HDU 1573】的更多相关文章

CRT模板题 /** @Date : 2017-09-15 13:52:21 * @FileName: HDU 1573 CRT EXGCD.cpp * @Platform: Windows * @Author : Lweleth (SoungEarlf@gmail.com) * @Link : https://github.com/ * @Version : $Id$ */ #include <bits/stdc++.h> #define LL long long #define PII p…
HDU 1573 X问题 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4857    Accepted Submission(s): 1611 Problem Description 求在小于等于N的正整数中有多少个X满足:X mod a[0] = b[0], X mod a[1] = b[1], X mod a[2] = b[2],…
链接:pid=1573">http://acm.hdu.edu.cn/showproblem.php? pid=1573 题意:求在小于等于N的正整数中有多少个X满足:X mod a[0] = b[0], X mod a[1] = b[1], X mod a[2] = b[2], -, X mod a[i] = b[i], - (0 < a[i] <= 10). 思路:中国剩余定理的模板题(全部除数相互不互质版),假设找不到这种数或者最小的X大于N.输出零. 资料:http:/…
X问题 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2980    Accepted Submission(s): 942 Problem Description 求在小于等于N的正整数中有多少个X满足:X mod a[0] = b[0], X mod a[1] = b[1], X mod a[2] = b[2], …, X mod…
数论题,本想用中国剩余定理,可是取模的数之间不一定互质,用不了,看到网上有篇文章写得很好的:数论——中国剩余定理(互质与非互质),主要是采用合并方程的思想: 大致理解并参考他的代码后便去试试hdu上这道题,可还是wa了数遍. #include<cstdio> #define scd(x) scanf("%d",&x) #define sclld(x) scanf("%I64d",&x) #define prd(x) printf(&quo…
Problem Description 要求(A/B)%9973,但由于A很大,我们只给出n(n=A%9973)(我们给定的A必能被B整除,且gcd(B,9973)= 1). Input 数据的第一行是一个T,表示有T组数据. 每组数据有两个数n(0 <= n < 9973)和B(1<= B <= 10^9). Output 对应每组数据输出(A/B)%9973. Sample Input 2 1000 53 87 123456789 Sample Output 7922 6060…
X问题 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8365    Accepted Submission(s): 3037 Problem Description 求在小于等于N的正整数中有多少个X满足:X mod a[0] = b[0], X mod a[1] = b[1], X mod a[2] = b[2], …, X mod…
2891 -- Strange Way to Express Integers import java.math.BigInteger; import java.util.Scanner; public class Main { static final BigInteger ZERO = new BigInteger("0"); static final BigInteger ONE = new BigInteger("1"); static BigInteger…
X问题 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5221    Accepted Submission(s): 1761 Problem Description 求在小于等于N的正整数中有多少个X满足:X mod a[0] = b[0], X mod a[1] = b[1], X mod a[2] = b[2], …, X mod…
题目链接 题意 : 中文题不详述. 思路 : 中国剩余定理.求中国剩余定理中解的个数.看这里看这里 #include <stdio.h> #include <iostream> #include <math.h> using namespace std ; long long x,y ; long long N,M ; long long ext_gcd(long long a,long long b) { long long t,d ; ) { x = ; y = ;…