[poj1821]Fence 有 N 块木板从左至右排成一行,有 M 个工匠对这些木板进行粉刷,每块木板至多被粉刷一次.第 i 个工匠要么不粉刷,要么粉刷包含木板 Si 的,长度不超过Li 的连续一段木板,每粉刷一块木板可以得到 Pi 的报酬.求如何安排能使工匠们获得的总报酬最多. 1<=N<=16000,1<=M<=100 输入 NK L1 P1 S1 L2 P2 S2 ... LK PK SK 输出 输出包含一个整数,即最大总收入. 样例输入: 8 4 3 2 2 3 2 3…

题意 Language:Default Fence Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 6478 Accepted: 2129 Description A team of k (1 <= K <= 100) workers should paint a fence which contains N (1 <= N <= 16 000) planks numbered from 1 to N from…

Fence Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 6122   Accepted: 1972 Description A team of k (1 <= K <= 100) workers should paint a fence which contains N (1 <= N <= 16 000) planks numbered from 1 to N from left to right. E…

传送门 1 题目描述 A team of $k (1 <= K <= 100) $workers should paint a fence which contains \(N (1 <= N <= 16 000)\) planks numbered from \(1\) to \(N\) from left to right. Each worker \(i (1 <= i <= K)\) should sit in front of the plank \(S_i\…

地址 一排N个木板,M个工匠站在不同位置$S_i$,每个人可以粉刷覆盖他位置的.最长长度为$L_i$木板段,每刷一个有$P_i$报酬.同一木板只刷一次.求最大报酬. 根据每个人的位置dp,设$f[i][j]$为第$i$个人刷前$j$个木板的最大报酬.$j<s[i]$表示不刷. 那就有 $f[i][j]=max\{f[i-1][k]+(j-k)*p[i]\}   $       $   (s[i]≤j<s[i]+L[i] , s[i]-L[i]≤k<j)$ 然后对于每行,相当于j从前面$l…

Poj   Acwing Description 有N块木板等待被M个工匠粉刷,每块木板至多被刷一次.第i个工匠要么不粉刷,要么粉刷包含木块Si的,长度不超过Li的连续的一段木板,每粉刷一块可以得到Pi的报酬.求如何安排能使工匠们获得的总报酬最多. 1<=N<=16000,1<=M<=100 Sol 先把所有工匠按照Si从小到大排序,使我们能够按顺序进行线性Dp. 设$F[i][j]$表示前i个工匠粉刷前j块木板的最大报酬(包含空着不刷的木板).转移分为三种情况: 1.第i个工匠啥…

题意: 由k(1 <= K <= 100)个工人组成的团队应油漆围墙,其中包含N(1 <= N <= 16 000)个从左到右从1到N编号的木板.每个工人i(1 <= i <= K)应该坐在木板Si的前面,并且他只能喷涂一个紧凑的间隔(这意味着该间隔中的木板应该是连续的).此间隔应包含Si木板.同样,工人最多涂li个木板,每涂一块木板他应得到Pi $(1 <= Pi <= 10000).一块木板最多只能由一个工人涂油漆.所有数字Si应该是不同的. 作为团队的…

题意: 一个栅栏一共有n(从1--n)个木板,我们找k个工人去粉刷它,li表示每个人有限制粉刷木板数量,pi表示粉刷一个木板得到的钱,si表示他开始在那个木板前面 如果一个工人要粉刷,那么他必须粉刷si这个木板,而且工人粉刷时必须是连续的木板 题解: dp[i][j]表示有i个人粉刷j块木板所获得的最大利润 dp[i][j]=max(max(dp[i-1][j],dp[i][j-1]),dp[i][k]+(j-k)*p(i)) dp[i-1][j]表示i-1个人粉刷j块木板所获得的最大利润 dp…

算是一个总结吧! 先来一个模板: TYVJ 1305 最大子序和 题目描述 输入一个长度为n的整数序列,从中找出一段不超过M的连续子序列,使得整个序列的和最大. 例如 1,-3,5,1,-2,3 当m=4时,S=5+1-2+3=7当m=2或m=3时,S=5+1=6 输入输出格式 输入格式: 第一行两个数n,m第二行有n个数,要求在n个数找到最大子序和 输出格式:一个数,数出他们的最大子序和 输入输出样例 输入样例#1: 6 4 1 -3 5 1 -2 3 输出样例#1: 7 数据范围:100%满…

Fence Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 4705   Accepted: 1489 Description A team of k (1 <= K <= 100) workers should paint a fence which contains N (1 <= N <= 16 000) planks numbered from 1 to N from left to right. E…

There is a fence with n posts, each post can be painted with one of the k colors. You have to paint all the posts such that no more than two adjacent fence posts have the same color. Return the total number of ways you can paint the fence. Note:n and…

Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 42979   Accepted: 13999 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…

