Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 思路:二进制加法,比較简单.代码例如以下: public class Solution { public String addBinary(String a, String b) { int len = Math.max(a.l…
题意:两个二进制数相加,大数加法的变形 大数加法流程: 1.倒置两个大数,这一步能使所有大数对齐 2.逐位相加,同时进位 3.倒置两个大数的和作为输出 class Solution { public: string addBinary(string a, string b) { if(a.size() < b.size()){ string t = a; a = b; b = t; } //该步使的能大数加小数,使其能加 reverse(a.begin(),a.end()); reverse(b…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 简单的二进制高精度加法. class Solution { public: string addBinary(string a, string b) { string ans=""; ,i=a.length()-,…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&qu…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 题目标签:Math 题目给了我们两个string a 和 b,让我们把这两个二进制 相加. 首先把两个string 的长度得到,然后从右向左 取 两个string 的 digit. 增设一个 carry = 0: 每一轮把 digit…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 这个题目只要注意各种情况你就成功了一大半,特别要注意的是对进位赋值后可能产生的变化,以及最后一位进位为1时, 我们要把这个1插进来.同时注意字符串的低位是我们数值的高位 class Solution { public: string…
题目描述: Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 解题思路: 使用StringBuilder,且使用进位. 代码如下: public class Solution { public String addBinary(String a, String b) { String…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…
翻译 给定两个二进制字符串,返回它们的和(也是二进制字符串). 比如, a = "11" b = "1" 返回 "100". 原文 Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 分析 我一開始写了这个算法,尽管实现…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…
原题链接 思路: 用一个数保存进制,从后往前不断pop出两个数字和进制数相加,放入返回值中. var addBinary = function(a, b) { var arrA = a.split(''); var arrB = b.split(''); var len = Math.max(a.length, b.length), c = 0, result = ''; while(len-- > 0 || c > 0) { let va = arrA.pop(); let vb = arr…
这些题目是高精度加法和高精度乘法相关的,复习了一下就做了,没想到难住自己的是C++里面string的用法. 原题地址: 415 Add Strings:https://leetcode.com/problems/add-strings/description/ 67 Add Binary: https://leetcode.com/problems/add-binary/description/ 43 Multiply Strings:https://leetcode.com/problems/…
67. Add Binary Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". public class Solution { public String addBinary(String a, String b) { String res =""; int l1…
1.题目 67. Add Binary——easy Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1"Output: "100"Example 2:…
1 题目 Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 接口 String addBinary(String a, String b) 2 思路 处理二进制求和和进位.从低位开始,一直相加并且维护进位.和Add Two Numbers的区别是这个题目低位在后面,所以要从strin…
Given a non-negative number represented as an array of digits, plus one to the number. The digits are stored such that the most significant digit is at the head of the list. 题解:简单的高精度加法,要注意[9]这种输入,要多一位. class Solution { public: vector<int> plusOne(v…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 BigInteger类 模拟加法 日期 题目地址:https://leetcode.com/problems/add-binary/description/ 题目描述 Given two binary strings, return their sum (also a binary string). The input strings are bot…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". (二)解题 题意很简单,实现二进制加法逻辑…
Given two binary strings, return their sum (also a binary string).The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&qu…
Given two binary strings, return their sum (also a binary string). For example,a ="11"b ="1"Return"100". 题意:将两个以字符串形式保存的二进制数进行相加. 思路:其实不管是以数组.字符串形式,加或者乘(multiply strings),一般的思路都是从后往前计算,用一个中间变量保存相加或者相乘的结果(加法是一个变量int 或string就行,…
二进制加法 https://discuss.leetcode.com/topic/33693/another-simple-java public String addBinary(String a, String b) { if(a==null||b==null){ return a==null?b:a; //如果其中一个为null,则返回另一个:结合着if条件语句可以包括两个都是null的情形 } int alen = a.length()-1; int blen = b.length()-…
题目: Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 提示: 此题我的第一反应是把输入的两个字符串转化为数字,相加以后再把结果转化为二进制输出,但是测试用例中会有很大的输入,此时即使是long long型也会造成溢出,所以只能用最传统的由低位到高位逐位相加的方法去做. 代码: c…
class Solution(object):    def addBinary(self, a, b):        """        :type a: str        :type b: str        :rtype: str        """        resA=int(a,base=2)        resB=int(b,base=2)                sumAB=bin(resA+resB)   …
问题描述 问题分析 分析题意,此题实际是求解两个二进制数的和,但是有两点要注意: 1.字符串的长度不限,所以相应十进制数值很可能会超过int的上限. 2.二进制的加法规则是自右向左进位,需要注意,以题目示例为例: 11 +  1 ------ 100 所以直接将二进制字符串转成十进制值相加求和,再将十进制和转为二进制字符串的做法是不被接受的,虽然其复杂度只有O(1),错误做法如下: public class Solution { public string AddBinary(string a,…
题目简述: Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 解题思路: class Solution: # @param a, a string # @param b, a string # @return a string def addBinary(self, a, b)…
Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 解题思路: JAVA实现如下: static public String addBinary(String a, String b) { if (a.length() < b.length()) { String temp…
题目: Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 思路: 题意:对字符串的二进制数字,计算 把二进制转化为整数,设置变量carry位进位,sum%2,是相应的数字,carry = sum/2 - 代码: public class Solution { public St…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…