According to the Wikipedia's article: "The Game of Life, also known simply as Life, is a cellular automaton devised by the British mathematician John Horton Conway in 1970." Given a board with m by n cells, each cell has an initial state live (1…
According to the Wikipedia's article: "The Game of Life, also known simply as Life, is a cellular automaton devised by the British mathematician John Horton Conway in 1970." Given a board with m by n cells, each cell has an initial state live (1…
According to the Wikipedia's article: "The Game of Life, also known simply as Life, is a cellular automaton devised by the British mathematician John Horton Conway in 1970." Given a board with m by n cells, each cell has an initial state live (1…
<span style="font-family: Arial, Helvetica, sans-serif; background-color: rgb(255, 255, 255);">leetcode第188题,Best Time to Buy and Sell Stock IV题目如下:</span> https://leetcode.com/problems/best-time-to-buy-and-sell-stock-iv/ Say you hav…
题目:(据说是facebook的面试题哦) The count-and-say sequence is the sequence of integers beginning as follows:1, 11, 21, 1211, 111221, ... 1 is read off as "one 1" or 11.11 is read off as "two 1s" or 21.21 is read off as "one 2, then one 1&qu…
题目难度:Medium 题目: Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target. Note: The solution set must not contain duplicate quadrup…
题目: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. 翻译: 给定一组整数,两个数字的返回索引,它们的和会等于一个特定…
leetcode第三题: 题目: 给定一个字符串,找出不含有重复字符的最长子串的长度. 源码(使用java语言): class Solution { public int lengthOfLongestSubstring(String s) { int result = 0; int front = 0 ; int after = 0; char[] temp = s.toCharArray();//save the String to a chararray Map<Character,Int…
Dynamic Programming 实际上是[LeetCode] 系统刷题4_Binary Tree & Divide and Conquer的基础上,加上记忆化的过程.就是说,如果这个题目实际上是类似于Divide and conquer或者说是DFS,但是在计算过程中有很多重复计算同样的过程的话,那么就可以用Dynamic prgramming/记忆化搜索来完成.基本就是利用空间来简化时间复杂度的过程. 可以/很有可能使用Dynamic programming的条件,满足之一即可. 1.…
LeetCode 第 342 题(Power of Four) Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example: Given num = 16, return true. Given num = 5, return false. Follow up: Could you solve it without loops/recursion? 题目很简单,…
LeetCode 第 231 题 (Power of Two) Given an integer, write a function to determine if it is a power of two. 这个题目有个特别简单的解法.当然.可以独自想出这种方法可不简单.这样的方法可以作为一个知识点记住就好了. class Solution { public: bool isPowerOfTwo(int n) { if(n <= 0) return false; return !(n &…
