POJ Big Christmas Tree(最短的基础)】的更多相关文章

Big Christmas Tree 题目分析: 叫你构造一颗圣诞树,使得 (sum of weights of all descendant nodes) × (unit price of the edge)尽量的小.转换后就是求根节点到每一个节点的距离最短,也就是最短路. 生成树可能会超时.我没试过.然后,求解最短路要用优化的解法不然会超时.最后的答案就是:sum = w[1] * dist[1] + w[2] * dist[2] + ..... w[n] * dist[n].能够自己推推例…
POJ 3013 Big Christmas Tree(最短路Dijkstra+优先队列优化,SPFA) ACM 题目地址:POJ 3013 题意:  圣诞树是由n个节点和e个边构成的,点编号1-n.树根为编号1,选择一些边.使得全部节点构成一棵树.选择边的代价是(子孙的点的重量)×(这条边的价值). 求代价最小多少. 分析:  单看每一个点被计算过的代价,非常明显就是从根到节点的边的价值.所以这是个简单的单源最短路问题. 只是坑点还是非常多的. 点的数量高达5w个,用矩阵存不行.仅仅能用边存.…
http://poj.org/problem?id=3013 Big Christmas Tree Time Limit: 3000MS   Memory Limit: 131072K Total Submissions: 19009   Accepted: 4048 Description Christmas is coming to KCM city. Suby the loyal civilian in KCM city is preparing a big neat Christmas…
Big Christmas Tree Time Limit: 3000MS   Memory Limit: 131072K Total Submissions: 20974   Accepted: 4535 Description Christmas is coming to KCM city. Suby the loyal civilian in KCM city is preparing a big neat Christmas tree. The simple structure of t…
Big Christmas Tree 题意:图中每个节点和边都有权值,图中找出一颗树,树根为1使得 Σ(树中的节点到树根的距离)*(以该节点为子树的所有节点的权值之和) 结果最小: 分析:直接求出每个节点到树根的最短距离距离,之后乘上自身节点的权值求和即可: ps:注意特判v = 0:这时cnt = 1 > v; Djistra + priority_queue //Accepted 2804K 141MS #include <cstdio> #include <cstring&g…
Big Christmas Tree Time Limit: 3000MS   Memory Limit: 131072K Total Submissions: 23387   Accepted: 5063 Description Christmas is coming to KCM city. Suby the loyal civilian in KCM city is preparing a big neat Christmas tree. The simple structure of t…
Big Christmas Tree Time Limit: 3000MS   Memory Limit: 131072K Total Submissions: 25823   Accepted: 5577 Description Christmas is coming to KCM city. Suby the loyal civilian in KCM city is preparing a big neat Christmas tree. The simple structure of t…
POJ.3321 Apple Tree ( DFS序 线段树 单点更新 区间求和) 题意分析 卡卡屋前有一株苹果树,每年秋天,树上长了许多苹果.卡卡很喜欢苹果.树上有N个节点,卡卡给他们编号1到N,根的编号永远是1.每个节点上最多结一个苹果.卡卡想要了解某一个子树上一共结了多少苹果. 现在的问题是不断会有新的苹果长出来,卡卡也随时可能摘掉一个苹果吃掉.你能帮助卡卡吗? 前缀技能 边表存储树 DFS时间戳 线段树 首先利用边表将树存储下来,然后DFS打上时间戳.打上时间戳之后,我们就知道书上节点对…
id=10486" target="_blank" style="color:blue; text-decoration:none">POJ - 3321 Apple Tree Time Limit: 2000MS   Memory Limit: 65536KB   64bit IO Format: %I64d & %I64u Submit Status Description There is an apple tree outside o…
模板 意甲冠军:给你一个图,1始终根,每一方都有单价值,每个点都有权重新. 每个边缘的价格值 = sum(后继结点重)*单价方值. 最低价格要求树值,它构成了一棵树n-1条边的最小价值. 算法: 1.由于每一个边的价值都要乘以后来訪问的节点的权重.而走到后来訪问的点必经过这条边. 实际上总价值就是  到每一个点的最短路径*这个点的权重. 2.可是这个题 数据量真的太大了.50000个点,50000条边. 写普通的dij算法tle. 必须加优先队列优化- - 据说spfa也能过.可是spfa算法不…
题目传送门 题意:找一棵树使得造价最少,造价为每个点的子节点造价和*边的造价和 分析:最短路跑出1根节点到每个点的最短边权值,然后每个点的权值*最短边距和就是答案,注意INF开足够大,n<=1特判.Dijkstra 和 SPFA都行 代码: #include <cstdio> #include <iostream> #include <algorithm> #include <queue> #include <vector> #includ…
Apple Tree Time Limit: 2000MS   Memory Limit: 65536K       Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been carefully nurturing the big apple t…
Christmas Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 1967   Accepted: 613 Description Harry and Sally were playing games at Christmas Eve. They drew some Christmas trees on a paper: Then they took turns to cut a branch of a tre…
好抽象的树形DP......... Apple Tree Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 6411 Accepted: 2097 Description Wshxzt is a lovely girl. She likes apple very much. One day HX takes her to an apple tree. There are N nodes in the tree. Each nod…
