目的:根据曲线值获得当前动作帧.用于实现各种通过曲线同步的功能. 方法:继承FAnimNode_Base创建自定义动画节点.重写Evaluate部分.创建相应的AnimGraphNode.可参考前一篇http://blog.csdn.net/u010831746/article/details/50733287 Evaluate : 1. 根据曲线Value(Y轴)值获得Time(X轴)值. 曲线KeyArray所在位置.AnimSequenceBase : RawCurveData. 类型An…

用途1: 半透明材质中实现遮挡Mesh自己其他部分的效果. 不遮挡效果如下: 遮挡后效果如下: 实现方法: 深度信息是越远值越大,使用两个Mesh,一个正常渲染,另一个渲染到custom depth buffer 即勾选Render Custom Depth Buffer,注意这个用来渲染到custom depth buffer的mesh不能使用Translucent的材质,因为透明物体不会写入深度缓冲.当custom depth buffer跟每个像素对应的深度信息比较时,pixeldepth…

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张宁 A Linear Least Square Initialization Method for 3D Pose Graph Optimization Problem "链接:https://pan.baidu.com/s/1oj_HgQtiiKExACscYuFhJQ 提取码:7xrg" 三维位姿图优化问题的线性最小二乘初始化方法 S. M. Nasiri, H. Moradi, Senior Member, IEEE, R. Hosseini Abstract Pose Gra…

Advanced Locomotion System V3是虚幻商城的一款第三方插件.它相比UE4的基础走跑跳表现,实现了更多动作游戏里常用的运动特性,虽然价格定价不菲,依然备受关注.笔者试用了这款插件,确实很强大,适合作为基础插件来做FPS,ACT游戏,因此简单学习分析下这款插件. 插件特点: 具备动作游戏的常见特性,支持多种移动模式,步行,奔跑,冲刺,下蹲,Ragdoll 运动细节做得很到位,包括原地转身,奔跑急停转向,移动中身体倾斜,落地腿部缓冲,头部Aim Offset(AO),腿部IK…

教是言词, 实不是道,道本无言, 言说是妄.------- 达摩 Qt 5提出了一个新的渲染底层,以替代Qt4时期的Graphics View,这个渲染底层就是Scene Graph.Scene Graph主要利用OpenGL ( ES )2的渲染优势,在2D和3D以非常流畅的速度进行渲染,满足日益增长的界面效果需求,同时Scene Graph预留了各种各样的接口,满足大家定义显示和渲染效果的需要. 该文章下面部分,主要来自Qt官方的说明文档:http://doc.qt.io/qt-5/qtqu…

  Find the number Weak Connected Component in the directed graph. Each node in the graph contains a label and a list of its neighbors. (a connected set of a directed graph is a subgraph in which any two vertices are connected by direct edge path.) Ex…

Given a directed graph, design an algorithm to find out whether there is a route between two nodes. Have you met this question in a real interview? Yes Example Given graph: A----->B----->C \ | \ | \ | \ v ->D----->E for s = B and t = E, return…

Problem link: http://oj.leetcode.com/problems/clone-graph/ This problem is very similar to "Copy List with Random Pointer", we need a hash map to map a node and its clone. The algorithm is 2-pass procedure as follows. CLONE-GRAPH(GraphNode node)…

题目: 找出无向图汇总的相连要素 请找出无向图中相连要素的个数. 图中的每个节点包含其邻居的 1 个标签和 1 个列表.(一个无向图的相连节点(或节点)是一个子图,其中任意两个顶点通过路径相连,且不与超级图中的其它顶点相连.) 样例 给定图: A------B C \ | | \ | | \ | | \ | | D E 返回 {A,B,D}, {C,E}.其中有 2 个相连的元素,即{A,B,D}, {C,E} 解题: 广度优先+递归,写不出来,程序来源 Java程序: /** * Defini…

上回说到,游戏项目中客观会遇到逻辑状态的复杂性和动画状态的单一性之间的矛盾,那么Animation Tree是如何解决这个问题的呢? 这又需要引入一个定律:就是逻辑状态无论有多么复杂,但一套逻辑状态组合一定唯一对应一个具体的动画. 举例来说:已知控制当前游戏对象的逻辑状态有是否技能中.是否受击.是否中毒.是否眩晕. 那么我们可以建立一个下面的关系: 技能中 否 是 否 否 否 否 是 受击 否 否 是 否 否 否 是 中毒 否 否 否 是 否 是 是 眩晕 否 否 否 否 是 是 否 最终动作…

