Given two strings A and B, find the minimum number of times A has to be repeated such that B is a substring of it. If no such solution, return -1. For example, with A = "abcd" and B = "cdabcdab". Return 3, because by repeating A three…
原题链接在这里:https://leetcode.com/problems/repeated-string-match/description/ 题目: Given two strings A and B, find the minimum number of times A has to be repeated such that B is a substring of it. If no such solution, return -1. For example, with A = "abc…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/repeated-string-match/description/ 题目描述 Given two strings A and B, find the minimum number of times A has to be repeated such that B is a…
686. 重复叠加字符串匹配 686. Repeated String Match 题目描述 给定两个字符串 A 和 B,寻找重复叠加字符串 A 的最小次数,使得字符串 B 成为叠加后的字符串 A 的子串,如果不存在则返回 -1. 举个例子,A = "abcd",B = "cdabcdab". 答案为 3,因为 A 重复叠加三遍后为 "abcdabcdabcd",此时 B 是其子串:A 重复叠加两遍后为 "abcdabcd",…
题目:Given two strings A and B, find the minimum number of times A has to be repeated such that B is a substring of it. If no such solution, return -1. For example, with A = "abcd" and B = "cdabcdab". Return 3, because by repeating A thr…
problem 686. Repeated String Match solution1: 使用string类的find函数: class Solution { public: int repeatedStringMatch(string A, string B) { ; string t = A; while(t.size() < n2) { t += A; cnt++; } if(t.find(B) != string::npos) return cnt;//err. t += A; : -…
Given two strings A and B, find the minimum number of times A has to be repeated such that B is a substring of it. If no such solution, return -1. For example, with A = "abcd" and B = "cdabcdab". Return 3, because by repeating A three…
Given two strings A and B, find the minimum number of times A has to be repeated such that B is a substring of it. If no such solution, return -1. For example, with A = "abcd" and B = "cdabcdab". Return 3, because by repeating A three…
Given two strings A and B, find the minimum number of times A has to be repeated such that B is a substring of it. If no such solution, return -1. For example, with A = "abcd" and B = "cdabcdab". Return 3, because by repeating A three…
［抄题］: Given two strings A and B, find the minimum number of times A has to be repeated such that B is a substring of it. If no such solution, return -1. For example, with A = "abcd" and B = "cdabcdab". Return 3, because by repeating A…
public static int repeatedStringMatch(String A, String B) { //判断字符串a重复几次可以包含另外一个字符串b,就是不断叠加字符串a直到长度大于等于b,叠加一次计数+1 //看现在的字符串是否包含b,包含就返回,不会包含就再叠加一次,因为可能有半截的在后边,再判断,再没有就返回-1 int count = 0; StringBuilder sb = new StringBuilder(); while (sb.length() < B.l…
题意 题目大意是,给两个字符串 A 和 B,问 B 是否能成为 A+A+A+...+A 的子字符串,如果能的话,那么最少需要多少个 A? 暴力解法 直接 A+A+...,到哪次 A 包含 B 了,就返回 A 的个数. 但是 B 也可能不是 A 的拼接的子字符串,所以这种直观解法还是存在隐患(无限循环),最好还是动动脑筋. 动脑筋解法 假如 B 的长度为 b,A 的长度为 a,那么 n=Math.ceil(b/a) 一定意味着什么.但是到底 n 意味着什么呢?看看例子先. 假设 A=“abcdef…
Given a non-empty string check if it can be constructed by taking a substring of it and appending multiple copies of the substring together. You may assume the given string consists of lowercase English letters only and its length will not exceed 100…
942. 增减字符串匹配 942. DI String Match 题目描述 每日一算法2019/6/21Day 49LeetCode942. DI String Match Java 实现 and so on 参考资料 https://leetcode-cn.com/problems/di-string-match/ https://leetcode.com/problems/di-string-match/…
LeetCode--Reverse String Question Write a function that takes a string as input and returns the string reversed. Example: Given s = "hello", return "olleh". Answer class Solution { public: string reverseString(string s) { string str(s.…
https://leetcode.com/problems/di-string-match/ Given a string S that only contains "I" (increase) or "D" (decrease), let N = S.length. Return any permutation A of [0, 1, ..., N] such that for all i = 0, ..., N-1: If S[i] == "I&quo…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/di-string-match/description/ 题目描述 Given a string S that only contains "I" (increase) or "D" (decrease), let N = S.length. R…
题目要求 Given a string S that only contains "I" (increase) or "D" (decrease), let N = S.length. Return any permutation A of [0, 1, ..., N] such that for all i = 0, ..., N-1: If S[i] == "I", then A[i] < A[i+1] If S[i] == "…
题目如下: Given a string S that only contains "I" (increase) or "D" (decrease), let N = S.length. Return any permutation A of [0, 1, ..., N] such that for all i = 0, ..., N-1: If S[i] == "I", then A[i] < A[i+1] If S[i] == &quo…
Given a non-empty string, encode the string such that its encoded length is the shortest. The encoding rule is: k[encoded_string], where the encoded_string inside the square brackets is being repeated exactly k times. Note: k will be a positive integ…
Given an encoded string, return it's decoded string. The encoding rule is: k[encoded_string], where the encoded_string inside the square brackets is being repeated exactly k times. Note that k is guaranteed to be a positive integer. You may assume th…
All DNA is composed of a series of nucleotides abbreviated as A, C, G, and T, for example: "ACGAATTCCG". When studying DNA, it is sometimes useful to identify repeated sequences within the DNA. Write a function to find all the 10-letter-long seq…