Apple Tree Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 18623   Accepted: 5629 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been…
Apple Tree Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 25904   Accepted: 7682 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been…
http://poj.org/problem?id=3237 题意:树链剖分.操作有三种:改变一条边的边权,将 a 到 b 的每条边的边权都翻转(即 w[i] = -w[i]),询问 a 到 b 的最大边权. 思路:一开始没有用区间更新,每次翻转的时候都更新到叶子节点,居然也能过,后来看别人的发现也是可以区间更新的. 第一种:无区间更新水过 #include <cstdio> #include <algorithm> #include <iostream> #inclu…
题目连接 http://poj.org/problem?id=2367 Genealogical tree Description The system of Martians' blood relations is confusing enough. Actually, Martians bud when they want and where they want. They gather together in different groups, so that a Martian can…
题目:http://poj.org/problem?id=3321 动态更新某个元素,并且求和,显然是二叉索引树,但是节点的标号不连续,二叉索引树必须是连续的,所以需要转化成连续的,多叉树的形状已经建好,只要重新标号成连续的就行了. 感觉重新标号是这个题最难的地方,否则就是个纯水题了... 重新标号是看的别人的...用dfs遍历多叉树标号. #include <stdio.h> #include <stdlib.h> #include <string.h> ; ], n…
Tree   Description Give a tree with n vertices,each edge has a length(positive integer less than 1001). Define dist(u,v)=The min distance between node u and v. Give an integer k,for every pair (u,v) of vertices is called valid if and only if dist(u,v…
http://poj.org/problem?id=2486 典型的回溯题目:特别是状态方程用三维的来标记是否要走回路. 题意:一颗树,n个点(1-n),n-1条边,每个点上有一个权值,求从1出发,走V步,最多能遍历到的权值 思路: 树形dp,比较经典的一个树形dp.首先很容易就可以想到用dp[root][k]表示以root为根的子树中最多走k时所能获得的最多苹果数,接下去我们很习惯地会想到将k步在root的所有子结点中分配,也就是进行一次背包,就可以得出此时状态的最优解了,但是这里还有一个问题…
Tree Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 11570   Accepted: 3626 Description Give a tree with n vertices,each edge has a length(positive integer less than 1001).  Define dist(u,v)=The min distance between node u and v.  Give a…
POJ - 1330 Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000KB   64bit IO Format: %lld & %llu Submit Status Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:  In t…
Apple Tree Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9808   Accepted: 3260 Description Wshxzt is a lovely girl. She likes apple very much. One day HX takes her to an apple tree. There are N nodes in the tree. Each node has an amoun…
题目链接:http://poj.org/problem?id=3321 Apple Tree Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 34812 Accepted: 10469 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka like…
Subway tree systems POJ - 1635 题目大意:给出两串含有‘1’和‘0’的字符串,0表示向下搜索,1表示回溯,这样深搜一颗树,深搜完之后问这两棵树是不是同一棵树 /* 在poj上交需要加一个string头文件,不然会CE 树的最小表示 这里用的最小表示法就是将树的所有子树分别用1个字符串表示,要按字典序排序将他们依依连接起来.连接后如果两个字符串是一模一样的,那么他们必然是同构的.这样原问题就变成了子问题,子树又是一颗新的树. */ #include<iostream>…
poj.org/problem?id=3321 [题意] 给一棵n个节点的树,每个节点开始有一个苹果,m次操作 1.将某个结点的苹果数异或 1 2.查询一棵子树内的苹果数 #include<iostream> #include<cstdio> #include<cstring> #include<string> #include<cmath> #include<algorithm> using namespace std; typed…
Tree Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 6131   Accepted: 1682 Description You are given a tree with N nodes. The tree's nodes are numbered 1 through N and its edges are numbered 1 through N − 1. Each edge is associated with…
Apple Tree Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 25232   Accepted: 7503 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been…
E - Cell Phone Network POJ - 3659 题目大意: 给你一棵树,放置灯塔,每一个节点可以覆盖的范围是这个节点的所有子节点和他的父亲节点,问要使得所有的节点被覆盖的最少灯塔数量. 考虑每一个节点要被覆盖应该如何放置灯塔. 如果一个节点被覆盖 1 该节点放了灯塔  2 该点的父亲节点放了灯塔  3 该点的儿子节点放了灯塔. dp[u][0] 表示这个节点的儿子节点放了灯塔 dp[u][1] 表示这个点本身放了灯塔 dp[u][2] 表示这个点的父亲节点放了灯塔 转移方程,…