▶ 三个与丑数相关的问题 ▶ 第 263题,判定一个数字是否是丑数,即其素因子是否仅由 2,3,5 构成. ● 常规消除判别,4 ms class Solution { public: bool isUgly(int num) { ) return false; ); num /= ); ); num /= ); ); num /= ); ; } }; ● 递归方法,6 ms class Solution { public: bool isUgly(int num) { ) return fal…

263. Ugly Number 注意:1.小于等于0都不属于丑数 2.while循环的判断不是num >= 0, 而是能被2 .3.5整除,即能被整除才去除这些数 class Solution { public: bool isUgly(int num) { ) return false; == ) num /= ; == ) num /= ; == ) num /= ; ? true : false; } }; 264. Ugly Number II 用一个数组去存第n个前面的所有整数,然后…

Write a program to find the nth super ugly number. Super ugly numbers are positive numbers whose all prime factors are in the given prime list primes of size k. Example: Input: n = 12, primes = [2,7,13,19] Output: 32 Explanation: [1,2,4,7,8,13,14,16,…

Write a program to find the nth super ugly number. Super ugly numbers are positive numbers whose all prime factors are in the given prime list primes of size k. For example, [1, 2, 4, 7, 8, 13, 14, 16, 19, 26, 28, 32] is the sequence of the first 12…

题目: Write a program to find the nth super ugly number. Super ugly numbers are positive numbers whose all prime factors are in the given prime list primes of size k. For example, [1, 2, 4, 7, 8, 13, 14, 16, 19, 26, 28, 32] is the sequence of the first…

丑数系列的题看这一道就可以了 /* 和ugly number2差不多,不过这次的质因子多了,所以用数组来表示质因子的target坐标 target坐标指的是这个质因子此次要乘的前任丑数是谁 */ public int nthSuperUglyNumber(int n, int[] primes) { //记录相乘坐标,存的是每个质因子对应相乘搭档在丑数数组中的下标 int[] target = new int[primes.length]; //动态规划数组 int[] dp = new int…

编写一段程序来寻找第 n 个超级丑数.超级丑数是指其所有质因数都在长度为k的质数列表primes中的正整数.例如,[1, 2, 4, 7, 8, 13, 14, 16, 19, 26, 28, 32],是给定长度为 4 的质数列表primes = [2, 7, 13, 19]的前 12 个超级丑数.注意:(1) 1是任何给定的primes的超级丑数.(2) 给定primes中的数字以升序排列.(3) 0 < k ≤ 100, 0 < n ≤ 106, 0 < primes[i] <…

题目如下: 解题思路:总结一下这么几点,一出一进,优先级队列排序,保证每次输出的都是当前的最小值.解法大致如图: 代码如下: #include<map> #include<queue> using namespace std; struct node { node(int k,int v) { key = k; val = v; } friend bool operator< (node n1, node n2) { return n1.val > n2.val; }…

Q: A: 用变量记录已经✖2.✖3.✖5的元素下标i2.i3.i5.表示截止到i2的元素都已经乘过2(结果添加到序列尾部的意思),i3.i5同理.这样每次可以循环可以O(1)时间找到下一个最小的丑数,时间O(N),空间O(N). class Solution { public: int nthUglyNumber(int n) { if(n<=0){ return 0; } int i2=0,i3=0,i5=0; vector<int> vec={1}; while(vec.size(…

Leetcode之动态规划(DP)专题-264. 丑数 II(Ugly Number II) 编写一个程序,找出第 n 个丑数. 丑数就是只包含质因数 2, 3, 5 的正整数. 示例: 输入: n = 10 输出: 12 解释: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12 是前 10 个丑数. 说明: 1 是丑数. n 不超过1690. dp含义: dp[i]表示第i-1个丑数. class Solution { public int nthUglyNumber(int n)…

一.Ugly Number Write a program to check whether a given number is an ugly number. Ugly numbers are positive numbers whose prime factors only include 2, 3, 5. For example, 6, 8 are ugly while 14 is not ugly since it includes another prime factor 7. Not…

Write a program to find the nth super ugly number. Super ugly numbers are positive numbers whose all prime factors are in the given prime list primes of sizek. For example, [1, 2, 4, 7, 8, 13, 14, 16, 19, 26, 28, 32] is the sequence of the first 12 s…

Write a program to find the nth super ugly number. Super ugly numbers are positive numbers whose all prime factors are in the given prime list primes of size k. For example, [1, 2, 4, 7, 8, 13, 14, 16, 19, 26, 28, 32] is the sequence of the first 12…

Write a program to find the nth super ugly number. Super ugly numbers are positive numbers whose all prime factors are in the given prime list primes of size k. For example, [1, 2, 4, 7, 8, 13, 14, 16, 19, 26, 28, 32] is the sequence of the first 12…

Super Ugly Number 最后WA没做出来. typedef long long int64; #define MAXBOUND 10000000 class Solution { public: int nthSuperUglyNumber(int n, vector<int>& primes) { bitset<MAXBOUND> bs; int64 bound = MAXBOUND; vector<int> v; bs.set(1); for (…

