[CF843D]Dynamic Shortest Path 题目大意: 给定一个带权有向图,包含\(n(n\le10^5)\)个点和\(m(m\le10^5)\)条边.共\(q(q\le2000)\)次操作,操作包含以下两种: \(1\:v\)--查询从\(1\)到\(v\)的最短路. \(2\:c\:l_1\:l_2\:\ldots\:l_c\)--将边\(l_1,l_2,\ldots,l_c\)增加\(1\)的权值. 思路: 首先使用Dijkstra算法求出原图的单源最短路径\(dis[i]…

考试的T3,拿暴力+剪枝卡过去了. 没想到 CF 上也能过 ~ code: #include <bits/stdc++.h> #define N 100004 #define LL long long #define inf 1000000000000000 using namespace std; int go[N]; namespace IO { char *p1, *p2, buf[100000]; #define nc() (p1 == p2 && (p2 = (p1…

大意: n结点有向有权图, m个操作, 增加若干边的权重或询问源点为1的单源最短路. 本题一个特殊点在于每次只增加边权, 并且边权增加值很小, 询问量也很小. 我们可以用johnson的思想, 转化为差值最短路, 这样边权就在n-1以内, 可以直接暴力跑桶优化dijkstra. #include <iostream> #include <algorithm> #include <cstdio> #include <math.h> #include <s…

题面: 传送门 思路: 真·动态最短路 但是因为每次只加1 所以可以每一次修改操作的时候使用距离分层的bfs,在O(n)的时间内解决修改 这里要用到一个小技巧: 把每条边(u,v)的边权表示为dis[u]+w(u,v)-dis[v],这样边权实际上变成了“这条边离作为最短路的一份子还差了多少” 然后在用这个边权的新图里面更新1到每个点的最短路,再用原来的dis加上这个值,就是当前的最短路了 实际上是把绝对数值转化为了“离最优解的距离”,以此解题 Code: #include<iostream>…

A method is presented for finding a shortest path from a starting place to a destination place in a traffic network including one or more turn restrictions, one or more U-turns and one or more P-turns using a Dijkstra algorithm. The method as sets a…

An undirected, connected graph of N nodes (labeled 0, 1, 2, ..., N-1) is given as graph. graph.length = N, and j != i is in the list graph[i] exactly once, if and only if nodes i and j are connected. Return the length of the shortest path that visits…

00 前言 各位小伙伴大家好,相信大家已经看过前面column generation求解vehicle routing problems的过程详解.该问题中,子问题主要是找到一条reduced cost最小的合法路径,然后加入到Master Problem中.其实,子问题也是一个著名的NP-Hard问题,今天我们就来介绍一下. 01 ESPPRC 考虑图1.1中描述的网络. 除了每条边的成本c_ij之外,还存在经过边(i,j)的所消耗的资源t_ij,比如时间. 我们的目标是找到从开始节点到结束节…

The Shortest Path Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2440    Accepted Submission(s): 784 Problem Description There are N cities in the country. Each city is represent by a matrix si…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1760 Given a weighted directed graph, we define the shortest path as the path who has the smallest length among all the path connecting the source vertex to the target vertex. And if two…

Problem Description This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que cambiar un poco el algoritmo. If you do not understand a word of this paragraph, just move on.The Nya graph is an un…

题目链接:pid=3631" style="font-size:18px">http://acm.hdu.edu.cn/showproblem.php?pid=3631 Shortest Path Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3962    Accepted Submission(s): 9…

Shortest Path  Accepts: 40  Submissions: 610  Time Limit: 4000/2000 MS (Java/Others)  Memory Limit: 131072/131072 K (Java/Others) Problem Description There is a path graph G=(V,E)G=(V,E) with nn vertices. Vertices are numbered from 11 to nn and there…

Shortest Path Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1494    Accepted Submission(s): 476 Problem Description There is a path graph G=(V,E) with n vertices. Vertices are numbered from…

Description This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que cambiar un poco el algoritmo. If you do not understand a word of this paragraph, just move on. The Nya graph is an undirecte…

How Many Shortest Path 标签: 网络流 描述 Given a weighted directed graph, we define the shortest path as the path who has the smallest length among all the path connecting the source vertex to the target vertex. And if two path is said to be non-overlapping…