E. Sign on Fence time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output Bizon the Champion has recently finished painting his wood fence. The fence consists of a sequence of n panels of 1 meter w…

http://poj.org/problem?id=3253 Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000) planks of wood, each having some integer length Li (1 ≤ Li ≤ 50,000) units. He…

Codeforces Round #256 (Div. 2) C C. Painting Fence time limit per test 1 second memory limit per test 512 megabytes input standard input output standard output Bizon the Champion isn't just attentive, he also is very hardworking. Bizon the Champion d…

E. Sign on Fence   Bizon the Champion has recently finished painting his wood fence. The fence consists of a sequence of n panels of 1 meter width and of arbitrary height. The i-th panel's height is hi meters. The adjacent planks follow without a gap…

Color the fence 时间限制:1000 ms  |  内存限制:65535 KB 难度:2   描述 Tom has fallen in love with Mary. Now Tom wants to show his love and write a number on the fence opposite to Mary’s house. Tom thinks that the larger the numbers is, the more chance to win Mary…

1.codeforces 349B    Color the Fence 2.链接:http://codeforces.com/problemset/problem/349/B 3.总结: 刷栅栏.1-9每个字母分别要ai升油漆,问最多可画多大的数字. 贪心,也有点考思维. #include<bits/stdc++.h> using namespace std; #define LL long long #define INF 0x3f3f3f3f int main() { ]; while(…

There is a fence with n posts, each post can be painted with one of the k colors.You have to paint all the posts such that no more than two adjacent fence posts have the same color.Return the total number of ways you can paint the fence. Notice n and…

原题链接在这里:https://leetcode.com/problems/paint-fence/ 题目: There is a fence with n posts, each post can be painted with one of the k colors. You have to paint all the posts such that no more than two adjacent fence posts have the same color. Return the t…

RHCS中必须有Fence设备,在设备为知故障发生时,Fence负责让占有浮动资源的设备与集群断开. REDHAT的fence device有两种, 内部fence设备: IBM RSAII卡,HP的iLO卡,Dell的DRAC,还有IPMI的设备: 外部fence 设备: UPS,SAN SWITCH,NETWORK SWITCH等. 对于外部fence 设备,可以做拔电源的测试,因为备机可以接受到fence device返回的信号,备机可以正常接管服务, 对于内部fence 设备,不能做拔电…

题意:求给定图的欧拉回路(每条边只走一次) 若欧拉回路存在,图中只可能有0个or2个奇数度的点. 求解时,若有奇数度的点,则必须从该点开始.否则可以从任一点开始 求解过程:dfs //主程序部分 # circuit is a global array find_euler_circuit circuitpos = find_circuit(node ) --------------------------------------------- # nextnode and visited is…

Fence Repair 问题大意:农夫约翰为了修理栅栏,要将一块很长的木块切割成N块,准备切成的木板的长度为L1,L2...LN,未切割前的木板的长度恰好为切割后木板的长度的总和,每次切断木板的时候,需要的开销为这块木板的长度,例如长度为21的木板需要切成长度为5,8,8的三块木板,长为21的木板切成长为13和8的板时,开销为21,.再将长度为13的板切成长度为5和8的板时,开销是13,于是合计开销是34,然后要你求切割完的最小开销是什么. 乍眼看这一道题好像有很多种切割方案,似乎是很难解决的…

Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 23913   Accepted: 7595 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…

源码下载地址 注:官方地址下载不了,可能不再维护了,此是一个老项目 efence中相关环境变量控制: 302 /* 303 * See if the user wants to allow malloc(0). 304 */ 305 if ( EF_ALLOW_MALLOC_0 == -1 ) { 306 if ( (string = getenv("EF_ALLOW_MALLOC_0")) != 0 ) 307 EF_ALLOW_MALLOC_0 = (atoi(string) !=…

Fence Repair Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 32424 Accepted: 10417 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000) pla…

POJ 3253 Fence Repair(修篱笆) Time Limit: 2000MS   Memory Limit: 65536K [Description] [题目描述] Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000) planks of wood, eac…

P2738 [USACO4.1]篱笆回路Fence Loops 11通过 21提交 题目提供者该用户不存在 标签USACO 难度提高+/省选- 提交  讨论  题解 最新讨论 暂时没有讨论 题目描述 农夫布朗的牧场上的篱笆已经失去控制了.它们分成了1~200英尺长的线段.只有在线段的端点处才能连接两个线段,有时给定的一个端点上会有两个以上的篱笆.结果篱笆形成了一张网分割了布朗的牧场.布朗想将牧场恢复原样,出于这个考虑,他首先得知道牧场上哪一块区域的周长最小. 布朗将他的每段篱笆从1到N进行了标号…

题目: There is a fence with n posts, each post can be painted with one of the k colors. You have to paint all the posts such that no more than two adjacent fence posts have the same color. Return the total number of ways you can paint the fence. Note:n…

题目链接: A. Vanya and Fence time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Vanya and his friends are walking along the fence of height h and they do not want the guard to notice them. In orde…