题目:http://acm.hdu.edu.cn/showproblem.php?pid=1026 Problem Description The Princess has been abducted by the BEelzebub feng5166, our hero Ignatius has to rescue our pretty Princess. Now he gets into feng5166's castle. The castle is a large labyrinth.…

Ignatius and the Princess I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 15576    Accepted Submission(s): 4937 Special Judge Problem Description The Princess has been abducted by the BEelzeb…

Ignatius and the Princess I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12124    Accepted Submission(s): 3824Special Judge Problem Description The Princess has been abducted by the BEelzebub…

Ignatius and the Princess I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 13911    Accepted Submission(s): 4370 Special Judge Problem Description The Princess has been abducted by the BEelzeb…

Problem Description The Princess has been abducted by the BEelzebub feng5166, our hero Ignatius has to rescue our pretty Princess. Now he gets into feng5166's castle. The castle is a large labyrinth. To make the problem simply, we assume the labyrint…

POJ.3894 迷宫问题 (BFS+记录路径) 题意分析 定义一个二维数组: int maze[5][5] = { 0, 1, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 1, 0, }; 它表示一个迷宫,其中的1表示墙壁,0表示可以走的路,只能横着走或竖着走,不能斜着走,要求编程序找出从左上角到右下角的最短路线. 一个5 × 5的二维数组,表示一个迷宫.数据保证有唯一解. 简单的BFS,路径记录开一个二维数组就…

A. Shortest path of the king time limit per test 1 second memory limit per test 64 megabytes input standard input output standard output The king is left alone on the chessboard. In spite of this loneliness, he doesn't lose heart, because he has busi…

Ignatius and the Princess I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 11710    Accepted Submission(s): 3661 Special Judge Problem Description The Princess has been abducted by the BEelzeb…

  此题需要时间更少,控制时间很要,这个题目要多多看, Ignatius and the Princess I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 9910    Accepted Submission(s): 2959 Special Judge Problem Description The Princess has b…

以前写的题了,现在想整理一下,就挂出来了. 题意比较明确,给一张n*m的地图,从左上角(0, 0)走到右下角(n-1, m-1). 'X'为墙,'.'为路,数字为怪物.墙不能走,路花1s经过,怪物需要花费1s+数字大小的时间. 比较麻烦的是需要记录路径.还要记录是在走路还是在打怪. 因为求最短路,所以可以使用bfs. 因为进过每一个点花费时间不同,所以可以使用优先队列. 因为需要记录路径,所以需要开一个数组,来记录经过节点的父节点.当然,记录方法不止一种. 上代码—— #include <cst…

传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1026 Ignatius and the Princess I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 21841    Accepted Submission(s): 7023Special Judge Problem Descrip…

http://acm.hdu.edu.cn/showproblem.php?pid=1026 题意:给出一个迷宫,求出到终点的最短时间路径. 这道题目在迷宫上有怪物,不同HP的怪物会损耗不同的时间,这个时候可以用优先队列,每次让时间最短的出队列.由于最后还需要输出路径,所以需要设置一个数组来保存路径. #include<iostream> #include<queue> #include<cstring> using namespace std; + ; struct…

Ignatius and the Princess I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 10312    Accepted Submission(s): 3125 Special Judge Problem Description The Princess has been abducted by the BEelzeb…

Description You are given two pots, having the volume of A and B liters respectively. The following operations can be performed: FILL(i)        fill the pot i (1 ≤ i ≤ 2) from the tap; DROP(i)      empty the pot i to the drain; POUR(i,j)    pour from…

题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=105278#problem/K K - 迷宫问题 Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Description 定义一个二维数组: int maze[5][5] = { 0, 1, 0, 0, 0, 0, 1, 0, 1, 0, 0,…

//yy:昨天看着这题突然有点懵,不知道怎么记录路径,然后交给房教了,,,然后默默去写另一个bfs,想清楚思路后花了半小时写了120+行的代码然后出现奇葩的CE,看完FAQ改了之后又WA了.然后第一次用对拍去找特殊数据折腾到十二点半终于AC,最后只想感叹没有仔细读题,没办法啊看着英语略烦躁,不扯了,那个题题解不想写了,回到这题...今天中午还是花了四十分钟写了这题(好慢啊orz),感觉,啊为什么别人可以一下子就写出来,我却想不到怎么写呢!!! poj 3414 Pots  [BFS] 题意:两个…

