poj 1269 计算几何

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/** 判断直线位置关系 **/ #include <iostream> #include <cmath> #include <cstdio> using namespace std; struct point { double x,y; point(,):x(x),y(y){} }; typedef point Vector; Vector operator - (point A,point B){ return Vector(A.x-B.x,A.y-B.y); }…

POJ 1269 (直线求交）

Problem Intersecting Lines (POJ 1269) 题目大意给定两条直线,问两条直线是否重合,是否平行,或求出交点. 解题分析主要用叉积做,可以避免斜率被0除的情况. 求交点P0: 已知P1 P2 P3 P4 运用 P0P1 X P0P2 = 0 和 P0P3 X P0P4 = 0 C++ 用%.2lf g++ 用 %.2f!!! C++ 用%.2lf g++ 用 %.2f!!! C++ 用%.2lf g++ 用 %.2f!!! 参考程序 #include <cstd…

直线相交 POJ 1269

// 直线相交 POJ 1269 // #include <bits/stdc++.h> #include <iostream> #include <cstdio> #include <cstdlib> #include <algorithm> #include <math.h> using namespace std; #define LL long long typedef pair<int,int> pii; con…

判断两条直线的位置关系 POJ 1269 Intersecting Lines

两条直线可能有三种关系:1.共线 2.平行(不包括共线) 3.相交. 那给定两条直线怎么判断他们的位置关系呢.还是用到向量的叉积例题:POJ 1269 题意:这道题是给定四个点p1, p2, p3, p4,直线L1,L2分别穿过前两个和后两个点.来判断直线L1和L2的关系这三种关系一个一个来看: 1. 共线. 如果两条直线共线的话,那么另外一条直线上的点一定在这一条直线上.所以p3在p1p2上,所以用get_direction(p1, p2, p3)来判断p3相对于p1p2的关…

poj 1269 线段与线段相交

Intersecting Lines Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 13605 Accepted: 6049 Description We all know that a pair of distinct points on a plane defines a line and that a pair of lines on a plane will intersect in one of three…

POJ 1269 Intersecting Lines (判断直线位置关系)

题目链接:POJ 1269 Problem Description We all know that a pair of distinct points on a plane defines a line and that a pair of lines on a plane will intersect in one of three ways: 1) no intersection because they are parallel, 2) intersect in a line becau…