1080 Graduate Admission (30)(30 分)】的更多相关文章

1080 Graduate Admission(30 分) It is said that in 2011, there are about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Each app…
1080 Graduate Admission (30 分)   It is said that in 2011, there are about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Each…
1080. Graduate Admission (30) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if yo…
1080 Graduate Admission--PAT甲级练习题 It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Eac…
It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Each applicant will have to provide t…
题意: 输入三个正整数N,M,K(N<=40000,M<=100,K<=5)分别表示学生人数,可供报考学校总数,学生可填志愿总数.接着输入一行M个正整数表示从0到M-1每所学校招生人数,N行数据分别包括两个成绩和K个志愿.输出M行依照平行志愿原则输出每所学校录取的学生序号,如果成绩相同,可以突破计划招生人数. trick: 不是很懂为什么当我输出的时候采用if(i>0)cout<<"\n";会导致测试点2和4格式错误..... 发现最后一行必须要换行…
时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to aut…
It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province.  It would help a lot if you could write a program to automate the admission procedure. Each applicant will have to provide…
简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include<string> #include<iostream> #include<algorithm> using namespace std;…
先对学生们进行排序,并且求出对应排名. 对于每一个学生,按照志愿的顺序: 1.如果学校名额没满,那么便被该学校录取,并且另vis[s][app[i].ranks]=1,表示学校s录取了该排名位置的学生. 2.如果该学校名额已满,那么看看vis[s][app[i].ranks]是否为1,若是,则表明学校有录取过和他排名一样的学生,那么该学生也能被录取. 否则,学生未录取. #include <iostream> #include <cstdio> #include <algor…
It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Each applicant will have to provide t…
题目:https://pintia.cn/problem-sets/994805342720868352/problems/994805387268571136 题意: 模拟高考志愿录取. 考生根据总成绩和高考成绩排名.根据排名往下录取,每个人有k个志愿. 如果他填的学校名额没有满,那么就可以被录取.如果他填的学校名额满了,最后一名的排名和这个人是一样的话,就可以被录取. 思路: 直接模拟. 刚开始居然有一个数据超时了,把排序的cmp里面改成传引用居然就过了. //#include<bits/s…
大致题意就是有N个学生,有M个学校,每个学校的名额都是正整数.每个学生可以填K个学校志愿,N个学生一起排名以后,排名高的学生先挑学校,不保护一志愿. 题目要求: 首先,把所有学生按总成绩SUM(GE+GI)递减排序,如果SUM相同,那么就按GE递减排序. 然后,根据成绩确定所有学生的名次.如果当前学生与上一个学生的SUM和GE相同,那么当前学生与上一个学生的名次也相同. 确定所有学生的名次以后,从排名第一名的学生的第一个志愿学校开始. 如果该学校有名额,或者该学校没名额了但是该学生与该学校录取的…
1080. Graduate Admission (30) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if yo…
1080. Graduate Admission It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Each applica…
Source: PAT A1080 Graduate Admission (30 分) Description: It is said that in 2011, there are about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the ad…
题目1005:Graduate Admission 时间限制:1 秒 内存限制:32 兆 特殊判题:否 题目描述: It is said that in 2011, there are about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the a…
# 函数原型detectMultiScale(gray, 1.2,3,CV_HAAR_SCALE_IMAGE,Size(30, 30)) # gray需要识别的图片 # 1.03:表示每次图像尺寸减小的比例 # 5:表示每一个目标至少要被检测到4次才算是真的目标(因为周围的像素和不同的窗口大小都可以检测到人脸) # CV_HAAR_SCALE_IMAGE表示不是缩放分类器来检测,而是缩放图像,Size(30, 30)为目标的最小最大尺寸…
题目链接:http://ac.jobdu.com/problem.php?pid=1005 详解链接:https://github.com/zpfbuaa/JobduInCPlusPlus 参考代码: // // 1005 Graduate Admission.cpp // Jobdu // // Created by PengFei_Zheng on 27/04/2017. // Copyright © 2017 PengFei_Zheng. All rights reserved. // #…
C#  时间格式处理,获取格式: 2014-04-12T12:30:30+08:00 一.获取格式: 2014-04-12T12:30:30+08:00 方案一:(局限性,当不是当前时间时不能使用)   string time = System.DateTime.Now.ToString("s");   //    2014-04-12T12:30:30 string timeZone = DateTime.Now.ToString("o");     //2014…
java.time.format.DateTimeParseException: Text '2019-10-11 12:30:30' could not be parsed at index 10 at java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:1949) at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1…
时间限制:1 秒 内存限制:32 兆 特殊判题:否 提交:5646 解决:1632 题目描述: It is said that in 2011, there are about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission p…
It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Each applicant will have to provide t…
题目描述: It is said that in 2011, there are about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure.    Each applicant will have to p…
It is said that in 2011, there are about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Each applicant will have to provide tw…
对于在中国大学MOOC(http://www.icourse163.org/ )学习“数据结构”课程的学生,想要获得一张合格证书,必须首先获得不少于200分的在线编程作业分,然后总评获得不少于60分(满分100).总评成绩的计算公式为 0,如果 G​mid−term​​>G​final​​:否则总评 G 就是 G​final​​.这里 G​mid−term​​ 和 G​final​​ 分别为学生的期中和期末成绩. 现在的问题是,每次考试都产生一张独立的成绩单.本题就请你编写程序,把不同的成绩单合…
问题来源 http://ac.jobdu.com/problem.php?pid=1005 问题描述 这道题理解题意有些麻烦,多看几遍先理解题意再说.每个学生有自己的三个成绩,一个编号,以及一个志愿列表.每个学校有自己的招生人数限制.按要求输出每所学校最后的招生情况. 问题分析 我们按照题目要求一个一个来.使用两个结构体分别为Student和School. typedef struct Student{ int id; int GE; int GI; double Final; ]; }Stud…
本文为PAT甲级分类汇编系列文章. 排序题,就是以排序算法为主的题.纯排序,用 std::sort 就能解决的那种,20分都算不上,只能放在乙级,甲级的排序题要么是排序的规则复杂,要么是排完序还要做点什么的. 在1051至1100中有6道: 题号 标题 分数 大意 时间 1055 The World's Richest 25 限定范围排序结果 500ms 1056 Mice and Rice 25 分组排序 200ms 1062 Talent and Virtue 25 一定规则的排序 400m…
今天开个坑,分类整理PAT甲级题目(https://pintia.cn/problem-sets/994805342720868352/problems/type/7)中1051~1100部分.语言是modern C++. 为什么要整理呢,因为我2019年9月要考PAT甲级,虽然是第一次考,虽然只学了数据结构(https://mooc.study.163.com/course/1000033001?tid=2402970002#/info),但我要冲着高分(2019年9月8日更新:满分)去. 下…
博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6102219.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 时隔两年,又开始刷题啦,这篇用于PAT甲级题解,会随着不断刷题持续更新中,至于更新速度呢,嘿嘿,无法估计,不知道什么时候刷完这100多道题. 带*的是我认为比较不错的题目,其它的难点也顶多是细节处理的问题~ 做着做着,发现有些题目真的是太水了,都不想写题解了…