Write a program to find the nth super ugly number. Super ugly numbers are positive numbers whose all prime factors are in the given prime list primes of size k. Example: Input: n = 12, primes = [2,7,13,19] Output: 32 Explanation: [1,2,4,7,8,13,14,16,…

264. 丑数 II 题目描述 编写一个程序,找出第 n 个丑数. 丑数就是只包含质因数 2, 3, 5 的正整数. 示例: 输入: n = 10 输出: 12 解释: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12 是前 10 个丑数. 说明:   1. 1 是丑数. 2. n 不超过1690. 想法 三指针法.一部分是丑数数组,另一部分是权重2,3,5.下一个丑数,定义为丑数数组中的数乘以权重,所得的最小值. 那么,2该乘以谁?3该乘以谁?5该乘以谁? 其一,使用三个指针idx…

好久没切 leetcode 的题了,静下心来切了道,这道题比较有意思,和大家分享下. 我把它叫做 "不一样的猜数字游戏",我们先来看看传统的猜数字游戏,Guess Number Higher or Lower.题意非常的简单,给定一个数字 n,系统会随机从 1 到 n 中抽取一个数字,你需要写一个函数 guessNumber,它的作用是返回系统选择的数字,同时你还有一个外部的 API 可以调用,是为 guess 函数,它会将你猜的数字和系统选择的数字比较,是大了还是小了. 非常的简单,…

We are playing the Guess Game. The game is as follows: I pick a number from 1 to n. You have to guess which number I picked. Every time you guess wrong, I'll tell you whether the number I picked is higher or lower. However, when you guess a particula…

[LeetCode]375. Guess Number Higher or Lower II 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/guess-number-higher-or-lower-ii/description/ 题目描述: We are playing the Guess Game. The game is as f…

e are playing the Guess Game. The game is as follows: I pick a number from 1 to n. You have to guess which number I picked. Every time you guess wrong, I'll tell you whether the number I picked is higher or lower. However, when you guess a particular…

264. 丑数 II 编写一个程序,找出第 n 个丑数. 丑数就是只包含质因数 2, 3, 5 的正整数. 示例: 输入: n = 10 输出: 12 解释: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12 是前 10 个丑数. 说明: 1 是丑数. n 不超过1690. class Solution { public int nthUglyNumber(int n) { if (n <= 0) { return 0; } int[] result = new int[n]; re…

264. 丑数 II 题目链接 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/ugly-number-ii/ 著作权归领扣网络所有.商业转载请联系官方授权,非商业转载请注明出处. 题目描述 给你一个整数 n ,请你找出并返回第 n 个 丑数 . 丑数 就是只包含质因数 2.3 和/或 5 的正整数. 示例 1: 输入:n = 10 输出:12 解释:[1, 2, 3, 4, 5, 6, 8, 9, 10, 12] 是由前 10 个丑数组成…

题目 给你一个整数 n ,请你找出并返回第 n 个 丑数 . 丑数 就是只包含质因数 2.3 和/或 5 的正整数. 示例 1: 输入:n = 10 输出:12 解释:[1, 2, 3, 4, 5, 6, 8, 9, 10, 12] 是由前 10 个丑数组成的序列. 示例 2: 输入:n = 1 输出:1 解释:1 通常被视为丑数. 暴力法 求出int范围内所有的丑数,取第n个返回. public int nthUglyNumber(int n) { List<Integer> all=new…

用了优先队列,还是超时 class Solution { public: int nthSuperUglyNumber(int n, vector<int>& primes) { priority_queue<int,std::vector<int>,std::greater<int> > pq; pq.push(1); int i=1; int t; while(i<=n){ if(t == pq.top()) { pq.pop(); con…

eg 2,3,5 把第一个元素(2,1)放到最小堆,2表示乘积,1表示乘数   乘数     队列                          最小堆                   即将进行的操作 第一阶段 [1]   [2,3,5]                2                          (2,1)出堆,(3,1)入堆,生成新的乘数2,并且(2*2,2)入堆: 第二阶段 [1]   [3,5]                    3,4        …

We are playing the Guess Game. The game is as follows: I pick a number from 1 to n. You have to guess which number I picked. Every time you guess wrong, I'll tell you whether the number I picked is higher or lower. However, when you guess a particula…

136. Single Number 除了一个数字,其他数字都出现了两遍. 用亦或解决,亦或的特点:1.相同的数结果为0,不同的数结果为1 2.与自己亦或为0,与0亦或为原来的数 class Solution { public: int singleNumber(vector<int>& nums) { if(nums.empty()) ; ; ;i < nums.size();i++) res ^= nums[i]; return res; } }; 137. Single N…

Given a boolean 2D matrix, find the number of islands. Notice 0 is represented as the sea, 1 is represented as the island. If two 1 is adjacent, we consider them in the same island. We only consider up/down/left/right adjacent. Example Given graph: […

We are playing the Guess Game. The game is as follows: I pick a number from 1 to n. You have to guess which number I picked. Every time you guess wrong, I'll tell you whether the number I picked is higher or lower. However, when you guess a particula…