数点后两位,你每月还B元,问多少月能还清. 输入 先是T代表测试数据组数 接下来T行,每行有三个实数,R,M,B每个实数小数点后有两位 输出 每组测试数据输出一行,还清债务的最小月数,如果超过1200月都不能还清,输出“impossible” [吐槽] 这道题过的好不容易,首先是读题,如果不了解那些银行业的词汇真读不懂题 比如interesting(利息),the outstanding balance(未付清的余额),…
D. Queue time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Little girl Susie went shopping with her mom and she wondered how to improve service quality. There are n people in the queue. For e…
C. Load Balancing 题目连接: http://www.codeforces.com/contest/609/problem/C Description In the school computer room there are n servers which are responsible for processing several computing tasks. You know the number of scheduled tasks for each server:…
题目链接: http://codeforces.com/problemset/problem/777/B 题目大意: A, B玩游戏,每人一串数字,数字不大于1000,要求每人从第一位开始报出数字,并且比较,如果等于则没事,A>B则B被打一下,反之A被打一下,A很老实不会耍计谋,老老实实从第一个开始报,但是B很狡猾,会改变数字的顺序.问2个次数,一个是B最小被打的次数,二是A最多被打的次数. 思路: 贪心,模拟一下就行了.这里用到了cmp的技巧,直接用字符比较,这样就省去了转换为字符串的步骤.…
题目链接 题意:给你两个数x,yx,yx,y,让你构造一些长为yyy的数列,让这个数列的累乘为xxx,输出方案数. 思路:考虑对xxx进行质因数分解,设某个质因子PiP_iPi​的的幂为kkk,则这个质因子的贡献就相当于把kkk个PiP_iPi​放到yyy个盒子中,且盒子可能为空,方案为C(k+y−1,y)C(k+y-1,y)C(k+y−1,y),然后每个质因子的方案乘在一起即可.最后,因为负号也会出现,但xxx为正,所以就是在yyy个位置上选偶数个位置放负号,方案为2y−12^{y-1}2y−…
https://codeforces.com/contest/1141/problem/F2 题意 一个大小为n的数组a[],问最多有多少个不相交的区间和相等 题解 离散化用值来做,贪心选择较前的区间 代码 #include<bits/stdc++.h> #define M 5000005 #define ll long long #define pb push_back using namespace std; struct N{int l,r;N(int l=0,int r=0):l(l)…
https://codeforces.com/contest/1136/problem/D 贪心 + 思维 题意 你面前有一个队列,加上你有n个人(n<=3e5),有m(m<=个交换法则,假如u在v相邻前面,那么u和v可以交换位置,问你是队列最后一个人的时候你最前可以换到前面哪里 题解 因为相邻才能换,所以最后一个换到前面一定是一步一步向前走,所以不存在还要向后走的情况 设最后一个为u,假设前面有一个能和u换位置的集合,那么需要将这些点尽量往后移动去接u 假设前面有一个不能和u换位置的集合S,…
A. Increasing Sequence 题目连接: http://www.codeforces.com/contest/11/problem/A Description A sequence a0, a1, ..., at - 1 is called increasing if ai - 1 < ai for each i: 0 < i < t. You are given a sequence b0, b1, ..., bn - 1 and a positive integer…
嘎嘎,今天被一些事耽误了,可是还是A了几个题目,这道题还不错 题目链接: 题意:两个人玩游戏,有N堆纸牌,纸牌上有数字,A每次仅仅能取N堆中的 当中一个的顶部的 纸牌,B仅仅能取N堆中的当中一个底部 的纸牌,A.B都想让自己取的和最大,问最后比分为多少 画了一下.假设某一堆里的 纸牌数量为偶数,发现事实上是两个人各分一半,由于假设对方想从这里拿走本来属于自己那半部分的 较大的牌,自己全然来得及阻止的, 接下来就是奇数了,奇数 事实上先手者就抢到了中间的一张牌.另外两半还是各自一半,所以 应该以每…
A.每个状态只有一种后续转移,判断每次转移是否都合法即可. #include <iostream> #include <cstdio> using namespace std; ], n; bool check(int x){ ] == x) return false; ], r = x, s = -a[]-x; ; i <= n; i++){ if(a[i] == s) return false; l = a[i]; r = s; s = -l-r; } return tr…
A. Table time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Simon has a rectangular table consisting of n rows and m columns. Simon numbered the rows of the table from top to bottom starting f…
C. Simple Strings 题目连接: http://www.codeforces.com/contest/665/problem/C Description zscoder loves simple strings! A string t is called simple if every pair of adjacent characters are distinct. For example ab, aba, zscoder are simple whereas aa, add a…