原题地址:https://oj.leetcode.com/problems/copy-list-with-random-pointer/ 题意: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 解题思路:这题主要是需要深…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这道链表的深度拷贝题的难点就在于如何处理随机指针的问题,由于每一个节点都有一个随机指针,这个指针可以为空,也可以指向链表的任意一个节点,如果我们在每生成一个新节点给其随机指…

给大家推荐一道leetcode上的面试题,这道题的详细解说在<剑指offer>的P149页有思路解说.假设你手头有这本书.建议翻阅. 题目链接 here A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. RandomLi…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 原题链接:https://oj.leetcode.com/problems/copy-list-with-random-pointer/ 题目:给定一个链表,当中的每一个节…

问题: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list.   结点的定义如下: /** * Definition for singly-linked list with a random pointer. * class…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 随机链表的节点数据结构 struct RandomListNode { int label; RandomListNode *next, *random; RandomLi…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 深度复制: 仅简单的遍历一遍链表时,没法复制random pointer属性.所以有点懵,大神的做法如下,加入个人理解. 思路:对链表进行三次遍历. 第一次遍历复制每一个结…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. /** * Definition for singly-linked list with a random pointer. * class RandomListNode…

/** * Definition for singly-linked list with a random pointer. * struct RandomListNode { * int label; * RandomListNode *next, *random; * RandomListNode(int x) : label(x), next(NULL), random(NULL) {} * }; */ class Solution {//为了可以高速定位某个节点,採用确定性映射的方式,将…

Copy List with Random Pointer 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/copy-list-with-random-pointer/description/ Description A linked list is given such that each node contains an additional random pointer which could point to any node in the…

Copy List with Random Pointer A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 题目意思: 深拷贝一个给定的带random指针的链表,这个random指针可能会指向其他任意一个节点或者是为nu…

题目: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 题解: 如果要copy一个带有random pointer的list,主要的问题就是有可能这个random指向的位置还没有被copy到,所以解决方法都是多次扫描li…

类同:剑指 Offer 题目汇总索引第26题 Copy List with Random Pointer A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 说明:分三步, 1. 每个节点复制其本身并链接在后面. 2, 复制…

133. Clone Graph Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node lab…

LintCode - Copy List with Random Pointer LintCode - Copy List with Random Pointer Web Link Description Code - C Tips Web Link http://www.lintcode.com/en/problem/copy-list-with-random-pointer/ Description A linked list is given such that each node con…

题目: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 代码:Runtime: 215 ms # Definition for singly-linked list with a random pointer. # cl…

作者: 负雪明烛 id: fuxuemingzhu 个人公众号:负雪明烛 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode-cn.com/problems/copy-list-with-random-pointer/ 题目描述 给你一个长度为 n 的链表,每个节点包含一个额外增加的随机指针 random ,该指针可以指向链表中的任何节点或空节点. 构造这个链表的 深拷贝. 深拷贝应该正好由 n 个 全…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这道题的难点在于如何处理随机指针,由于每一个节点都有一个随机指针,这个指针可以为空,也可以指向链表的任意一个节点,如果在生成一个新节点给其随机指针赋值时,都去遍历原链表的话…

Problem link: http://oj.leetcode.com/problems/copy-list-with-random-pointer/ Deepcopy a linked list with random pointer, realy simple problem, solved in three steps using a hash map: Create a new head, duplicating the head (return NULL for case head=…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 解题思路: 我们在Java for LeetCode 133 Clone Graph题中做过图的复制,本题和图的复制十分类似,JAVA实现如下: public Random…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. Example 1: Input: {"$id":"1","next":{"$id":"2&…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 思路: 做过,先复制一遍指针,再复制random位置,再拆分两个链表. #include <iostream> #include <vector> #incl…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. Solution: Uses map to recorde node mapping between old linked list and new linked list…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 和第133题差不多,都是图的复制,区别在于这道题的label有可能是相同的,所以导致了map的key有可能相同,所以需要处理. 两种方法差不多.第二种更简洁. 1.在复制n…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 剑指offer里面的一道题,具体思路看不懂请查阅剑指offer /** * Definition for singly-linked list with a random…

题目: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 提示: 此题有两种方法,一种是按照原链表next的顺序依次创建节点,并处理好新链表的next指针,同时把原节点与新节点的对应关系保存到一个hash_map中,然后第…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 解题思路: 本题要求新建一个链表,使其完全等于输入链表,相当于对输入链表深复制. 题目的难点在于,原链表中有random指针,指向原链表对应的结点.当新链表建立时,需要对新…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这题用map做其实比较简单,但是一开始没想明白越想越乱,最后看了下别人的实现,思路还是很清晰的,代码如下所示: /** * Definition for singly-li…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 思路:第一遍正常复制链表,同一时候用哈希表保存链表中原始节点和新节点的相应关系,第二遍遍历链表的时候,再复制随机域. 这是一种典型的空间换时间的做法,n个节点,须要大小为O…

题目 A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 分析 实现一个链表的深拷贝,返回拷贝后的新链表. 若是普通链表,逐个拷贝原始链表节点并连接即可,只需O(n)的时间复杂度:但是此题特殊的是,每个节点都有一个rando…