题目:http://poj.org/problem?id=2049 题意: 有一个迷宫,在迷宫中有墙与门 有m道墙,每一道墙表示为(x,y,d,t)x,y表示墙的起始坐标d为0即向右t个单位,都是墙d为1即向上t个单位,都是墙有n道门,每一道门表示为(x,y,d)x,y表示门的起始坐标d为0即向右一个单位表示门d为1即向上一个单位表示门再给出你起点的位置(f1,f2),并保证这个点的位置不会再墙或者门中,为起点到(0,0)最少要穿过多少条门 代码是根据网上大神的稍微改了一下,就交了 #inclu…

版权声明:本文为博主原创文章,未经博主同意不得转载. https://blog.csdn.net/u013497151/article/details/29562915 海底总动员.... 这个题開始不会建图,彻底颠覆曾经我对广搜题的想法.想了好久. 忽然想到省赛时HYPO让我做三维BFS来着,一直没做,看到POJ计划这个题.就是三维BFS解题,就做了一下, 对于这个题.. . . 实在不知道说什么好,又坑.又SB,POJ的后台数据和题目描写叙述的全然不一样,看了DIscuss之后開始 修改代码…

Finding Nemo Time Limit: 2000MS   Memory Limit: 30000K Total Submissions: 6952   Accepted: 1584 Description Nemo is a naughty boy. One day he went into the deep sea all by himself. Unfortunately, he became lost and couldn't find his way home. Therefo…

Finding Nemo Time Limit: 2000MS   Memory Limit: 30000K Total Submissions: 8631   Accepted: 2019 Description Nemo is a naughty boy. One day he went into the deep sea all by himself. Unfortunately, he became lost and couldn't find his way home. Therefo…

Time Limit: 2000MS   Memory Limit: 30000K Total Submissions: 6988   Accepted: 1600 Description Nemo is a naughty boy. One day he went into the deep sea all by himself. Unfortunately, he became lost and couldn't find his way home. Therefore, he sent a…

题目链接:http://poj.org/problem?id=2312 题目大意:给出一个n*m的矩阵,其中Y是起点,T是终点,B和E可以走,S和R不可以走,要注意的是走B需要2分钟,走E需要一分钟.最后求解Y--->T的最短时间!! 看到这题首先想到广搜来找最短时间,但是这里可以对B和E进行处理,方便计算~ #include <iostream> #include <cstdio> #include <queue> #include <cstring>…

Finding Nemo Time Limit: 2000MS   Memory Limit: 30000K Total Submissions: 8117   Accepted: 1883 Description Nemo is a naughty boy. One day he went into the deep sea all by himself. Unfortunately, he became lost and couldn't find his way home. Therefo…

题目链接:http://poj.org/problem?id=2449 Time Limit: 4000MS Memory Limit: 65536K Description "Good man never makes girls wait or breaks an appointment!" said the mandarin duck father. Softly touching his little ducks' head, he told them a story. &quo…

链接: http://acm.hdu.edu.cn/showproblem.php?pid=1026 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=29096#problem/D Ignatius and the Princess I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(…

POJ 2251 题目大意: 给出一三维空间的地牢,要求求出由字符'S'到字符'E'的最短路径,移动方向可以是上,下,左,右,前,后,六个方向,每移动一次就耗费一分钟,要求输出最快的走出时间.不同L层的地图,相同RC坐标处是相连通的.(.可走,#为墙) 解题思路:从起点开始分别往6个方向进行BFS(即入队),并记录步数,直至队为空.若一直找不到,则困住. /* POJ 2251 Dungeon Master --- 三维BFS(用BFS求最短路) */ #include <cstdio> #i…