1.1 NCE21 Daniel Mendoza

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1.1 NCE21 Daniel Mendoza

1.text translation Two hundred years ago, boxing matches were very popular in England. At that time/In those days, boxers fought for prize with bare fists. Because of /By reason of/On account of this, they were known as 'prizefighter'.However, boxing…

lesson 21 Daniel Mendoza

lesson 21 Daniel Mendoza bare 赤裸的 :boxers fought with bare fists crude 天然的:crude sugar, crude oil 粗俗的:A crude manner figure: someone who is important or famous in someway draw up 起草 draw up a contract/will/list/plan 表示喜欢的词语 like/be interested in be f…

NCE3

Lesson1 A puma at large Pumas are large, cat-like animals which are found in America. When reports came into London Zoo that a wild puma had been spotted forty-five miles south of London, they were not taken seriously. However, as the evidence began…

New Concept English three（21）

27W 59 Boxing matches were very popular in England two hundred years ago. In those days, boxers fought with bare fists for Prize money. Because of this, they were known as 'prizefighters'. However, boxing was very crude, for there were no rules and a…

Lesson2 Thirteen equals one

Lesson2 Thirteen equals one equal ['i:kwəl] v. 等于 He equaled the world record. Nobody equals him in strength. Nobody matches him in strength. In English she has no equal in her class. be/ stand head and shoulders above sb. be much better than other…

Disposable microfluidic devices: fabrication, function, and application Gina S. Fiorini and Daniel T

Disposable microfluidic devices: fabrication, function, and application Gina S. Fiorini and Daniel T. Chiu BioTechniques 38:429-446 (March 2005) This review article describes recent developments in microfluidics, with special emphasis on disposable p…

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Codeforces Round #597 (Div. 2) F. Daniel and Spring Cleaning 数位dp

F. Daniel and Spring Cleaning While doing some spring cleaning, Daniel found an old calculator that he loves so much. However, it seems like it is broken. When he tries to compute 1+3 using the calculator, he gets 2 instead of 4. But when he tries co…

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CF1245F: Daniel and Spring Cleaning 题意描述: 给定区间$[L,R]$,其中 $(0\leq L,R\leq 10^9)$,问在区间内有多少数对$(x,y)$满足$x+y==x\land y$. 输入描述: 第一行输入一个$T$表示测试样例数目. 接下来每一个测试样例输入两个整数$L,R$表示区间. 输出描述: 输出一个整数表示答案. 思路: 首先对条件进行变形. $x+y==x\land y$,有$x\&y==0$,证明略.…

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ABSTRACT: Daniel Robbins is best known as the creator of Gentoo Linux and author of many IBM developerWorks articles about Linux. Daniel currently serves as Benevolent Dictator for Life (BDFL) of Funtoo Linux. Funtoo Linux is a Gentoo-based distribut…

『BASH』——Learn BashScript from Daniel Robbins——[001-002]

ABSTRACT: Daniel Robbins is best known as the creator of Gentoo Linux and author of many IBM developerWorks articles about Linux. Daniel currently serves as Benevolent Dictator for Life (BDFL) of Funtoo Linux. Funtoo Linux is a Gentoo-based distribut…

CodeForces - 1245F Daniel and Spring Cleaning （数位DP）

While doing some spring cleaning, Daniel found an old calculator that he loves so much. However, it seems like it is broken. When he tries to compute 1+31+3 using the calculator, he gets 22 instead of 44. But when he tries computing 1+41+4, he gets t…

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从小经历了移民和不断辗转迁徙搬家的Daniel Bolsonaro(现就职于灵石团队,职位是核心技术架构师)知道,人生不可能只有一条路,也不要局限于只给自己设立一条路.既然父母能带自己离开巴西来到美国,说明这个世界上有很多改变生活的道路,条条大路通罗马不过如此. 可惜父母年事已高,要在高消费的加州继续供自己读大学并不容易,不过所幸offer不少,出于对家庭条件的考虑,他还是选择了加州大学圣地亚哥分校作为他的人生新的出发点,毕竟加州大学圣地亚哥分校离家近,给的奖学金也最多,这都是他无法拒绝的理由.…