An undirected, connected graph of N nodes (labeled 0, 1, 2, ..., N-1) is given as graph. graph.length = N, and j != i is in the list graph[i] exactly once, if and only if nodes i and j are connected. Return the length of the shortest path that visits…

1.概述 路由协议OSPF全称为Open Shortest Path First,也就开放的最短路径优先协议,因为OSPF是由IETF开发的,所以所有厂商都可以用. OSPF的流量使用IP协议号. OSPF对网络没有跳数限制,支持 Classless Interdomain Routing (CIDR)和Variable-Length Subnet Masks (VLSMs),没有自动汇总功能,可以手动汇总. OSPF并不会周期性更新路由表,而采用增量更新,即只在路由有变化时,才会发送更新,并且…

Given a knight in a chessboard (a binary matrix with 0 as empty and 1 as barrier) with a source position, find the shortest path to a destinationposition, return the length of the route. Return -1 if knight can not reached. Notice source and destinat…

The Shortest Path in Nya Graph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 13445    Accepted Submission(s): 2856 Problem Description This is a very easy problem, your task is just calculate…

2018-10-06 22:04:38 问题描述: 问题求解: 本题要求是求遍历所有节点的最短路径,由于本题中是没有要求一个节点只能访问一次的,也就是说可以访问一个节点多次,但是如果表征两次节点状态呢?可以使用(curNode, VisitedNode)来进行表征,如果两次的已经访问的节点相同那么就没有必要再进行访问了,最终的状态就是所有节点都访问过了. 另外,由于起点对结果是有影响的,因此在最开始需要将所有的节点都压栈. public int shortestPathLength(int[][…

Shortest Path Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 627    Accepted Submission(s): 204 Problem Description There is a path graph G=(V,E) with n vertices. Vertices are numbered from 1…

The Shortest Path in Nya Graph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 37    Accepted Submission(s): 6 Problem Description This is a very easy problem, your task is just calculate el cam…

Shortest Path Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 1146 Accepted Submission(s): 358 Problem Description There is a path graph G=(V,E) with n vertices. Vertices are numbered from 1 to…

人老了就比较懒,故意挑了到看起来很和蔼的题目做,然后套个spfa和dinic的模板WA了5发,人老了,可能不适合这种刺激的竞技运动了…… 题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2760 Description Given a weighted directed graph, we define the shortest path as the path who has the smallest leng…

转自:Pavel's Blog Now let's say we want to find the LCA for nodes 4 and 9, we will need to traverse the whole tree to compare each node so that we can locate the nodes. Now considering that we start the traversal with the left branch (pre-order travers…

An undirected, connected graph of N nodes (labeled 0, 1, 2, ..., N-1) is given as graph. graph.length = N, and j != i is in the list graph[i] exactly once, if and only if nodes i and j are connected. Return the length of the shortest path that visits…

[CF938G]Shortest Path Queries(线段树分治,并查集,线性基) 题面 CF 洛谷 题解 吼题啊. 对于每个边,我们用一个\(map\)维护它出现的时间, 发现询问单点,边的出现时间是区间,所以线段树分治. 既然路径最小值就是异或最小值,并且可以不是简单路径, 不难让人想到\(WC2011\)那道最大\(Xor\)路径和. 用一样的套路,我们动态维护一棵生成树,碰到一个非树边, 就把这个环的异或和丢到线性基里面去,这样子直接查就好了. 动态维护生成树直接用并查集就好了,没…

(THIS BLOG WAS ORIGINALLY WRTITTEN IN CHINESE WITH LINK: http://www.cnblogs.com/waytofall/p/3732920.html) Foreword: Floyd-Warshall is a classical dynamical programming algorithm for deriving shortest paths between each pair of nodes on a graph. It ha…

A. Shortest path of the king time limit per test 1 second memory limit per test 64 megabytes input standard input output standard output The king is left alone on the chessboard. In spite of this loneliness, he doesn't lose heart, because he has busi…

Description Given a weighted directed graph, we define the shortest path as the path who has the smallest length among all the path connecting the source vertex to the target vertex. And if two path is said to be non-overlapping, it means that the tw…