路线冲突问题 题目描述 给出一张地图,地图上有n个点,任意两点之间有且仅有一条路.点的编号从1到n. 现在兵团A要从s1到e1,兵团B要从s2到e2,问两条路线是否会有交点,若有则输出交点个数,否出输出”success”. 输入 多组输入. 对于每组输入. 第一行输入n(1 <= n <= 100000),代表点的个数. 接下来的n-1行,每行包含两个整数u,v(1 <= u,v <= n),代表u,v之间有一条相连. 再接下里的一行包含四个整数s1,e1,s2,e2(1 <…

传送门 转:http://blog.csdn.net/wangjian8006/article/details/7460523 (比较好的记录路径方案) #include<iostream> #include<cstring> #include<cstdlib> #include<cstdio> #include<algorithm> #include<cmath> #include<queue> #include<…

定义一个二维数组: int maze[5][5] = { 0, 1, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 1, 0, }; 它表示一个迷宫,其中的1表示墙壁,0表示可以走的路,只能横着走或竖着走,不能斜着走,要求编程序找出从左上角到右下角的最短路线. Input 一个5 × 5的二维数组,表示一个迷宫.数据保证有唯一解. Output 左上角到右下角的最短路径,格式如样例所示. Sample Input 0…

http://acm.hdu.edu.cn/showproblem.php? pid=1226 为了节省空间.您可以使用vis初始化数组初始化-1. 发现BFSeasy错了地方 始一直WA在这里:就是我int tp=q.front();之后立即q.pop():了,然后才去推断是不是符合条件以break,这样就不能依据q.empty()==1觉得没有找到ans 由于这里WA了 事实上也能够vis[0] == -1来推断 比較不理解的是 当n==0的时候 %n==0的时候怎么处理 //#pragma…

Problem Description The Princess has been abducted by the BEelzebub feng5166, our hero Ignatius has to rescue our pretty Princess. Now he gets into feng5166's castle. The castle is a large labyrinth. To make the problem simply, we assume the labyrint…

解题思路:打印路径是关键,细节处理见代码. #include<cstdio> #include<cstring> #include<algorithm> using namespace std; ; char mapp[maxn][maxn]; ][]; //队列,刚开始没有乘以4,结果RE了 //dp[i][j]表示走到坐标(i,j)时所用的时间 //pre[x][y]存储当前点的前一个点在队列中的位置 int pre[maxn][maxn], dp[maxn][ma…

定义一个二维数组: int maze[5][5] = { 0, 1, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 1, 0, }; 它表示一个迷宫,其中的1表示墙壁,0表示可以走的路,只能横着走或竖着走,不能斜着走,要求编程序找出从左上角到右下角的最短路线. Input 一个5 × 5的二维数组,表示一个迷宫.数据保证有唯一解. Output 左上角到右下角的最短路径,格式如样例所示. Sample Input 0…

Pots Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 10149   Accepted: 4275   Special Judge Description You are given two pots, having the volume of A and B liters respectively. The following operations can be performed: FILL(i)        f…

题意:在01矩阵中,找到一条从入口到终点的最短路径,并且打印这条路径. 题目链接:http://lx.lanqiao.cn/problem.page?gpid=T291 #include<iostream> #include<queue> #include<cstring> using namespace std; ][]; ][]; int n,m; struct node{ int x; int y; int dis; //到达这个点的距离 }; queue<…

题意:从0,0点出发到n-1,m-1点,路上的数字代表要在这个点额外待多少秒,求最短的路 递归输出路径即可 #include<cstdio> #include<iostream> #include<algorithm> #include<cstring> #include<cmath> #include<queue> #include<map> using namespace std; #define MOD 100000…

http://poj.org/problem?id=2935 Basic Wall Maze Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 3220   Accepted: 1457   Special Judge Description In this problem you have to solve a very simple maze consisting of: a 6 by 6 grid of unit sq…

DFS记录路径的意义好像不大,因为不一定是最短的,但是实现起来却很简单. #include<math.h> #include<stdio.h> #include<queue> #include<string.h> #include<iostream> #include<algorithm> using namespace std; #define N 1234 int n,m,step; ,,,-}; ,-,,}; char mat[…

Ignatius and the Princess I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10541    Accepted Submission(s): 3205Special Judge Problem Description The Princess has been abducted by the BEelzebub…

链接: http://acm.hdu.edu.cn/showproblem.php?pid=1026 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=29096#problem/D Ignatius and the Princess I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(…