1035 Password (20 分) To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) fr…

1035 Password (20 分)   To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero)…

1035 Password(20 分) To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) fro…

1035 Password (20 分)   To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero)…

题目:http://pat.zju.edu.cn/contests/pat-a-practise/1035 分析:简单题.直接搜索,然后替换,不会超时,但是应该有更好的办法. 题目描述: To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since…

PAT (Advanced Level) Practice 1035 Password (20 分) 凌宸1642 题目描述: To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (o…

1035 Password (20 分) To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) fr…

1035. Password (20) 时间限制 400 ms 内存限制 32000 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is…

1035 Password (20 分) To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) fr…

FJ的字符串-简单递归 问题描述FJ在沙盘上写了这样一些字符串: A1 = “A” A2 = “ABA” A3 = “ABACABA” A4 = “ABACABADABACABA” … … 你能找出其中的规律并写所有的数列AN吗? 输入格式仅有一个数:N ≤ 26. 输出格式请输出相应的字符串AN,以一个换行符结束.输出中不得含有多余的空格或换行.回车符. 样例输入3 样例输出ABACABA 代码如下: #include<stdio.h> void act(int i) { if (i) {…

https://pintia.cn/problem-sets/994805342720868352/problems/994805454989803520 To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to di…

To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppercase)…

To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppercase)…

To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppercase)…

注意下单复数 #include<bits/stdc++.h> using namespace std; pair<string,string>pa; int main() { int n; scanf("%d",&n); vector<pair<string,string> >vec; ;i<n;i++){ ],b[]; scanf("%s %s",a,b); bool flag=false; ;b[j]…

简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<vector> using namespace std; int n; struct X { string a; string b; bool f…

题意: 输入一个正整数N(<=1000),接着输入N行数据,每行包括一个ID和一个密码,长度不超过10的字符串,如果有歧义字符就将其修改.输出修改过多少组密码并按输入顺序输出ID和修改后的密码,如果没有修改过就输出There are N accounts and no account is modified.(根据样例如果N==1,are改成is并且accounts不加s) AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bit…

题意:给n个用户名和密码,把密码中的1改为@,0改为%,l改为L,O改为o. 让你输出需要修改密码的用户名个数,以及对应的用户名和密码,按输入的顺序.如果没有用户需要修改,则输出对应的语句,注意单复数... 没啥好说的,就for一遍密码,把需要改的改下,存入到ans中去. #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cm…

problem To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in up…

C. Dasha and Password time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output After overcoming the stairs Dasha came to classes. She needed to write a password to begin her classes. The password i…

题目描述: To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppe…

Python反转字符串的最简单方法是用切片: >>> a=' >>> print a[::-1] 654321 切片介绍:切片操作符中的第一个数(冒号之前)表示切片开始的位置,第二个数(冒号之后)表示切片到哪里结束,第三个数(冒号之后)表示切片间隔数.如果不指定第一个数,Python就从序列首开始.如果没有指定第二个数,则Python会停止在序列尾.注意,返回的序列从开始位置开始 ,刚好在结束位置之前结束.即开始位置是包含在序列切片中的,而结束位置被排斥在切片外. 这样…

Problem Description 每个人的童年都可能梦想过自己成为一个英雄,尤其是喜欢武侠的男生,Yifenfei也不例外. 童年的他常常梦想自己能成为一个绝世英雄,手拿一把灿灿发亮的宝剑,手挽一位长发飘逸的秀丽气质MM ^_^ ,散步于清幽的泉边小道,微风吹过,飘落两片枫叶...... 正由于成天陶醉于这种脱世的意境之中,导致此人老大不小依旧形单影只,每天只能在人潮中孤单上路...... 现在就让我们为这个可怜的人创造一个机会,权当假设yifenfei现在已经捕获一位MM的芳心,但该MM…

文本压缩有很多种方法,这里我们只考虑最简单的一种:把由相同字符组成的一个连续的片段用这个字符和片段中含有这个字符的个数来表示.例如 ccccc 就用 5c 来表示.如果字符没有重复,就原样输出.例如 aba 压缩后仍然是 aba. 解压方法就是反过来,把形如 5c 这样的表示恢复为 ccccc. 本题需要你根据压缩或解压的要求,对给定字符串进行处理.这里我们简单地假设原始字符串是完全由英文字母和空格组成的非空字符串. 输入格式: 输入第一行给出一个字符,如果是 C 就表示下面的字符串需要被压缩:…

题目:http://poj.org/problem?id=1200 最近看了一个关于hash的问题,不是很明白,于是乎就找了些关于这方面的题目,这道题是一道简单的hash 字符串题目,就先从他入手吧. 题目说字串的最大数量不超过16Millions,也就是字串的存储16000000就够了. 查看网上给出的hash映射是把字串映射成为一个NC进制的数字每个字串都是一个数字. #include <stdio.h> #include <iostream> using namespace…

错误的学习编码语言观点:语言语法不用记,多练习就可以了.   应该是死记住,然后加强练习以免忘记.以及在练习中加强理解.试着想“为什么是这样的语法习惯”.PHP提供了8种数据类型.4种是标量型(单值)的:整型.浮点型.字符串和布尔值:两种是复合型(集合)的:数组和对象.两种特殊类型:资源和NULL 静态变量在所有对该函数的调用中是共享的,而非静态变量会在函数结束时被销毁.嵌套声明并没有限制内部定义函数的可见性.除非外部函数被调用,否则内部函数无法被调用. 字符串的定义:字符串可以是任意长度的字符…

1132 Cut Integer(20 分) Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devid…

一:什么是正则表达式 1.定义:正则表达式是一种可以用于模式匹配和替换的规范,一个正则表达式就是由普通的字符(例如字符a到z)以及特殊字符(元字符)组成的文字模式,它 用以描述在查找文字主体时待匹配的一个或多个字符串.正则表达式作为一个模板,将某个字符模式与所搜索的字符串进行匹配. 2.用途: 字符串匹配(字符匹配) 字符串查找 字符串替换 字符串分割 这里---正则表达式中每一种标记符都代表一种特殊作用及意义,在表达式中把它们连起来读就知道它们所表达的意思啦 正则表达式:A.match(B),…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4772 题面: Zhuge Liang's Password Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1404    Accepted Submission(s): 926 Problem Description In the anc…

简单的字符串模式匹配算法,可使用KMP进行优化 /** * @param s1 母串 * @param s2 子串 * @return */ public static int myIndexOf(String str1,String str2) { int pos=-1; int index=0; char [] s1= str1.toCharArray(); char [] s2= str2.toCharArray(); if(str2.length()>str1.length() || s…