题目的关键是要让新链表和原有链表发送关联,可以通过这种关联来设置新链表的random pointer 思路:将新链表的元素插入到原有链表元素的后面,如下图所示,就可以根据原有链表的radom->next 就是新链表的random指针 所以分3步骤: 1 新元素插入 2 设置新链表的random 3 拆分大链表,回复old link 和new link /** * Definition for singly-linked list with a random pointer. * struct R…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这道链表的深度拷贝题的难点就在于如何处理随机指针的问题,由于每一个节点都有一个随机指针,这个指针可以为空,也可以指向链表的任意一个节点,如果我们在每生成一个新节点给其随机指…

原题地址:https://oj.leetcode.com/problems/copy-list-with-random-pointer/ 题意: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 解题思路:这题主要是需要深…

给大家推荐一道leetcode上的面试题,这道题的详细解说在<剑指offer>的P149页有思路解说.假设你手头有这本书.建议翻阅. 题目链接 here A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. RandomLi…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 原题链接:https://oj.leetcode.com/problems/copy-list-with-random-pointer/ 题目:给定一个链表,当中的每一个节…

问题: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list.   结点的定义如下: /** * Definition for singly-linked list with a random pointer. * class…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 随机链表的节点数据结构 struct RandomListNode { int label; RandomListNode *next, *random; RandomLi…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 深度复制: 仅简单的遍历一遍链表时,没法复制random pointer属性.所以有点懵,大神的做法如下,加入个人理解. 思路:对链表进行三次遍历. 第一次遍历复制每一个结…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. /** * Definition for singly-linked list with a random pointer. * class RandomListNode…

/** * Definition for singly-linked list with a random pointer. * struct RandomListNode { * int label; * RandomListNode *next, *random; * RandomListNode(int x) : label(x), next(NULL), random(NULL) {} * }; */ class Solution {//为了可以高速定位某个节点,採用确定性映射的方式,将…