POJ-1751 Highways---确定部分边的MST】的更多相关文章

http://poj.org/problem?id=1751 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2048 题目大意: 给你n个点的坐标,并且m个点之间已经建立起连接,让你输出剩下的MST的连接点. 两题其实一样.就输入一点点不同. 因为题目采用Special Judge故水题一题. POJ: #include<cstdio> #include<cmath> #include<algorit…
Highways Time Limit:1000MS     Memory Limit:10000KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 1751 Appoint description:  System Crawler  (2015-06-02) Description The island nation of Flatopia is perfectly flat. Unfortunately, Flato…
Highways 题目链接: http://acm.hust.edu.cn/vjudge/contest/124434#problem/G Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has a very poor system of public highways. The Flatopian government is aware of this problem an…
题目链接:http://poj.org/problem?id=1751 题意是给你n个点的坐标,然后给你m对点是已经相连的,问你还需要连接哪几对点,使这个图为最小生成树. 这里用kruskal不会超时,用prim应该会超时,特别注意在输入的时候不要多组输入,否则会TLE. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <vec…
Highways Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 23070   Accepted: 6760   Special Judge Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has a very poor system of public highways. The Flatopian…
Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has a very poor system of public highways. The Flatopian government is aware of this problem and has already constructed a number of highways connecting some of the…
题目链接:点击打开链接 Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has a very poor system of public highways. The Flatopian government is aware of this problem and has already constructed a number of highways connecting…
思路: 一开始用Kruskal超时了,因为这是一个稠密图,边的数量最惨可能N^2,改用Prim. Prim是这样的,先选一个点(这里选1)作为集合A的起始元素,然后其他点为集合B的元素,我们要做的就是每次找到B中的一个点,满足这个点到A的权值是B到A的权值中最小的,然后我们把这个点加入到A,再更新B中的点到A的最小距离. 代码: #include<cstdio> #include<cmath> #include<cstring> #include<iostream…
链接: http://poj.org/problem?id=1751 Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 11507   Accepted: 3279   Special Judge Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has a very poor system of publ…
POJ 1258 Agri-Net http://poj.org/problem?id=1258 水题. 题目就是让你求MST,连矩阵都给你了. prim版 #include<cstdio> const int MAXN=101; const int INF=100000+10; int map[MAXN][MAXN]; int dis[MAXN]; int n; void prim() { bool vis[MAXN]={0}; for(int i=0;i<=n;i++) dis[i]…
给出结点的坐标 以及已建好的边 要输出MST中加入的边(已建好的边就不用输出了)结点的编号从1开始注意这题只有一组数据 不能用多组输入 否则就超时(在这被坑惨了Orz) Sample Input 91 50 0 3 24 55 10 45 21 25 331 39 71 2Sample Output 1 63 74 95 78 3 # include <iostream> # include <cstdio> # include <cstring> # include…
某个地方政府想修建一些高速公路使他们每个乡镇都可以相同通达,不过以前已经修建过一些公路,现在要实现所有的联通,所花费的最小代价是多少?(也就是最小的修建长度),输出的是需要修的路,不过如果不需要修建就什么都不输出. 分析:构建一个完全图,使用krusal进行一些简单优化不知道可以不,试一下吧 已经T成狗了 下面是TLE的krusal代码 ****************************************************************************** #…
题目链接:https://vjudge.net/problem/POJ-1751 思路: 最小生成树板子,只需要多记录每个dis[x]的权值是从哪个点到x这个点的. #include <stdio.h> #include <iostream> #include <queue> #include <math.h> #include <algorithm> using namespace std; ; const int inf = (int)1e9…
题目连接 http://poj.org/problem?id=2485 Highways Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has no public highways. So the traffic is difficult in Flatopia. The Flatopian government is aware of this problem. They…
链接: http://poj.org/problem?id=2485 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=22010#problem/H Highways Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 18668   Accepted: 8648 Description The island nation of Flatopia is perfect…