题目来源: https://leetcode.com/problems/clone-graph/ 题意分析: 克隆一个无向图.每个节点包括一个数值和它的邻居. 题目思路: 直接深度拷贝. 代码(python): # Definition for a undirected graph node # class UndirectedGraphNode(object): # def __init__(self, x): # self.label = x # self.neighbors = [] cl…

类似于二叉树的三种遍历,我们能够基于遍历的模板做非常多额外的事情,图的两种遍历,深度和广度模板相同也能够做非常多额外的事情,这里举例利用深度优先遍历的模板来进行复制,深度优先中,我们先訪问第一个结点,接着訪问第一个邻接点,再訪问邻节点的邻节点.... class Solution: # @param node, a undirected graph node # @return a undirected graph node def cloneGraph(self, node): if None…

使用脚本控制动画 Animation 组件 Animation 组件提供了一些常用的动画控制函数,如果只是需要简单的控制动画,可以通过获取节点的 Animation 组件来做一些操作. 播放 var anim = this.getComponent(cc.Animation); // 如果没有指定播放哪个动画,并且有设置 defaultClip 的话,则会播放 defaultClip 动画 anim.play(); // 指定播放 test 动画 anim.play('test'); // 指定…

Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…

Given a directed graph, design an algorithm to find out whether there is a route between two nodes. Have you met this question in a real interview? Yes Example Given graph: A----->B----->C \ | \ | \ | \ v ->D----->E for s = B and t = E, return…

原题地址:https://oj.leetcode.com/problems/clone-graph/ 题意:实现对一个图的深拷贝. 解题思路:由于遍历一个图有两种方式:bfs和dfs.所以深拷贝一个图也可以采用这两种方法.不管使用dfs还是bfs都需要一个哈希表map来存储原图中的节点和新图中的节点的一一映射.map的作用在于替代bfs和dfs中的visit数组,一旦map中出现了映射关系,就说明已经复制完成,也就是已经访问过了. dfs代码: # Definition for a undire…

Find the Connected Component in the Undirected Graph Find the number connected component in the undirected graph. Each node in the graph contains a label and a list of its neighbors. (a connected component (or just component) of an undirected graph i…

Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…

参考:http://blog.csdn.net/leonwei/article/details/5819248 http://blog.csdn.net/debugconsole/article/details/32721901 在Ogre中Animation是一块非常重要的部分,但是笔者在学习Ogre的动画时遗憾的发现关于Ogre中动画的资料非常的少,Ogre的sample中只有最简单的导入一个骨骼动画的例子,在网上也很少有人谈及,Ogre Wiki中的教程也是边边角角,不知这么重要的部分为什…

［抄题］: 克隆一张无向图,图中的每个节点包含一个 label 和一个列表 neighbors. ［思维问题］: ［一句话思路］: 先BFS克隆点(一个点+扩展所有邻居),再克隆邻居(一个点+扩展所有邻居). ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: bfs的结果应该存在一个节点构成的数组中ArrayList<UndirectedGraphNode>,作为for(UndirectedGraphNode n: nod…

［抄题］: Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node…

Graph is an important data structure and has many important applications. Moreover, grach traversal is key to many graph algorithms. There are two systematic ways to traverse a graph, breadth-first search (BFS) and depth-frist search (DFS). Before fo…

Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node label and each neigh…

Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…

题目如下: Given the head of a graph, return a deep copy (clone) of the graph. Each node in the graph contains a label (int) and a list (List[UndirectedGraphNode]) of its neighbors. There is an edge between the given node and each of the nodes in its neig…

You've got a undirected graph G, consisting of n nodes. We will consider the nodes of the graph indexed by integers from 1 to n. We know that each node of graph G is connected by edges with at least k other nodes of this graph. Your task is to find i…

本次分析的KOA版本是2.13.1,它非常轻量,诸如路由.模板等功能默认都不提供,需要自己引入相关的中间件. 源码的目录结构比较简单,主要分为3部分,__tests__,lib和docs,从名称中就可以了解到. __tests__是单元测试,lib是核心代码,docs是文档.在lib目录中只有4个文件. ├── __tests__ ------------------------ 单元测试 ├── docs ----------------------------- 文档 ├── lib ---…

https://docs.unity3d.com/2018.4/Documentation/Manual/Glossary.html 2D terms 2D Physics terms AI terms Analytics terms Animation terms Assets terms Audio terms Core terms Editor terms General terms Graphics terms Lighting terms Multiplayer terms Packa…

https://github.com/XCGit/awesome-objc-frameworks#awesome-objc-frameworks awesome-objc-frameworks ID Framework Images 1 AFNetworking/AFNetworking 19,058 A delightful iOS and OS X networking framework 2 rs/SDWebImage 10,139 Asynchronous image downloade…