1004 Counting Leaves (30分)   A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Specification: Each input file contains one test case. Each case starts with a line containing…

1004 Counting Leaves (30分) A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Specification: Each input file contains one test case. Each case starts with a line containing 0…

题意:给出一棵树的点数N,输入M行,每行输入父亲节点An,儿子个数n,和a1,a2,...,an(儿子结点编号),从根节点层级向下依次输出当前层级叶子结点个数,用空格隔开.(0<N<100) AAAAAccepted code: #include<bits/stdc++.h> using namespace std; vector<]; queue<int>q; ; ; ; ; ; void BFS(){ int x=q.front();//队头元素调用 if(v…

A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Specification: Each input file contains one test case. Each case starts with a line containing 0, the number of nodes in a…

1004 Counting Leaves (30)(30 分) A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Each input file contains one test case. Each case starts with a line containing 0 < N < 10…

1004. Counting Leaves (30)   A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Each input file contains one test case. Each case starts with a line containing 0 < N < 100,…

1004. Counting Leaves (30) A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Each input file contains one test case. Each case starts with a line containing 0 < N < 100, th…

题目链接:https://www.patest.cn/contests/pat-a-practise/1004 大意:输出按层次输出每层无孩子结点的个数 思路:vector存储结点,dfs遍历 #include<iostream> #include<cstdio> #include<string> #include<vector> #include<algorithm> using namespace std; ; int n,m,k,x,f[m…

统计每层的叶子节点个数建树,然后dfs即可 #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <vector> using namespace std; /* 统计每层的叶子节点个数 建树,然后dfs即可 */ ; int n,m; int layer[maxn]; //统计每层的叶子节点个数 ; vector<int…

题目 A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Each input file contains one test case. Each case starts with a line containing 0 < N < 100, the number of nodes in a t…

A family hierarchy is usually presented by a pedigree tree.  Your job is to count those family members who have no child. Input Each input file contains one test case. Each case starts with a line containing 0 < N < 100, the number of nodes in a tre…

简单DFS. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<vector> using namespace std; +; vector<int>g[maxn]; int n,m; int ans[maxn]; int root; int Deep; void dfs(in…

利用广度优先搜索,找出每层的叶子节点的个数. #include <iostream> #include <vector> #include <queue> #include <fstream> using namespace std; vector<vector<int>> tree; vector<int> ans; void BFS(int s) { queue<pair<int, int>>…

problem A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Each input file contains one test case. Each case starts with a line containing 0 < N < 100, the number of nodes i…

1004. Counting Leaves (30) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Each input file contains one…

1004 Counting Leaves (30 分) A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Specification: Each input file contains one test case. Each case starts with a line containing …

题目与翻译 1004 Counting Leaves 数树叶 (30分) A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. 一个家族的等级通常是由一个系谱树表示的.你的工作是统计那些没有孩子的家庭成员. Input Specification: 输入规格: Each input file contains…

1049 Counting Ones (30 分)   The task is simple: given any positive integer N, you are supposed to count the total number of 1's in the decimal form of the integers from 1 to N. For example, given N being 12, there are five 1's in 1, 10, 11, and 12. I…

1004 Counting Leaves A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Specification: Each input file contains one test case. Each case starts with a line containing 0<N<10…

Counting Leaves A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Specification: Each input file contains one test case. Each case starts with a line containing 0 < N < 100…

给出一棵树,问每一层各有多少叶子节点 dfs遍历树 #include<bits/stdc++.h> using namespace std; vector<]; int n,m; int node ,k; ]; ; void dfs(int node,int step) { if(p[node].empty()){ vis[step]++; maxn=max(step,maxn); } else{ ;i<p[node].size();i++){ dfs(p[node][i],ste…

A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Specification: Each input file contains one test case. Each case starts with a line containing 0, the number of nodes in a…

A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Each input file contains one test case. Each case starts with a line containing 0 < N < 100, the number of nodes in a tree…

题目分析: 一共有N个编号为1~1000的人,以及一共有编号为1~1000种不同的兴趣,在题目给出1~N编号的人员每个人喜欢的兴趣的id后,要求统计出不同的人员集合的个数以及每个人员几个的人数从大到小输出 注意点: 1.每个输入的人员id范围1~N,但是并不意味着兴趣的id也是1~N,完全有可能是大于N 小于等于1000的其他数 2.通过样例输出我们可以得知,如果有三个人喜欢的是(2,3)(3,5)(5,6)类似这样的三个人是归属一个集合的,换句话说只要某个人和另一个集合中的任何一个人有兴趣的交…

一种新的不使用左右子树递归进行树高计算的方法,使用层次遍历 树的存储方式: 1.本题提供的一种思路: 使用(邻接表的思想)二维数组(vector[n])表示树,横坐标表示 父节点,每一行表示孩子. 能够很轻松的使用dfs进行遍历 优点: 只需要知道输入的父和子的值,不需要清楚整个树的结构, 能够方便的使用深搜遍历,计算树高:dfs(root,high): 缺点: 占空间太大,提前要知道节点数的上限 2.双亲表示法 每个节点只有一个指向父节点的指针, 优点: 能够方便的从叶节点往回找,空间小 缺点…

韩梅梅喜欢满宇宙到处逛街.现在她逛到了一家火星店里,发现这家店有个特别的规矩:你可以用任何星球的硬币付钱,但是绝不找零,当然也不能欠债.韩梅梅手边有 1 枚来自各个星球的硬币,需要请你帮她盘算一下,是否可能精确凑出要付的款额. 输入格式: 输入第一行给出两个正整数:N(≤)是硬币的总个数,M(≤)是韩梅梅要付的款额.第二行给出 N 枚硬币的正整数面值.数字间以空格分隔. 输出格式: 在一行中输出硬币的面值 V​1​​≤V​2​​≤⋯≤V​k​​,满足条件 ..数字间以 1 个空格分隔,行首尾不得…

https://pintia.cn/problem-sets/994805342720868352/problems/994805521431773184 A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Specification: Each input file contains one t…

参考:https://blog.csdn.net/qq278672818/article/details/54915636 首先贴上我一开始的部分正确代码: #include<bits/stdc++.h> using namespace std; ; struct node { int level,child;//level为该节点层数,child为该节点孩子数 node() { level=; child=; } }no[N]; int n,m; int ans[N];//ans[i]为第i…

题意: 输入一个正整数N(N<=2^30),输出从1到N共有多少个数字包括1. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int n; cin>>n; ; ,r=,low_bit=,yushu…

根据家谱树从根结点开始输出每一层的叶子结点数量.使用BFS来解决.因为不会重复访问结点,所以不需要vis数组来标记是否访问过该结点. //#include "stdafx.h" #include <iostream> #include <vector> #include <queue> using namespace std; vector<]; // Storing children's dynamic arrays queue<int…