题目链接:Highways 没看题,看了输入输出.就有种似曾相识的感觉,果然和HDU1102 题相似度99%,可是也遇到一坑 cin输入居然TLE,cin的缓存不至于这么狠吧,题目非常水.矩阵已经告诉你了.就敲个模板就是了,5分钟.1A 题意就是打印,最小生成树的最大边权.改了改输入,水过 这个题完了.我的个人POJ计划进度以完毕 20/200,这当中主要是图论的题.等下周把POJ计划图论的题目打完,就回头打模拟!我就不信还能比图论难 #include <iostream> #include…
点击打开链接 Highways Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 19004   Accepted: 8815 Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has no public highways. So the traffic is difficult in Flatopia.…
链接:poj 2485 题意:输入n个城镇相互之间的距离,输出将n个城镇连通费用最小的方案中修的最长的路的长度 这个也是最小生成树的题,仅仅只是要求的不是最小价值,而是最小生成树中的最大权值.仅仅须要加个推断 比較最小生成树每条边的大小即可 kruskal算法 #include<cstdio> #include<algorithm> using namespace std; int f[510],n,m; struct stu { int a,b,c; }t[20100]; int…
题目链接 Description The islandnation of Flatopia is perfectly flat. Unfortunately, Flatopia has no publichighways. So the traffic is difficult in Flatopia. The Flatopian government isaware of this problem. They're planning to build some highways so that…
Highways Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 23033   Accepted: 10612 Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has no public highways. So the traffic is difficult in Flatopia. The Fl…
                                                                                                                Highways Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 23426   Accepted: 10829 Description The island nation of Flatopia is…
Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has no public highways. So the traffic is difficult in Flatopia. The Flatopian government is aware of this problem. They're planning to build some highways so that i…
Description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has no public highways. So the traffic is difficult in Flatopia. The Flatopian government is aware of this problem. They're planning to build some highways so that i…
题意:Bessie要从牧场1到达各大牧场去,他从不关心他要走多远,他只关心他的水袋够不够水,他可以在任意牧场补给水,问他走完各大牧场,最多的一次需要多少带多少单位的水? 思路:其实就是要让所带的水尽量少,即所选的每条路都要尽量短,即最小瓶颈生成树.其实也就是最小生成树.再求生成树上权值最大的边即可. //#include <bits/stdc++.h> #include <cstdio> #include <iostream> #include <algorith…
题目 //听说听木看懂之后,数据很水,我看看能不能水过 #define _CRT_SECURE_NO_WARNINGS #include<stdio.h> #include<string.h> #include<math.h> #include<algorithm> using namespace std; #define M 510 #define inf 999999999 int mat[M][M]; int prim(int n,int sta) {…
对于终于生成的最小生成树中最长边所连接的两点来说 不存在更短的边使得该两点以不论什么方式联通 对于本题来说 最小生成树中的最长边的边长就是使整个图联通的最长边的边长 由此可知仅仅要对给出城市所抽象出的图做一次最小生成树 去树上的最长边就可以 #include<bits/stdc++.h> using namespace std; int T,n,a,dist[1020],m[1020][1020]; void prim() { bool p[1020]; for(int i=2;i<=n…
KUANGBIN带你飞 全专题整理 https://www.cnblogs.com/slzk/articles/7402292.html 专题一 简单搜索 POJ 1321 棋盘问题    //2019.3.18 POJ 2251 Dungeon Master POJ 3278 Catch That Cow  //4.8 POJ 3279 Fliptile POJ 1426 Find The Multiple  //4.8 POJ 3126 Prime Path POJ 3087 Shuffle…
整套题都没什么难度. POJ 1251 Jungle Roads #include <map> #include <set> #include <list> #include <cmath> #include <ctime> #include <deque> #include <stack> #include <queue> #include <cctype> #include <cstdio…
[kuangbin带你飞]专题1-23 专题一 简单搜索 POJ 1321 棋盘问题POJ 2251 Dungeon MasterPOJ 3278 Catch That CowPOJ 3279 FliptilePOJ 1426 Find The MultiplePOJ 3126 Prime PathPOJ 3087 Shuffle'm UpPOJ 3414 PotsFZU 2150 Fire GameUVA 11624 Fire!POJ 3984 迷宫问题HDU 1241 Oil Deposit…
专题一 简单搜索 POJ 1321 棋盘问题POJ 2251 Dungeon MasterPOJ 3278 Catch That CowPOJ 3279 FliptilePOJ 1426 Find The MultiplePOJ 3126 Prime PathPOJ 3087 Shuffle'm UpPOJ 3414 PotsFZU 2150 Fire GameUVA 11624 Fire!POJ 3984 迷宫问题HDU 1241 Oil DepositsHDU 1495 非常可乐HDU 26…