*HDU 1398 母函数】的更多相关文章

Square Coins Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11529    Accepted Submission(s): 7897 Problem Description People in Silverland use square coins. Not only they have square shapes but…
pid=1398">链接:hdu 1398 题意:有17种货币,面额分别为i*i(1<=i<=17),都为无限张. 给定一个值n(n<=300),求用上述货币能使价值总和为n的方案数 分析:这题能够用母函数的思想,对300以内的值进行预处理就可以 也可用全然背包思想求300以内的方案数 母函数: #include<stdio.h> int main() { int c1[305],c2[305],i,j,k,n; for(i=0;i<=300;i++){…
///hdu 1028 母函数 一个数有几种相加方式 #include<stdio.h> #include<string.h> #include<iostream> #include<algorithm> #define INF 1000000009 using namespace std; ; int c1[_max], c2[_max]; int main() { int n,i,j,k; while(cin>>n) { ;i<=n;i…
Square Coins Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1398 Description People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Co…
Problem Description People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values of all square numbers up to 289 (=17^2), i.e., 1-credit coins, 4-credit coins, 9-credit coins, ...…
Square Coins Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7883    Accepted Submission(s): 5332 Problem Description People in Silverland use square coins. Not only they have square shapes but…
题意:输入一个n  给出其所有组合数 如: 4 = 4;  4 = 3 + 1;  4 = 2 + 2;  4 = 2 + 1 + 1;  4 = 1 + 1 + 1 + 1; 重复不算 母函数入门题: #include<iostream> #include<queue> #include<cstdio> #include<cstring> #include<vector> #include<map> #include<algo…
欢迎参加——BestCoder周年纪念赛(高质量题目+多重奖励) Square Coins Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9728    Accepted Submission(s): 6668 Problem Description People in Silverland use square coins. Not…
题意: 有17种硬币,每种的面值为编号的平方,比如 1,4,9,16.....给出一个数字,求组成这个面值有多少种组法? 思路: 用普通母函数解,主要做的就是模拟乘法,因为硬币是无限的,所以每个构造式中每一个项的系数都是1.我们只需要第n项的系数,大于n的并不需要,所以大于n的项就不用再做计算了. #include <bits/stdc++.h> using namespace std; ; int main() { freopen("input.txt", "r…
Square Coins Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9903    Accepted Submission(s): 6789 Problem Description People in Silverland use square coins. Not only they have square shapes but…