题目大意:给定一个长度为 N 的数组,以及 M 个区间,给出的区间有两个性质,性质一是给定区间中的元素单调不减,性质二是给定区间中的元素存在相邻单调减的元素对,求构造一个符合给定区间条件的序列,若不存在,则输出 NO. 题解:没有从差分的角度进行考虑,WA 到吐血... 区间增减性的问题应该从差分角度进行考虑.对于 [l,r] 中元素单调不减时,对应的差分数组 [l+1,r] 应该每一项均大于等于 0:对于 [l,r] 中元素存在单调减的相邻数对时,对应的差分数组应该至少存在一项使得 d[i]…

[02][].slice和Array.prototype.slice 01,Array是一个构造函数.浏览器内置的特殊对象.   02,Array没有slice方法. 03,Array.prototype原型上有方法slice() 我们可以用Array.prototype.slice或者Array的实例[].slice都行,但不能Array.slice     04, Array.prototype.slice.call(arguments) 可以将类数组对象转成数组. 如: var a={le…

[LeetCode]659. Split Array into Consecutive Subsequences 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/split-array-into-consecutive-subsequences/description/ 题目描述: You are g…

Vasya is studying in the last class of school and soon he will take exams. He decided to study polynomials. Polynomial is a function P(x) = a0 + a1x1 + ... + anxn. Numbers ai are called coefficients of a polynomial, non-negative integer n is called a…

题目描述: 给定一个长度为n的整数数组Array[],输出一个等长的数组result[],这个输出数组,对应位置i是除了Array[i]之外,其他的所有元素的乘积 例如: given [1,2,3,4], return [24,12,8,6]. 要求: 时间复杂度是o(n) 原文描述: Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the…

题目如下: 解题思路:本题和[leetcode]75. Sort Colors类似,但是没有要求在输入数组本身修改,所以难度降低了.引入一个新的数组,然后遍历输入数组,如果数组元素是是偶数,插入到新数组头部,否则追加到尾部. 代码如下: class Solution(object): def sortArrayByParity(self, A): """ :type A: List[int] :rtype: List[int] """ res =…

题目描述 Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B…

Java集合类主要分为以下三类: 第一类:Array.Arrays第二类:Collection :List.Set第三类:Map :HashMap.HashTable 一.Array , Arrays Java所有"存储及随机访问一连串对象"的做法,array是最有效率的一种. 1.效率高,但容量固定且无法动态改变.array还有一个缺点是,无法判断其中实际存有多少元素,length只是告诉我们array的容量. 2.Java中有一个Arrays类,专门用来操作array .array…

C. Sasha and Array time limit per test:5 seconds memory limit per test:256 megabytes input:standard input output: standard output Sasha has an array of integers a1, a2, ..., an. You have to perform m queries. There might be queries of two types: 1 l…

Product of Array Except Self Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2…

Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST.   每次把中间元素当成根节点,递归即可   /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * Tre…

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 有序数组变二叉平衡搜索树,不难,递归就行.每次先序建立根节点(取最中间的数),然后用子区间划分左右子树. 一次就AC了 注意:new 结构体的时候对于 struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int x)…

Product of Array Except Self Total Accepted: 26470 Total Submissions: 66930 Difficulty: Medium Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of numsexcept nums[i…

1. array   同一类型数据的集合     var arr [n]type    //声明type类型一维数组     var arr [m][n]type //声明type类型二维数组     多维数组以此类推     也可以用 := 声明     arr := [n]type{元素1[,元素2, ...]} 其中n可以用 "..." 三个点表示,系统会根据元素个数来确定   下标只能为 int 类型,而 php 还支持 string 类型的下标   1.1 数组长度 len(…

Given an array where elements are sorted in ascending order, convert it to a height balanced BST.思路:对于树来说,自顶向下的递归是很好控制的,自底向上的递归就很容易让脑神经打结了.本来想仿照排序二叉树的中序遍历,逆向地由数组构造树,后来发现这样做需要先确定树的结构,不然会一直递归下去,不知道左树何时停止.代码: TreeNode *addNode(vector<int> &num, int…

Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space to hold additional elements from B. The number of elements initialized in A and B are m and n respectively. 思路: 归并的一部分,比Merge Tw…

Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note:Try to come up as many solutions as you can, there are at least 3 different ways to solve this pro…

题目: Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space to hold additional elements from B. The number of elements initialized in A and B are m and n respectively. 题意要把两个有序的数组合并到他们…

一. 现象 var name = new Array(); typeof(name)      // 为string 类型 var name = new Array('a' , 'b' , 'c'); typeof(name)     // 为string 类型 name.length      // 长度为3 , 理解为字符串 function test () { var name = new Array('a' , 'b' , 'c'); console.log(typeof(name) ,…

题目标签:Array 题目给了我们一个数组 和 k. 让我们 旋转数组 k 次. 方法一: 这里有一个很巧妙的方法: 利用数组的length - k 把数组 分为两半: reverse 左边和右边的数组: reverse 总数组. 举一个例子: 1 2 3 4 5 6 7 如果k = 3 的话, 会变成 5 6 7 1 2 3 4 1 2 3 4 5 6 7 middle = 7 - 3 = 4,分为左边 4个数字,右边 3个数字 4 3 2 1 7 6 5 分别把左右reverse 一下 5…

原文:http://blog.csdn.net/ma_jiang/article/details/52672762 最劲项目需要用到js数组去重和交集的一些运算,我的数组元素个数可能到达1000以上,网上的实现方式都是2次循环,性能不适合我的需求,1000*1000那次数太多了,所以我这里采用对象object来做处理,用空间换时间,code 如下: ///集合取交集 Array.intersect = function () { var result = new Array(); var obj…

题目: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 思路: 找到数组的中间数据作为根节点,小于中间数据的数组来构造作为左子树,大于中间数据的数组来构造右子树. /** * Definition for a binary tree node. * function TreeNode(val) { * this.val = val; * this.l…

题目: iven an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2,3,4], return [24,12,8,6].…

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 解题思路: 用一个有序数组,创建一个平衡二叉查找树. 为确保平衡,需要满足两子树的高度差不大于1,可以通过设置左子树结点数等于或者比右子树结点数多1,来实现. 那么每次取数组的中间位置后一个值,作为根结点,数组左边元素的插入左子树,数组右边元素插入右子树,依次类推. 代码: /** * Definiti…

Given two sorted integer arrays A and B, merge B into A as one sorted array. Note:You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are ma…

Watson gives an array A1,A2...AN to Sherlock. Then he asks him to find if there exists an element in the array, such that, the sum of elements on its left is equal to the sum of elements on its right. If there are no elements to left/right, then sum…

题意: 给出一个长度为n的字符串,只有字符'a'和'b'.最多能改变k个字符,即把'a'变成'b'或把'b'变成'a'. 问改变后的最长连续相同字符的字串长度为多少. 首先是二分查找,好想也好写 ..]of longint; ch:ansistring; n,k,i,l,r,mid,last,ans:longint; function max(x,y:longint):longint; begin if x>y then exit(x); exit(y); end; begin //assign…

参考了这篇文章: https://my.oschina.net/u/1034176/blog/512314 1. 在Scala 2.7中,Array.List都不能混合类型,只有Tuple可以:而在Scala以上版本中,3者的元素都可以混合不同的类型(转化为Any类型),只不过是当使用混合类型时,Array和List会将元素类型转化为Any类型,而Tuple则保留每一个元素的初始类型. 2. 可变性 3. 关于初始化 Array 1) val array= new Array[String](3…

problem 896. Monotonic Array solution1: class Solution { public: bool isMonotonic(vector<int>& A) { int inc = true, dec = true; ; i<A.size(); ++i) { inc &= (A[i]>=A[i-]); dec &= (A[i]<=A[i-]); } return inc || dec; } }; solution2…

problem 905. Sort Array By Parity solution1: class Solution { public: vector<int> sortArrayByParity(vector<int>& A) { vector<int> even, odd; for(auto a:A) { ==) even.push_back(a); else odd.push_back(a); } even.insert(even.end(), odd.…