题目链接: https://cn.vjudge.net/problem/SGU-101 题目大意: 给定你n张骨牌,每张牌左右两端有一个数字,每张牌的左右两端数字可以颠倒,找出一种摆放骨牌的顺序,使得相邻骨牌的两端数字相同(最左边骨牌的最左端和最右边骨牌的最右端可以不管). 解题思路: 直接求解无向图的欧拉回路即可. 欧拉回路相关定理 此处建模把每张牌看做一条边,牌左右两端的数字为起点和终点.存边的时候存两条,一条正向边,一条反向边 首先判断度数关系,存在欧拉道路回路的条件是连通图不存在或者仅存…

Dominoes – game played with small, rectangular blocks of wood or other material, each identified by a number of dots, or pips, on its face. The blocks usually are called bones, dominoes, or pieces and sometimes men, stones, or even cards. The face of…

101. Domino time limit per test: 0.25 sec. memory limit per test: 4096 KB Dominoes – game played with small, rectangular blocks of wood or other material, each identified by a number of dots, or pips, on its face. The blocks usually are called bones,…

题意:好多木棒,俩端有数字(0--6)标记,按数字相同的端首尾相连成一条直线(木棒可以相同).即求有重边的无向图欧拉迹. 先判定是否为欧拉图,俩个条件,不说了.如果是欧拉图,输出路经. 方法:dfs遍历边,回溯时候记录边,遍历过了就标记"双向边". 那么所记录的恰好是一条逆欧拉迹.不可以前进的时候标记,原因:有可能一笔画失败,导致边不连续, 而回溯的时候记录,原因较复杂,大致证明如下: 分几种情况讨论即可: 1,只有偶数结点.任选一个点,必然从一条出发回到该点,直到无边为止,回溯时边自…

SGU 解题报告(持续更新中...Ctrl+A可看题目类型): SGU101.Domino(多米诺骨牌)------------★★★type:图 SGU102.Coprimes(互质的数) SGU103.TrafficLights(交通灯)---------★★type:图 SGU104.LittleShopofFlowers(小花店)---★type:DP SGU105.Div3(整除3) SGU106.TheEquation(方程)-------------★type:数论 SGU107.…

101. Domino time limit per test: 0.25 sec. memory limit per test: 4096 KB Dominoes – game played with small, rectangular blocks of wood or other material, each identified by a number of dots, or pips, on its face. The blocks usually are called bones,…

SGU 100 A+B :太神不会 SGU 101 Domino: 题目大意:有N张骨牌,两张骨牌有两面有0到6的数字,能相连当且仅当前后数字相同,问能否有将N张骨牌连接的方案?思路:裸的欧拉回路,注意自环,连通 //sgu101 #include<iostream> #include<cstdio> #include <math.h> #include<algorithm> #include<string.h> #include<queu…