2020美亚团体—Daniel篇

Daniel的桌上计算机的哈希值(SHA-256)是甚么? 通过取证大师计算 SHA-256值为 07DD40CF28603F421F3A09CD38F1C8AA40A2AC4BFB46ECF8299C38CE6AE44ED5 该桌上计算机操作系统储存在哪个分区上? C盘,分区3 在桌上计算器机中找到Daniel的电子邮件地址是甚么? 仿真后进入OUTlook邮箱 daniellaw43346@gmail.com 该恶意软件感染源是甚么? 未知在Daniel的桌面上发现了甚么恶意软件?(某些字…

[cf 1245 F] Daniel and Spring Cleaning

题意: 求区间$[l,r]$内有多少有序数对$(a,b)$满足$a+b=a\bigoplus b$. $l,r\leq 10^9$. 题解: 有用的就一句话: 求区间内一元组可以一维容斥,同理求二元组可以二维容斥,三元组可以三维容斥…… 我tm原来居然不知道,佛了. 然后数位dp就完事了. 代码: #include<bits/stdc++.h> #define maxn 55 #define maxm 500005 #define inf 0x7fffffff #define ll long…

Codefroces 1245 F. Daniel and Spring Cleaning

传送门考虑简单的容斥设 $F(n,m)$ 表示 $a \in [1,n] , b \in [1,m]$ 的满足 $a+b=a \text{ xor } b$ 的数对的数量那么答案即为 $F(r,r)-2F(l-1,r)+F(l-1,l-1)$ 意思就是总方案减去 $a,b$ 至少一个数小于 $l$ 再加上 $a,b$ 都小于 $l$ 的方案然后现在考虑求 $F$ 首先显然 $a+b=a \text{ xor } b$ 意思就是二进制下不存在同时为 $1$ 的位那么可以考虑简单的数位 $…

codeforces 597div2 F. Daniel and Spring Cleaning（数位dp+二维容斥）

题目链接:https://codeforces.com/contest/1245/problem/F 题意:给定一个区间(L,R),a.b两个数都是属于区间内的数,求满足 a + b = a ^ b 的实数对个数. 题解:看到求区间内满足一定条件的数的个数,应该用数位dp,数位dp基本操作是编写出solve函数调用记忆化搜索,那么考虑solve(R,R)是求0到R满足条件的答案,solve(L-1,R)求a属于0到L-1,b属于0到R满足条件的答案,solve(L-1,L-1)是ab都属于0到L…

[cf1495E]Qingshan and Daniel

选择其中卡片总数较少的一类,当相同时选择$t_{1}$所对应的一类(以下记作$A$类) 如果$t_{1}$不是$A$类,就先对$t_{1}$操作一次(即令$a_{1}$减少1) 下面,问题即不断删去$A$类中的一张卡片,再删除另一类中的一张卡片,直至$A$中卡片被删光事实上,$A$类中卡片删除顺序与最终另一类卡片剩余卡片的位置无关,具体证明考虑交换$A$中两张相邻卡片的删除顺序,并分类讨论来说明不影响即可由此,不妨假设$A$类卡片是从左到右依次删除(即删完一叠后删除下一叠),每一张删除时都找…

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This article come from HEREARS-L1: Learning Tuesday 10:30–12:30; Oral Session; Room: Leonard de Vinci 10:30 ARS-L1.1—GROUP STRUCTURED DIRTY DICTIONARY LEARNING FOR CLASSIFICATION Yuanming Suo, Minh Dao, Trac Tran, Johns Hopkins University, USA; Hojj…

List Of All Machine Learning Sorted By Citation

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CVPR 2017 Paper list

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原文地址: https://www.cnblogs.com/marsggbo/p/9308518.html ------------------------------------------------------------------------------------------------------------ 本文为Awesome-AutoML-Papers的译文. 1.AutoML简介 Machine Learning几年来取得的不少可观的成绩,越来越多的学科都依赖于它.然而,这…