求因子数一定的最小数(反素数) #include<iostream> #include<string> #include<cmath> #include<cstring> #include<vector> #include<map> #include<set> #include<algorithm> #include<queue> #include<stack> #include<…
E. Number With The Given Amount Of Divisors time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Given the number n, find the smallest positive integer which has exactly n divisors. It is guara…
E. Number With The Given Amount Of Divisors time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Given the number n, find the smallest positive integer which has exactly n divisors. It is guara…
E. Number With The Given Amount Of Divisors time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Given the number n, find the smallest positive integer which has exactly n divisors. It is guara…
传送门 Description 给定一个正整数\(n\),输出最小的整数,满足这个整数有n个因子 Input 一行一个整数\(n\) Output 一行一个整数,代表答案. Hint \(1~\leq~n~\leq~1000\).保证答案不超过\(10^{18}\) Solution 经典题. 引理: 对于一个唯一分解式形如\(x=p_1^{c_1}p_2^{c_2}p_3^{c^3}\cdots p_k^{c_k}\)的数字\(x\),则其因数个数为\(\prod(c_i+1)\). 证明:…
题目链接:http://codeforces.com/problemset/problem/27/E 暴力 //#pragma comment(linker, "/STACK:102400000, 102400000") #include <algorithm> #include <iostream> #include <cstdlib> #include <cstring> #include <cstdio> #includ…
题目链接 首先要知道一个性质, 一个数x的因子个数等于 a1^p1 * a2^p2*....an^pn, ai是x质因子, p是质因子的个数. 然后就可以搜了 #include <iostream> #include <vector> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <map> #incl…
http://codeforces.com/problemset/problem/27/E RT,求含n个约数的最小的数 我们设答案p = 2^t1 * 3^t2 * -- * p^tk(其中p是第k大的质数),则必有:t1 >= t2 >= t3 >= - >= tk >= 0. 反证法证明:若不然可将{ti}由大到小排序,设形成的新有序序列是{ti'},t1' >= t2' >= t3' >= - >= tk':令p' = 2^t1' * 3^t2…
题目来源:CodeForce #27 E 题目意思和题目标题一样,给一个n,求约数的个数恰好为n个的最小的数.保证答案在1018内. Orz,这题训练的时候没写出来. 这道题目分析一下,1018的不大,比264要小,所以这题可以枚举. 一个数 A 可以分解成 p1k1 * p2k2 * -- * pnkn 其中p为素数.这样分解之后,A的因子个数 S = (k1+1) *( k2+1) * -- *( kn+1) 然后用dfs枚举 + 剪枝. 剪枝的话大于现有结果return.就这样就能AC了.…
题目链接:http://codeforces.com/contest/27/problem/E 题意:问因数为n个的最小的数是多少. 题解:一般来说问到因数差不多都会想到素因子. 任意一个数x=(p1^a1)*(p2^a2)*(p3^a3)*......*(pn^an);p表示素数. 然后因子数就是ans=(a1+1)*(a2+1)*(a3+1)*....*(an+1) 这个很显然.然后要使得x最小而且ans最大 显然要优先选择最小的素数. 拿12=(2^2)*3为样例可以建一个搜索树于是dfs…
CodeForces - 27E Number With The Given Amount Of Divisors Submit Status Description Given the number n, find the smallest positive integer which has exactly n divisors. It is guaranteed that for the given n the answer will not exceed 1018. Input The…
Yada Number Problem Description: Every positive integer can be expressed by multiplication of prime integers. Duoxida says an integer is a yada number if the total amount of 2,3,5,7,11,13 in its prime factors is even. For instance, 18=2 * 3 * 3 is no…
Yada Number       Time Limit : 2000 MS   Memory Limit : 65536 KB   Yada Number Problem Description: Every positive integer can be expressed by multiplication of prime integers. Duoxida says an integer is a yada number if the total amount of 2,3,5,7,1…
Yada Number Problem Description: Every positive integer can be expressed by multiplication of prime integers. Duoxida says an integer is a yada number if the total amount of 2,3,5,7,11,13 in its prime factors is even. For instance, 18=2 * 3 * 3 is no…
我的那个暴力求解,太耗时间了. 用了网上产的什么因式分解,质因数之类的.确实快!还是数学基础不行,只能知道大约. The sequence of triangle numbers is generated by adding the natural numbers. So the 7th triangle number would be 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28. The first ten terms would be: 1, 3, 6, 10, 15, 2…
Highly divisible triangular number Problem 12 The sequence of triangle numbers is generated by adding the natural numbers. So the 7th triangle number would be 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28. The first ten terms would be: 1, 3, 6, 10, 15, 21, 28, 36,…
