[LeetCode] 241. Different Ways to Add Parentheses 添加括号的不同方式

【[LeetCode] 241. Different Ways to Add Parentheses 添加括号的不同方式】的更多相关文章

[LeetCode] 241. Different Ways to Add Parentheses 添加括号的不同方式

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. Example 1: Input: "2-1-1" Output: [0, 2] Explanation: ((2-1)-…

[LeetCode] Different Ways to Add Parentheses 添加括号的不同方式

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, -and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) = 2 Output: …

LN : leetcode 241 Different Ways to Add Parentheses

lc 241 Different Ways to Add Parentheses 241 Different Ways to Add Parentheses Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are…

LeetCode 241. Different Ways to Add Parentheses为运算表达式设计优先级 (C++)

题目: Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. Example 1: Input: "2-1-1" Output: [0, 2] Explanation: ((2…

(medium)LeetCode 241.Different Ways to Add Parentheses

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are+, - and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) = 2 Output: …

leetcode@ [241] Different Ways to Add Parentheses (Divide and Conquer)

https://leetcode.com/problems/different-ways-to-add-parentheses/ Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. E…

[LeetCode#241]Different Ways to Add Parentheses

Problem: Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) =…

leetcode 96. Unique Binary Search Trees 、95. Unique Binary Search Trees II 、241. Different Ways to Add Parentheses

96. Unique Binary Search Trees https://www.cnblogs.com/grandyang/p/4299608.html 3由dp[1]*dp[1].dp[0]*dp[2].dp[2]*dp[0]相加而成从2开始 class Solution { public: int numTrees(int n) { vector<); dp[] = ; dp[] = ; ;i <= n;i++){ ;j < i;j++){ dp[i] += dp[j] *…

241. Different Ways to Add Parentheses

241. Different Ways to Add Parentheses https://leetcode.com/problems/different-ways-to-add-parentheses/ 思路就是:首先找到以运算符为根节点,分别计算左子串和右子串的所有结果的集合,然后依次进行组合计算.参考博客http://www.cnblogs.com/ganganloveu/p/4681439.html. 自己的思路错了,直接用两边只用了一个整数去接收左右子串的计算值!! #include…

【LeetCode】241. Different Ways to Add Parentheses

Different Ways to Add Parentheses Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are+, - and *. Example 1 Input: "2-1-1". ((…

LC 241. Different Ways to Add Parentheses

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. Example 1: Input: "2-1-1" Output: [0, 2] Explanation: ((2-1)-…

【LeetCode】241. Different Ways to Add Parentheses 解题报告（Python & C++）

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录题目描述题目大意解题方法方法一:递归构建所有表达式方法二:分而治之日期题目地址:https://leetcode.com/problems/different-ways-to-add-parentheses/description/ 题目描述 Given a string of numbers and operators, return all possible re…

241. Different Ways to Add Parentheses——本质：DFS

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) = 2 Output:…

[Swift]LeetCode241. 为运算表达式设计优先级 | Different Ways to Add Parentheses

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. Example 1: Input: "2-1-1" Output: [0, 2] Explanation: ((2-1)-…

Leetcode241.Different Ways to Add Parentheses为运算表达式设计优先级

给定一个含有数字和运算符的字符串,为表达式添加括号,改变其运算优先级以求出不同的结果.你需要给出所有可能的组合的结果.有效的运算符号包含 +, - 以及 * . 示例 1: 输入: "2-1-1" 输出: [0, 2] 解释: ((2-1)-1) = 0 (2-(1-1)) = 2 示例 2: 输入: "2*3-4*5" 输出: [-34, -14, -10, -10, 10] 解释: (2*(3-(4*5))) = -34 ((2*3)-(4*5)) = -14…

Different Ways to Add Parentheses——Leetcode

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +,- and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) = 2 Output: …

LeetCode OJ ： Different Ways to Add Parentheses（在不同位置增加括号的方法）

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are+, - and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) = 2 Output: …

Different Ways to Add Parentheses

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) = 2 Output:…

leetcode--Different Ways to Add Parentheses

题目链接:https://leetcode.com/submissions/detail/86532557/ 算法类型:分治法题目分析:计算表达式的所有结果可能性代码实现: class Solution(object): def diffWaysToCompute(self, input): """ :type input: str :rtype: List[int] """ def dfs(s, cache) : ops = {'+':la…

LeetCode241——Different Ways to Add Parentheses

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are+, - and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) = 2 Output: …

算法8-----Different Ways to Add Parentheses（不同括号结果）

题目: Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) = 2 Out…

【LeetCode】【动态规划】Generate Parentheses（括号匹配问题）

描述 Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ]…

[LeetCode] 20. Valid Parentheses 合法括号

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. An input string is valid if: Open brackets must be closed by the same type of brackets. Open brackets must be closed in the correct…

[LeetCode] Generate Parentheses 生成括号

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()()" 在LeetCo…

[LeetCode] Valid Parentheses 验证括号

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]"…

[LeetCode] 22. Generate Parentheses 生成括号

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] …

[LeetCode] 20. Valid Parentheses 验证括号

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. An input string is valid if: Open brackets must be closed by the same type of brackets. Open brackets must be closed in the correct…

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