题目传送门 /* 题意:找出符合 A^B > max (A, B) 的组数: 位运算:异或的性质,1^1=0, 1^0=1, 0^1=1, 0^0=0:与的性质:1^1=1, 1^0=0, 0^1=0, 0^0=0: 假设A < B,一定要满足B的最高位对应A的值是0,这样才可能>B(即0^1=1): 然后比赛时假设A的极限是类似0111111的情况,最后假设有误: 题解是先把每个数最高位(1)的位置统计个数,1<<4 的意思是 000010000: 只要与为0,表示最高位p…

Team Formation Time Limit: 2 Seconds Memory Limit: 131072 KB For an upcoming programming contest, Edward, the headmaster of Marjar University, is forming a two-man team from N students of his university. Edward knows the skill level of each student.…

                                                B - Team Formation Description For an upcoming programming contest, Edward, the headmaster of Marjar University, is forming a two-man team from N students of his university. Edward knows the skill level…

Team Formation Time Limit: 3 Seconds      Memory Limit: 131072 KB For an upcoming programming contest, Edward, the headmaster of Marjar University, is forming a two-man team from N students of his university. Edward knows the skill level of each stud…

Description For an upcoming programming contest, Edward, the headmaster of Marjar University, is forming a two-man team from N students of his university. Edward knows the skill level of each student. He has found that if two students with skill leve…

For an upcoming programming contest, Edward, the headmaster of Marjar University, is forming a two-man team from N students of his university. Edward knows the skill level of each student. He has found that if two students with skill level A and B fo…

题意:给定N个数,求这N个数中满足A ⊕ B > max{A, B})的AB有多少对.(A,B是N中的某两个数) 分析: 1.异或,首先想到转化为二进制. eg:110011(A)和 1(B)--------A中从右数第三个数是0,若某个数B(eg:110,101,111,……)从左向右数第三个数为1,那么两个异或一定满足A ⊕ B > max{A, B}). 还有哪些数B能让A ⊕ B > max{A, B})呢? 根据上述,同理,从右数第四个为1的数B也符合要求. 很容易想到,将N个…

Attention 秋招接近尾声,我总结了 牛客.WanAndroid 上,有关笔试面经的帖子中出现的算法题,结合往年考题写了这一系列文章,所有文章均与 LeetCode 进行核对.测试.欢迎食用 本文将覆盖 「二进制」 + 「位运算」 和 Lru 方面的面试算法题,文中我将给出: 面试中的题目 解题的思路 特定问题的技巧和注意事项 考察的知识点及其概念 详细的代码和解析 开始之前,我们先看下会有哪些重点案例: 为了方便大家跟进学习,我在 GitHub 建立了一个仓库 仓库地址:超级干货!精心归…

Team Formation Time Limit: 3000MS   Memory Limit: 131072KB   64bit IO Format: %lld & %llu Submit Status Description For an upcoming programming contest, Edward, the headmaster of Marjar University, is forming a two-man team from N students of his uni…

题意: 出自刘汝佳算法竞赛入门经典第四章. 考虑下面的01串序列: 0, 00, 01, 10, 000, 001, 010, 011, 100, 101, 110, 0000, 0001, …, 1101, 1110, 00000, … 首先是长度为1的串,然后是长度为2的串,依此类推.如果看成二进制,相同长度的后 一个串等于前一个串加1.注意上述序列中不存在全为1的串. 你的任务是编写一个解码程序.首先输入一个编码头(例如AB#TANCnrtXc),则上述 序列的每个串依次对应编码头的每个字…