问题 : Friends number 时间限制: 1 Sec  内存限制: 128 MB 题目描述 Paula and Tai are couple. There are many stories between them. The day Paula left by airplane, Tai send one message to telephone 2200284, then, everything is changing- (The story in "the snow queen&q…
Time limit  1000 ms Memory limit   131072 kB Paula and Tai are couple. There are many stories between them. The day Paula left by airplane, Tai send one message to telephone 2200284, then, everything is changing… (The story in “the snow queen”). Afte…
Paula and Tai are couple. There are many stories between them. The day Paula left by airplane, Tai send one message to telephone 2200284, then, everything is changing- (The story in "the snow queen"). After a long time, Tai tells Paula, the numb…
title: The sequence of triangle numbers is generated by adding the natural numbers. So the 7th triangle number would be 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28. The first ten terms would be: 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, ... Let us list the factors of…
[PHP];;;;;;;;;;;;;;;;;;;; About php.ini   ;;;;;;;;;;;;;;;;;;;;; PHP's initialization file, generally called php.ini, is responsible for; configuring many of the aspects of PHP's behavior.; php的初始化文件,通常叫做php.ini,负责配置php很多层面的行为; PHP attempts to find an…
--假设 成绩>100 优 --假设成绩>90 良 select * from TblScore select 英语成绩= (case  when tEnglish>90  then '良' when tEnglish>100 then'优'    end),数学成绩=(case when tMath>90  then '良' when tMath>100 then'优'  end) from TblScore --第二个练习  1  2  3 select * fro…
C#常见的设计模式 一.概要: 模式分为三种,设计模式.体系结构模式与惯用法.其中惯用法是一种语言紧密相关的模式,例如,定界加锁模式其实是一种惯用法. 在C#项目开发过程中,很多情况下您已经使用了某些模式,但或许您并不知道自己所使用的这种解决方案是一种已经被总结归纳的模式. 工厂.策略.桥接.模板方法.代理等等23种Gof经典模式是属于设计模式,设计模式的粒度相对较小,基本上用于提高模块内部的可扩展性和可维护性需求 三层.MVC.IoC/DI等属于体系结构模式,粒度比设计模式大,它是从项目的整体…
从Hinton在science上发表深度学习训练开创新的文章以来,深度学习火了整整有3年多,而且随着新的硬件和算法的提出,深度学习正在应用于越来越多的领域,发挥其算法的优势. 实验室并没有赶上第一波深度学习热,但是让人高兴的是最近终于配了一台超级电脑,虽说和谷歌.百度几百个上千个GPU跑算法的设备不能比,但是好歹终于有了搭建自己的深度学习平台,想想还很是兴奋.最近这几天忙着搭建深度学习平台,把现在最火的Caffe框架代码跑通,从最初对ubuntu的菜鸟到现在顺利搭建起深度学习平台,中间走了很多弯…
Ubuntu14.04+caffe+cuda 环境搭建以及MNIST数据集的训练与测试 一.ubuntu14.04的安装: ubuntu的安装是一件十分简单的事情,这里给出一个参考教程: http://jingyan.baidu.com/article/76a7e409bea83efc3b6e1507.html 二.cuda的安装: 1.首先下载nvidia cuda的仓库安装包(我的是ubuntu 14.04 64位,所以下载的是ubuntu14.04的安装包,如果你是32位的可以参看具体的地…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2069 Problem Description Suppose there are 5 types of coins: 50-cent, 25-cent, 10-cent, 5-cent, and 1-cent. We want to make changes with these coins for a given amount of money.For example, if we have 11…
Preparation for MCM/ICM Writing -- by Chance Zhang $1^{st}ed$ key words: MCM/ICM, format, phrases, tools 目录 Preparation for MCM/ICM Writing Format The Basic Format Style and Layout Phrase bank Tools Codes Latex Table & Figure Finding Data Collaborati…
使用函数式语言来建立领域模型--类型组合 理解函数式编程语言中的组合--前言(一) 理解函数式编程中的函数组合--Monoids(二) 继上篇文章引出<范畴论>之后,我准备通过几篇文章,来介绍函数式编程语言中的若干"行话",例如Functor, Applicative, Monad.如果给这些名字一个通俗的名称,我觉得Combinator(组合子)比较形象一些,组合子可以将函数组合起来.我在一篇文章中还看到过一个另一个通俗的说法--"胶水函数",简而言之…
Problem: A Time limit: 1s    Mem limit: 64 MB    AC/Submission: 0/0    Discuss Back   Ranklist  Status  Pending: NaN天 NaN时 NaN分 NaN秒 Problem DescriptionA famous ACMer named LIST.He is very rich,so he has infinite coins of some par value(面值).One day h…
npm install -g aglio npm i aglio-theme-minimal aglio --theme-full-width -t minimal -i ./src/index.md -o index.html FORMAT: 1AHOST: http://123.56.205.244:8602/event/ # Common Demo Interface Plan后端 `Demo` 通用接口计划 # Group Event Manage农事管理 ## Event [/even…