Building Permutation CodeForces - 285C Permutation p is an ordered set of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. We'll denote the i-th element of permutation p as pi. We'll call number …
A.Slightly Decreasing Permutations Permutation p is an ordered set of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. We'll denote the i-th element of permutation p as pi. We'll call number n th…
C. The Phone Number time limit per test 1 second memory limit per test 256 megabytes Mrs. Smith is trying to contact her husband, John Smith, but she forgot the secret phone number! The only thing Mrs. Smith remembered was that any permutation of…
Mrs. Smith is trying to contact her husband, John Smith, but she forgot the secret phone number! The only thing Mrs. Smith remembered was that any permutation of nn can be a secret phone number. Only those permutations that minimize secret value migh…
C. The Phone Number time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Mrs. Smith is trying to contact her husband, John Smith, but she forgot the secret phone number! The only thing Mrs. Smit…
CF798E. Mike and code of a permutation 题意: 排列p,编码了一个序列a.对于每个i,找到第一个\(p_j > p_i\)并且未被标记的j,标记这个j并\(a[i]=j\).给出a求一个可行的p,保证有解.\(n \le 500000\) 官方题解很详细 令\(b(i) = a^{-1}(i)\),也就是说\(b_i\)表示i被谁标记了 容易想到把小于关系用边表示然后拓扑排序 将没有的a和b置为n+1 我们从题目中能直接得到两种小于关系:\((i,b_i)\…
F - Permutation 思路:对于当前的值x, 只需要知道x + k, x - k这两个值是否出现在其左右两侧,又因为每个值只有一个, 所以可以转换成,x+k, x-k在到x所在位置的时候是否都出现,或者都不出现,即出现情况相等,我们可以 用线段树维护hash值的方式来判断所有x+k, x-k的出现情况是否都一样. #include<bits/stdc++.h> #define LL long long #define fi first #define se second #defi…
Description Write a program to transform the permutation 1, 2, 3,..., n according to m instructions. Each instruction (a, b) means to take out the subsequence from the a-th to the b-th element, reverse it, then append it to the end. Input There is on…
