Problem Description 大学英语四级考试就要来临了,你是不是在紧张的复习?也许紧张得连短学期的ACM都没工夫练习了,反正我知道的Kiki和Cici都是如此.当然,作为在考场浸润了十几载的当代大学生,Kiki和Cici更懂得考前的放松,所谓“张弛有道”就是这个意思.这不,Kiki和Cici在每天晚上休息之前都要玩一会儿扑克牌以放松神经.“升级”?“双扣”?“红五”?还是“斗地主”?当然都不是!那多俗啊~作为计算机学院的学生,Kiki和Cici打牌的时候可没忘记专业,她们打牌的规则是…

题目链接:https://www.51nod.com/onlineJudge/questionCode.html#!problemId=1714 nim游戏的一个变形,需要打出sg函数的表 #include <bits/stdc++.h> using namespace std; typedef long long LL; ; ], maxs; int vis[maxn]; //yu控制递归层数,cur控制所分配最大值,next控制所分配最小值 void dfs(int cur, int yu…

题目链接:https://www.51nod.com/onlineJudge/questionCode.html#!problemId=1714 nim游戏的一个变形,需要打出sg函数的表 #include <bits/stdc++.h> using namespace std; typedef long long LL; ; ], maxs; int vis[maxn]; //yu控制递归层数,cur控制所分配最大值,next控制所分配最小值 void dfs(int cur, int yu…

题意: n*m的棋盘,一枚硬币右上角,每人每次可将硬币移向三个方向之一(一格单位):左边,下边,左下边. 无法移动硬币的人负. 给出n和m,问,先手胜还是后手胜. 数据范围: n, m (0<n,m<=2000) 思路: dp[i][j]=0,说明从(i,j)这个点到时左下角先手败.dp[i][j]=1则先手胜. 然后记忆搜.但是记忆搜会超时. 搜完把整张表打出来,发现规律了,,,,然后,,,代码剩几行了. 代码: ///打表观察 /* int f[2005][2005]; int go(in…

Nim or not Nim? Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 3032 Description Nim is a two-player mathematic game of strategy in which players take turns removing objects from distinct heaps.…

Nim or not Nim? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 613    Accepted Submission(s): 282 Problem Description Nim is a two-player mathematic game of strategy in which players take turns…

Nim or not Nim? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1056    Accepted Submission(s): 523 Problem Description Nim is a two-player mathematic game of strategy in which players take turn…

Nim or not Nim? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 623    Accepted Submission(s): 288 Problem Description Nim is a two-player mathematic game of strategy in which players take turns…

Nim or not Nim? Problem Description Nim is a two-player mathematic game of strategy in which players take turns removing objects from distinct heaps. On each turn, a player must remove at least one object, and may remove any number of objects provide…

题意: 有n堆石子,alice先取,每次可以选择拿走一堆石子中的1~x(该堆石子总数) , 也可以选择将这堆石子分成任意的两堆.alice与bob轮流取,取走最后一个石子的人胜利. 思路: 因为数的范围比较大,所以最好通过SG打表的结果找出规律在解. 打表代码 #include<cstdio> #include<cstring> ]; int find(int x) { ) return sg[x]; ]= {}; ; i<x; i++) { mex[find(i)]=;//…